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Chemistry
UTME / JAMB 2017
Acids, Bases, and Salts
Solution
The salt formed from a weak acid and a strong base hydrolyzes in water to form
A
A saturated solution
B
an acidic solution
C
a buffer solution
D
an alkaline solution
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
This is a solution formed from the hydrolyses of an alkali in water.
Source: Myschool Past Questions Archive (Record #46530)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
Calculate the amount in moles of silver deposited when 9650C of electricty is passed through a solution of silver salt [= 96500 Cmol-1]
A
0.05
B
10.80
C
10.00
D
0.10
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
m = \(\frac{Mm \times Q}{96500n
}\)
where Q = IT
M = Mm × \(\frac{Q}{96500n}\)
where m = mass
Mm = Molar mass
Q = Quantity of electricity
n = number of change= +1
\(\frac{M}{Mm}\) = mole = \(\frac{mass}{Molarmass}\)
\(\frac{M}{Mm}\) = \(\frac{Q}{96500n}\)
= \(\frac{9650}{96500n}\) × 1
= \(\frac{1}{10}\) = 0.1mol
Source: Myschool Past Questions Archive (Record #46537)
Chemistry
UTME / JAMB 2017
Organic Chemistry
Solution
The reaction of halogens with alkanes in the presence of sunlight is an example of
A
oxidation reaction
B
addition reaction
C
hydrogenation reaction
D
substitution reaction
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Alkanes undergoes substitution reaction and it is an example of halogenation substitution reaction.
Reaction of halogen with alkane in the presence of sunlight (ultraviolet) is termed halogenation. Halogenation is an example of substitution reaction. In addition, alkanes only undergo substitution reaction but not addition reaction.
Source: Myschool Past Questions Archive (Record #46538)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
The enzyme used in the hydrolysis of starch to dextrin and maltose is?
A
lipase
B
amylase
C
invertase
D
zymase
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Starch is hydrolyzed by dilute acids to yield a mixture of dextrin (a shorter chain intermediate product), disaccharides (mainly maltose) and glucose. Further hydrolysis will eventually give glucose. Hydrolysis of starch to dextrin and maltose can also be brought about by the enzyme amylase present in saliva and in malt.
Source: Myschool Past Questions Archive (Record #46539)
Chemistry
UTME / JAMB 2017
Organic Chemistry
Solution
The alkyl group is represented by the general formula
A
CnH2n
B
CnH2n − 2
C
CnH2n + 1
D
CnH2n + 2
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Alkyl group has the general formula CnH2n + 1.
This formed when one hydrogen is removed from the alkane family. It has the general formula CnH2n + 1
Source: Myschool Past Questions Archive (Record #46540)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
The reddish–brown rust on iron roofing sheets consists of
A
Fe3 + (H2O)6
B
FeO.H2O
C
Fe2O3.XH2O
D
Fe3O4.2H22O
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Iron [Fe] reacts with H2 in the presence of oxygen to form a rust.
4Fe + 3O2 → 2 Fe2O2
Fe2O3 + H2O → Fe2O3.H2O
Source: Myschool Past Questions Archive (Record #46546)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
The densities of two gases, X and Y are 0.5gdm-3 and 2.0gdm-3 respectively. What is the rate of diffusion of X relative to Y?
A
0.1
B
0.5
C
2.0
D
4.0
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.
R ∝ \(\frac{1}{\sqrt{Mm}}\) or R ∝ \(\frac{1}{\sqrt{D}}\)
Dx = 0.5gdm-3, Dy = 2gdm-3
R= \(\frac{K}{\sqrt{D}}\)
R\(\sqrt{D}\) = k
R1\(\sqrt{D_1}\) = R1\(\sqrt{D_2}\)
Rx\(\sqrt{D_x}\) = Ry\(\sqrt{D_y}\)
\(\frac{R_x}{R_y}\) = \(\frac{\sqrt{D_y}}{\sqrt{D_x}}\)
= \(\frac{\sqrt{2}}{\sqrt{0.5}}\)
= 2.0
Source: Myschool Past Questions Archive (Record #46547)
Chemistry
UTME / JAMB 2017
Organic Chemistry
Solution
The carbon atoms on ethane are
A
sp2 hybridized
B
sp3 hybridized
C
sp4 hybridized
D
sp hybridized
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Alkane's family are sp3 hybridized
Source: Myschool Past Questions Archive (Record #46551)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
According to Charle's law, the volume of a gas becomes zero at
A
−100°c
B
−273°c
C
−373°c
D
0°c
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Where −273°c = OK
i.e −273°c + 273 = OK
At zero kelvin, the volume of a gas becomes zero.
