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Mathematics
WAEC / WASSCE 2003
Number and Numeration
If \(P = \sqrt{QR\left(1+\frac{3t}{R}\right)}\), make R the subject of the formula.
A
\(R = \frac{3Qt}{P^2 - Q}\)
B
\(R = \frac{P^2 – 3t}{Q+1}\)
C
\(R = \frac{P^2 + 3t}{Q - 1}\)
D
\(R = \frac{P^2-3Qt}{Q}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #26601)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Diagram
Solution
From the Venn diagram below, how many elements are in P∩Q?
Attached Figure / Diagram
A
1
B
2
C
4
D
6
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
P \(\cap\) Q = {f, e} = 2
Source: Myschool Past Questions Archive (Record #26602)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Solution
The square root of a number is 2k. What is half of the number
A
\(\sqrt{\frac{k}{2}}\)
B
\(\sqrt{k}\)
C
\(\frac{1}{2}k^2\)
D
2k2
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Let the number be x.
\(\sqrt{x} = 2k \implies x = (2k)^2\)
= \(4k^2\)
\(\frac{1}{2} \times 4k^2 = 2k^2\)
Source: Myschool Past Questions Archive (Record #26604)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Solution
Evaluate Cos 45o Cos 30o - Sin 45o Sin 30o leaving the answer in surd form
A
\(\frac{\sqrt{2}-1}{2}\)
B
\(\frac{\sqrt{3}-\sqrt{2}}{4}\)
C
\(\frac{\sqrt{6}-\sqrt{2}}{2}\)
D
\(\frac{\sqrt{6}-\sqrt{2}}{4}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(cos45^o \times cos30^o - sin45^o \times sin30^o\)
\(\frac{1}{\sqrt{2}}\times \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}}\times \frac{1}{2}\)
\(\frac{\sqrt{3}}{2\sqrt{2}}-\frac{1}{2\sqrt{2}}; = \frac{\sqrt{3}-1}{2\sqrt{2}} = \frac{\sqrt{6}-\sqrt{2}}{4}\)
Source: Myschool Past Questions Archive (Record #26610)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Solution
A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h
A
\(\frac{2}{3}\pi h^2\)
B
\(\frac{1}{12}\pi h^3\)
C
\(\frac{4}{3}\pi h^2\)
D
\(\frac{4}{3}\pi h^3\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Volume of a cone = \(\frac{\pi r^2 h}{3}\)
r = 2h.
V = \(\frac{\pi \times (2h)^2 \times h}{3}\)
= \(\frac{4}{3} \pi h^3\)
Source: Myschool Past Questions Archive (Record #26613)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Which of the following is not a measure of dispersion?
A
Range
B
Mean deviation
C
Mean
D
Standard deviation
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #26616)
Mathematics
NECO SSCE 2003
Number and Numeration
Solution
The ratio of the circumference to the diameter of a circle is approximately equal to
A
2.5
B
3.14
C
4.83
D
6.52
E
7
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
To calculate the circumference of a circle, use the formula C = \pid, where "C" is the circumference, "d" is the diameter, and \pi is 3.14
Or
The ratio of the circumference to the diameter of a circle is the mathematical constant \pi (pi), which is approximately 3.14.
Source: Myschool Past Questions Archive (Record #42190)
Mathematics
NECO SSCE 2003
Number and Numeration
Solution
Two similar cylindrical cans have heights of 7cm and 21cm, if the smaller holds 250g of sugar, how many kg of sugar will the larger one hold?
A
0.75
B
1.5
C
2.25
D
3.5
E
6.75
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
- If two solids are similar, the ratio of their volumes is equal to the cube of the ratio of their corresponding sides.
Given: Heights of cylinder --> 21 : 7 or 3 : 1 = \(\frac{3}{1}\)
= 3 times height enlargement
Volume / Capacity of larger cylinder = 3\(^3\) \(\times\) 250g
= 27 \(\times\) 250g = 6,750 or 6.75kg
Source: Myschool Past Questions Archive (Record #42251)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Solution
The table shows the monthly contributions and expenditure pattern of an employee in 1999.
Item
Percentage
Pension
5
Income Tax
25
Food
40
Transport
10
Rent
12.5
Others
7.5
(a) Draw a pie chart to illustrate the data.
(b) If the employee's gross monthly salary was N10,800.00, calculate (i) the pension contribution of the employee ; (ii) the income tax paid by the employee.
(c) If the pension contribution and income tax were deducted from the gross monthly salary, before payment, calculate the take- home pay of the employee.
medium Difficulty
Verified Correct Answer: Option
Step-by-Step Mathematical Solution
(a)
Items
Percentage(%)
Degree in pie chart
Pension
5
\(\frac{5}{100} \times 360^\circ = 18^\circ\)
Income tax
25
\(\frac{25}{100} \times 360^\circ = 90^\circ\)
Food
40
\(\frac{40}{100} \times 360^\circ = 144^\circ\)
Transport
10
\(\frac{10}{100} \times 360^\circ = 36^\circ\)
Rent
12.5
\(\frac{12.5}{100} \times 360^\circ = 45^\circ\)
Others
7.5
\(\frac{7.5}{100} \times 360^\circ = 27^\circ\)
100
360^\circ
A pie- chart showing the monthly contributions and expenditure pattern of an employee in 1999.
