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Chemistry
UTME / JAMB 2017
Atomic Structure and Periodic Table
Solution
The process that occurs when two equivalent forms of a compound are in equilibrium is
A
Isotopy
B
Resonance
C
Isomerism
D
Reforming
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Resonance involves two forms of a compound.
Isomerism involves two or more forms of an element.
Reforming involves the rearrangement of molecule.
This deals with a two forms of a molecule where the chemical connectivity is the same but the electrons are distributed differently around the structure.
Source: Myschool Past Questions Archive (Record #46520)
Chemistry
UTME / JAMB 2017
Matter & Separation Techniques
Solution
In the laboratory preparation of ethyl ethanoate, the water present in the mixture is removed using ?
A
Anhydrous CaCl2
B
concentrated NaCO4
C
dilute NaOH
D
concentrated H2SO4
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
To purify the distillate of impurities like unreacted ethanol, acids, water and ethoxyethane.
Adding anhydrous calcium chloride and leave it to stand for a day to remove any water present
in the mixture.
Source: Myschool Past Questions Archive (Record #46521)
Chemistry
UTME / JAMB 2017
Electrochemistry and Redox
Solution
The constituent of air necessary in the rusting process are
A
O2 and H2O
B
Ar and CO2
C
CO2 and H2O
D
O2 and CO2
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Rust is an iron oxide, a usually red oxide formed by the redox reaction of iron and oxygen in the presence of water or air moisture.
Source: Myschool Past Questions Archive (Record #46522)
Chemistry
UTME / JAMB 2017
Kinetics, Energetics and Equilibrium
Solution
For a general equation of the nature xP + yQ → mR + nS, the expression for the equilibrium constant is
A
k [P]x [Q]y
B
\(\frac{[P]^x [Q]^y}{[R]^m [S]^n}\)
C
\(\frac{[R]^m [S]^n}{[P]^x [Q]^y}\)
D
\(\frac{m[R] n[S]}{x[P] y[Q] }\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Expression for equilibrium constant
k = \(\frac{\text{concentration of product}}{\text{concentration of reactant}}\)
Source: Myschool Past Questions Archive (Record #46523)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
A given mass of gas occupies 2dm3 at 300k. At what temperature will its volume be doubled, keeping the pressure constant?
A
400k
B
480k
C
550k
D
600k
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
At constant pressure connotes Charle's law
\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)
\(\frac{2dm^3}{300k}\) = 2 x \(\frac{2dm^3}{T_2}\)
T2= 600k
Source: Myschool Past Questions Archive (Record #46524)
Chemistry
UTME / JAMB 2017
Electrochemistry and Redox
Solution
The oxidation number of iodine in KIO3 is
A
+7
B
+3
C
+5
D
+6
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
If the rules are followed, it is non-negotiable that +5 is the suitable answer to the question.
Source: Myschool Past Questions Archive (Record #46525)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
The ideal gas laws and equations are true for all gases at
A
low pressures and lower temperatures
B
low temperatures and high pressures
C
high pressures and high temperatures
D
low pressure and high temperatures
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
At high temperature and low pressure, the vanderwaal equation is reduced to ideal gas equation.
i.e, [P + \(\frac{a}{v^2}\)] [v - b] = RT is reduced to PV = nRT
Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure as the potential energy due to intermolecular forces, it becomes less significant compared with the particles kinetic energy and the size of the molecules, then it becomes less significant compared to the empty space between them.
Source: Myschool Past Questions Archive (Record #46531)
Chemistry
UTME / JAMB 2017
Kinetics, Energetics and Equilibrium
Solution
When ΔH is negative, a reaction is said to be
A
endothermic
B
exothermic
C
reversible
D
ionic
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
When ΔH is negative, heat is liberated to the surrounding and it connotes an exothermic reaction.