Source: Myschool Past Questions Archive (Record #46556)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
An oxide XO2 has a vapour density of 32. What is the atomic mass of X?
A
20
B
32
C
14
D
12
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Molecular mass = vapour density X2
Mm of XO2 = x + 16(2) = x + 32
vapour density = 32
∴ x + 32 = 32 × 2
x + 32 = 64
x = 64 - 32
x = 32
∴ the relative molecular mass of X is 32
Relative molecular mass = vapour density × 2
Source: Myschool Past Questions Archive (Record #46558)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
The gas that can be collected by downward displacement of air is
A
chlorine
B
sulphur (IV) oxide
C
carbon (IV) oxide
D
ammonia
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Upward delivery works well for hydrogen and ammonia, which are both less densed than air. Sometimes, they are collected over water.
Source: Myschool Past Questions Archive (Record #46562)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
In the laboratory preparation of trioxonitrate (V) acid the nitrogen(iv) oxide formed as a by-product is removed by
A
further heating
B
adding concentrated H2SO4
C
cooling the acid solution with cold water
D
bubbling air through the acid solution
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Bubbling of air through the acid solution removes deposited oxides of nitrogen.
Nitric acid is prepared in the laboratory by heating a nitrate salt with the concentrated acid.
NaNO3 + H2SO4 → NaHSO4 + HNO3
Vapours of nitric acid are condensed to a brown liquid in a receiver cooled under cold water. "Dissolved oxides of nitrogen" e.g NO2 are removed by redistillation or blowing a current of carbondioxide or dry air through the warm acid
Source: Myschool Past Questions Archive (Record #46565)
Chemistry
UTME / JAMB 2017
Atomic Structure and Periodic Table
Solution
A particle that contains 9 protons, 10 neutrons and 10 electrons is
A
positive ion
B
neutral atom of a metal
C
neutral atom of a non-metal
D
negative ion
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
protons = 9
neutrons = 10
electrons = 10
Electronic configuration = 2, 8
Ground state Electronic configuration=2, 7
It means that the atom has gained an electron thereby making it have a negative ion.
When an atom donates an electron, it becomes positively charged.
When an atom accepts an electron, it becomes negatively charged
Source: Myschool Past Questions Archive (Record #46571)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
Ethene is prepared industrially by
A
Reforming
B
Polymerization
C
Distillation
D
Cracking
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Ethene is produced from cracking which involves breaking up large hydrocarbon molecules into smaller and more useful bits. This is achieved by using high temperatures and pressures without a catalyst.
C15H32 → 2C2H4 + C3H6 + C8H14
......Δheat...ethene........propene.........octane
Source: Myschool Past Questions Archive (Record #46575)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
Calculate the amount in moles of a gas which occupies 10.5 dm3 at 6 atm and 30oC [R = 0.082 atm dm3 K-1 mol-1]
A
2.536
B
1.623
C
4.736
D
0.394
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
For an ideal gas PV = nRT
Amount in moles = n
Volume v = 10.5dm3
Pressure P = 6atm
Temperature T = 30^\circC + 273 = 303k
R, Gas constant = 0.082 atmdm3k-1 mol
Recall from ideal gas equation
pv = nRT
n = \(\frac{RV}{RT}\)
n = \(\frac{6 \times 10.5}{0.082 \times 303}\)
n= 2.536mol
Source: Myschool Past Questions Archive (Record #46587)