(b)(i) \(360^\circ = N10,800.00\)
\(\text{Pension} - 18^\circ = \frac{18}{360} \times N10,800\)
= \(N540\)
(ii) \(360^\circ = N10,800.00\)
\(\text{Income tax} - 90^\circ = \frac{90}{360} \times N10,800\)
= \(N2700\)
(c) The percentage sum of pension and income tax = (5 + 25)% = 30%
Take home pay = 100% - 30% = 70%
= \(\frac{70}{100} \times N10,800\)
= \(N7560\)
Source: Myschool Past Questions Archive (Record #53300)
Mathematics
WAEC / WASSCE 2003
Number and Numeration
Solution
(a) A = {1, 2, 5, 7} and B = {1, 3, 6, 7} are subsets of the universal set U = {1, 2, 3,...., 10}. Find (i) \(A'\) ; (ii) \((A \cap B)'\) ; (iii) \((A \cup B)'\) ; (iv) the subsets of B each of which has three elements.
(b) Write down the 15th term of the sequence, \(\frac{2}{1 \times 3}, \frac{2}{2 \times 4}, \frac{4}{3 \times 5}, \frac{5}{4 \times 6},...\).
(c) An Arithmetic Progression (A.P) has 3 as its first term and 4 as the common difference, (i) write an expression in its simplest form for the nth term ; (ii) find the least term of the A.P that is greater than 100.
medium Difficulty
Verified Correct Answer: Option
Step-by-Step Mathematical Solution
(a)(i) U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
A = {1, 2, 5, 7}
A' = U - A = {3, 4, 6, 8, 9, 10}
(ii) \(A \cap B = {1, 2, 5, 7} \cap {1, 3, 6, 7} = {1, 7}\)
\((A \cap B)' = {2, 3, 4, 5, 6, 8, 9, 10}\)
(iii) \(A \cup B = {1, 2, 5, 7} \cup {1, 3, 6, 7}\)
= \({1, 2, 3, 5, 6, 7}\)
\((A \cup B)' = {4, 8, 9,10}\)
(iv) {1, 3, 6}, {1, 3, 7}, {1, 6, 7} and {3, 6, 7}.
(b) The nth term of the sequence is given as
\(U_{n} = \frac{n + 1}{n(n + 2)}, n = 1, 2,3\)
For the 15th term,
\(U_{15} = \frac{16}{15 \times 17}\)
(c)(i) \(T_{n} = a + (n - 1)d\)
\(T_{n} = 3 + (n - 1)4 = 3 + 4n - 4\)
= \(4n - 1\)
(ii) \(4n - 1 > 100\)
\(4n > 100 + 1 \implies 4n > 101\)
\(n > 25.25\)
The least term greater than 100 = 26th term.
Source: Myschool Past Questions Archive (Record #53303)
Mathematics
UTME / JAMB 2003
Number and Numeration
Solution
Find the value of p, if the line that passes through (-1, -p) and (-2p, 2) is parallel to the line 2y + 8x - 17 = 0
A
\(\frac{7}{6}\)
B
\(\frac{6}{7}\)
C
\(\frac{-2}{7}\)
D
\(\frac{-6}{7}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
The given line is 2y + 8x - 17 = 0.
Rewrite in slope form: 2y = -8x + 17
y = -4x + \(\frac{17}{2}\)
Slope = −4.
The line through points \((-1, -p)\) and \((-2p, 2)\) must have the same slope (parallel lines).
Slope = \(\frac{2 - (-p)}{-2p - (-1)} = \frac{2 + p}{1 - 2p}\)
\(\frac{2 + p}{1 - 2p} = -4\)
Cross-multiply:
2 + p = -4(1 - 2p)
2 + p = -4 + 8p
2 + 4 = 8p - p
6 = 7p
p = \(\frac{6}{7}\)
Source: Myschool Past Questions Archive (Record #76327)
Mathematics
UTME / JAMB 2002
Number and Numeration
Solution
In a school, 220 students offer Biology or Mathematics or both. 125 offer Biology and 110 mathematics. How many offer Biology but not Mathematics?
A
95
B
80
C
125
D
110
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Hint: Represent the question in a venn diagram, such that
n(B ∩ M) = x
n(B) only = 125-x
n(M) only = 110-x
=> 125-x + 110-x + x = 220
=> x = 15.
n(B) only = 125 - 15 = 110
Source: Myschool Past Questions Archive (Record #2875)
Mathematics
UTME / JAMB 2002
Number and Numeration
Solution
Simplify 52.4 - 5.7 - 3.45 - 1.75
A
41.4
B
41.5
C
42.1
D
42.2
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
52.4 - 5.7 - 3.45 - 1.75
= 52.4 - (5.7 + 3.45 + 1.75)
= 52.4 - 10.90
= 41.5
Source: Myschool Past Questions Archive (Record #2876)
Mathematics
UTME / JAMB 2002
Number and Numeration
Solution
Simplify \((\sqrt{0.7} + \sqrt{70})^{2}\)
A
84.7
B
70.7
C
217.7
D
168.7
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\((\sqrt{0.7} + \sqrt{70})^{2}\)
= \((\sqrt{0.7} + \sqrt{70})(\sqrt{0.7} + \sqrt{70})\)
= \(0.7 + 2\sqrt{0.7 \times 70} + 70\)
= \(0.7 + 14 + 70 \)
= 84.7
Source: Myschool Past Questions Archive (Record #2877)
Mathematics
UTME / JAMB 2002
Number and Numeration
Solution
Evaluate: \(\frac{0.21 \times 0.072 \times 0.00054}{0.006 \times 1.68 \times 0.063}\)
A
0.01286
B
0.01285
C
0.1286
D
0.1285
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{0.21 \times 0.072 \times 0.00054}{0.006 \times 1.68 \times 0.063}\)
= \(\frac{9 \times 10^{-10}}{7 \times 10^{-8}}\)
= \(1.2857 \times 10^{-2}\)
= \(0.012857 \approxeq 0.01286\) (to 4 s.f)
Source: Myschool Past Questions Archive (Record #2878)