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Power(p) = Force(F) x velocity(v) F = \(\frac{\text{power}}{\text{velocity}}\)

No expanded working has been attached for this question yet. The verified answer is Option B.

Differences between Evaporation and Boiling Evaporation Boiling Evaporation is a normal process that occurs when the liquid form changes into the gaseous form; while causing an increase in the pressure or temperature. Boiling is an unnatural process where the liquid gets heated up and vaporized due to continuous heating. Evaporation usually occurs on the heated liquid’s surface. Boiling usually occurs on the entire mass of the heated liquid. The bubbling effect is not visible in evaporation. The bubbling effect is visible during the process of boiling. produces a cooling effect. does not produce a cooling effect. The process of evaporation is slow. The process of boiling is much quicker.

No expanded working has been attached for this question yet. The verified answer is Option B.

The density of liquid Y is less than that of liquid Z.

A scalar quantity has a magnitude only, which means it tells you how much of something there is, but it does not provide any information about direction.e.g temperature. A vector quantity includes both magnitude and direction. This means it tells you how much and also which way something is happening. e.g velocity Therefore, I and III are correct.

Kinetic energy at point of projection = \(\frac{1}{2} mv^2 \times 0.6 \times 20^2\) = 120J or V\(^2\) = U\(^2\) - 2gs S = \(\frac{v^2 - U^2}{-2g}\) = \(\frac{0^2 - 2062}{-2 \times 10}\) = 20cm P.E. = mgs or mgh 0.6 x 10 x 20 = 120J ii) Kinetic energy in reaching ground = Potential energy at highest point = 120J.

A projectile is an object or body launched into the air and allowed to move on its own or moving freely under gravity. Examples are - a shot arrow, a thrown javeline, a fired bullet, a kicked football etc.

a) Surface tension is defined as a force per unit length perpendicular to any line on the surface of the liquid OR Property of a liquid which makes the surface of liquid behave like an elastic skin. (b) Surface tension =\(\frac{F}{2L}\) F = 7.3 x 1\(^{-2}\) x 2 x 0.04 = 5.8 x 10\(^{-3}\)N

(i) Matter is made up of tiny particles, molecules or atoms (ii) Matter occupies space (iii) Matter possesses inertia, mass or weight (iv) Matter exerts pressure.

(i) Elasticity is the ability of a material to regain its original shape or size after deformations. OR after removal of stress force, OR after it has been 1 compressed. (ii) Young's Modulus is the ratio of tensile I or compressive stress to tensile or compressive strain (iii) Force constant = the amount of force that causes a unit extension of an elastic material. OR \(\frac{Force (F)}{ Extension(e)}\) of an elastic material.

(i) Stress = \(\frac{force}{\text{cross sectiona area}}\) = \(\frac{40}{3.142 (1 \times 10^{-3})^2}\) = 12.74 x 10\(^{6}\)Nm\(^{-2}\) (ii) Strain = \(\frac{e}{I}\) = \(\frac{24 \times 10^{-5}}{4}\) = 6.0 x 10\(^{-5}\)

P = mv = 9.1 x 10\(^{31}\) x 4.2 x 10\(^{-7}\) = 9.1 x 4.2 x 10\(^{-24}\) Kgms\(^{-1}\) \(\lambda = \frac{h}{p} = \frac{6.6 \times 10^{-34}}{9.1 \times 4.2 \times 10^{-24}}\) = 1.73 x 10\(^{-11}\)m or \(\lambda = \frac{h}{mv} = \frac{6.6 \times 10^{-34}}{9.1 \times 10^{-31} \times 4.2 \times 10^7}\) = 1.73 x 10\(^{-11}\)

(a)(i) The momentum of a body is the product of its mass and its velocity. (ii) The total momentum of a system before collision equals to the total momentum after collision provided no external force acts. OR In a system of colliding bodies the total momentum is constant provided no external force acts. (b) Mp Up + Mq Uq = Mp Vp + Mq Vq 0.25 Up + 0 = 0.25 x \(\frac{2}{3}\) Up + 0.25 x 2; 0.25 (Up - 2/3 Up) = 0.50; 1/3 Up = \(\frac{0.50}{0.25}\) = 2m/s Up = 2 x 3 = 6m/s (c)(i) Newton's second law of motion states that the time rate of change of linear momentum is directly proportional to the force causing the change and the change takes place in the direction of the force (ii) Let the momentum before collision = mu and momentum after collision = my, change in momentum = my - mu, Change in momentum in unit time = \(\frac{mv - mu}{t}\) From second law: \(\frac{mv - mu}{t}\) = KF \(\frac{m(v - u)}{t}\) = KF If m = 1kg, a = 1ms\(^{-2}\) and F = 1N, K = 1 ma = F (iii) Resultant force on the vehicle = 9600 - 200 = 7400N. But F = ma a = \(\frac{F}{m} = \frac{7400}{3400}\) = 2.18ms\(^{-2}\) or 2.2ms\(^{-2}\)

(a)(i) Conduction and Radiation. (ii) The specific heat capacity of land is less than that of sea. Land Breeze: At night land cools faster than sea, warm air from above the sea rises upward. It's place is taken by cooler air from above the land. Sea Breeze: During the day the land is hotter than the sea. Warm air above land rises, and its place is taken by cooler air from the sea. (b) Increase in length (L\(_2\) - L\(_1\) = L\(_1 \alpha \Delta \theta = 30 \times 1.2 \times 10^{-5} \times 50 = 1.8 \times 10^{-2}\) cm (c) Ivt = mc\(\Delta \theta\) Power x time = mc\(\Delta \theta\) (i) Iv x 360 = m x c 60 ----(i) Ivt = \(\frac{1}{2}\)mL (ii) Ivx 25 x 60 = \(\frac{1}{2}\)mL ------(ii) \(\frac{Iv \times 25 \times 60}{Iv \times 360} = \frac{\frac{1}{2}mL}{mc \times 60}\) L = \(\frac{25 \times 60 \times C \times 60 \times 2}{360}\) = \(\frac{25 \times 60 \times 4200 \times 60 \times 2}{360}\) = 2.1 x 10\(^5\) Jkg\(^{-1}\)