ΔH = −ve
Source: Myschool Past Questions Archive (Record #46532)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + alpha particle
A
226
B
220
C
227
D
222
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
\(^{226}_{88}Ra\) → \(^x_{86}Rn\) + \(^4_{2}He\)
\(^4_{2}He\) = alpha particle
considering the summation of the mass number
226 = x + 4
x = 226 - 4
x = 222
Source: Myschool Past Questions Archive (Record #46533)
Chemistry
UTME / JAMB 2017
Atomic Structure and Periodic Table
Solution
The shape of ammonia molecules is
A
trigonal pyramidal
B
octahedral
C
square planar
D
tetrahedral
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The ammonia (NH\(_3\)) molecule has a trigonal pyramidal shape, with the three hydrogen atoms and the nitrogen atom forming a pyramid, and a lone pair of electrons on the nitrogen atom.
Trigonal pyramidal and trigonal planar are distinct molecular geometries; trigonal planar has three atoms bonded to a central atom in a flat, triangular arrangement, while trigonal pyramidal has three atoms and one lone pair around the central atom, resulting in a pyramid shape.
Source: Myschool Past Questions Archive (Record #46534)
Chemistry
UTME / JAMB 2017
Stoichiometry & Mole Concept
Solution
The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)
A
54.0g
B
27.0g
C
13.5g
D
108.0g
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Recall that
mass deposited = \(\frac{MmIt}{96500n}\)
Mm =108, t = 4830s
I = 10A, n = 1
m = 108 \times 10 \times (\(\frac{4830}{96500}\)) \times 1
m = 54.0g
Source: Myschool Past Questions Archive (Record #46535)
Chemistry
UTME / JAMB 2017
Acids, Bases, and Salts
Solution
An isomer of C5H12 is
A
2–ethyl butane
B
butane
C
2–methyl butane
D
2–methyl propane
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
C5H12 has 5 carbons acid 12 hydrogens.
2–methyl butane
No of carbon=5
No of hydrogen=12
Source: Myschool Past Questions Archive (Record #46526)
Chemistry
UTME / JAMB 2017
Acids, Bases, and Salts
Solution
When few drops of concentrated trioxonitrate(V) acid is added to an unknown sample and wanned an intense yellow colouration is observed. The likely functional group present in the sample is
A
NH2RCHCOOH
B
CHO
C
CO
D
CNH2
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Xanthopreitic test for the presence of protein, when conc nitric acid is added to the drop, an intense yellow colouration is observed.
It contains all the functional group of protein which includes the amino, alkanol and the carboxylic group. Adding few drops of conc HNO3 to a protein, gives an intense yellow colouration.
It is called Xanthopreitic test.
Source: Myschool Past Questions Archive (Record #46527)
Chemistry
UTME / JAMB 2017
Acids, Bases, and Salts
Solution
A sample of orange juice is found to have a PH of 3.80. What is the concentration of the hydroxide ion in the juice?
A
1.6 \(\times\) 10-4
B
6.3 \(\times\) 10-11
C
6.3 \(\times\) 10-4
D
1.6 \(\times\) 10-11
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
PH = - Log[ H+ ]
PH + POH =14
POH = 14 - 3.8
POH = 10.2
POH = - Log[ OH- ]
10.2 = - Log[ OH- ]
10-10.2 = [ OH- ]
[ OH- ] = 6.3 x 10-11
Source: Myschool Past Questions Archive (Record #46528)
Chemistry
UTME / JAMB 2017
Acids, Bases, and Salts
Solution
Incomplete oxidation of ethanol yields
A
CH3COOH
B
CH3COCH3
C
CH3CH2OCH2CH3
D
CH3CHO
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
C2H5OH → CH3CHO → CH3COOH
Ethanol.....oxidation Ethanal........Ethanoic Acid
Primary alcohol oxidises to aldehyde and later to carboxylic acid.
Secondary alcohol oxidises to ketones.
Ethanol is an example of primary alcohol and primary alcohol can be oxidised to aldehyde and carboxylic acid. Wherein, incomplete oxidation of primary alcohol yields aldehyde also known as alkanal while complete oxidation of primary alcohol yields carboxylic acid.
Source: Myschool Past Questions Archive (Record #46529)