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Mathematics
WAEC / WASSCE 2017
Algebra
Solution
Find the 6th term of the sequence \(\frac{2}{3} \frac{7}{15} \frac{4}{15}\),...
A
-\(\frac{1}{3}\)
B
-\(\frac{1}{5}\)
C
-\(\frac{1}{15}\)
D
\(\frac{1}{9}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
a = \(\frac{2}{3}\), d = \(\frac{7}{15}\) - \(\frac{2}{3}\)
= 7 - 10
= \(\frac{-3}{15}\)
d = - \(\frac{-1}{5}\)
T6 = a + 5d
= \(\frac{2}{3}\) + 5(\(\frac{-1}{5}\)
= \(\frac{2}{3}\) - 1
= \(\frac{2 - 3}{3}\)
= \(\frac{-1}{3}\)
Source: Myschool Past Questions Archive (Record #50121)
Mathematics
WAEC / WASSCE 2017
Algebra
Solution
The roots of a quadratic equation are \(\frac{-1}{2}\) and \(\frac{2}{3}\). Find the equation.
A
\(6x^2 - x + 2 = 0\)
B
\(6x^2 - x - 2 = 0\)
C
\(6x^2 + x - 2 = 0\)
D
\(6x^2 + x + 2 = 0\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
(x + \(\frac{1}{2}\)) (n - \(\frac{2}{3}\))
\(x^2 - \frac{2}{3^x} + \frac{x}{2} - \frac{1}{3}\)
\(6x^2 - 4n + 3n - 2 = 0\)
\(6x^2 - x - 2 = 0\)
Source: Myschool Past Questions Archive (Record #50122)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Consider the statements: p it is hot, q: it is raining
Which of the following symbols correctly represents the statement "It is raining if and only if it it is cold"?
A
p \(\iff\) \(\sim\)q
B
p \(\iff\) q
C
\(\sim\)p \(\iff\) \(\sim\)q
D
q \(\iff\) \(\sim\)p
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #50126)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Solution
Given that t = \(2 ^{-x}\), find \(2 ^{x + 1}\) in terms of t.
A
\(\frac{2}{t}\)
B
\(\frac{t}{2}\)
C
\(\frac{1}{2t}\)
D
t
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
t = \(2^{-x} = \frac{1}{2^{x}}\)
\(\implies 2^{x} =\frac{1}{t}\)
\(2^{x+1} = 2^{x} \times 2^{1}\)
= \(\frac{1}{t} \times 2 = \frac{2}{t}\)
Source: Myschool Past Questions Archive (Record #50130)
Mathematics
WAEC / WASSCE 2017
Statistics and Probability
Solution
Two bottles are drawn with replacement from a crate containing 8 Coke, 12 Fanta, and 4 Sprite bottles. What is the probability that the first is coke and the second is not coke?
A
\(\frac{1}{12}\)
B
\(\frac{1}{6}\)
C
\(\frac{2}{9}\)
D
\(\frac{3}{8}\)
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Total = 8 + 12 + 4
= 24
\(\frac{8}{24} \times (\frac{12}{24} + \frac{4}{24}\))
= \(\frac{1}{3} \times (\frac{1}{2} + \frac{1}{6}\))
= \(\frac{1}{3} \times \frac{3 + 1}{6}\)
\(\frac{1}{3} \times \frac{4}{6} = \frac{2}{9}\)
Source: Myschool Past Questions Archive (Record #50132)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Solution
If the simple interest on a certain amount of money saved in a bank for 5 years at 2\(\frac{1}{2}\)% annum is N500.00, calculate the total amount due after 6 years at the same rate
A
N2,500.00
B
N2,600.00
C
N4,500.00
D
N4,600.00
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
P = \(\frac{100l}{RT} = \frac{100 \times 500}{5 \times 2.5} = \frac{50,000}{12.5}\)
= 4,000
Annual interest is \(\frac{500}{5}\) = 100
for 6 year = 4,000 + 100 + 100 + 100 + 100 + 100 + 100
= N 4,600
Source: Myschool Past Questions Archive (Record #50135)
Mathematics
WAEC / WASSCE 2017
Statistics and Probability
Solution
Calculate the variance of 2, 3, 3, 4, 5, 5, 5, 7, 7 and 9
A
2.2
B
3.4
D
4.0
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
x = \(\frac{2 + 3 + 3 + 4 + 5 + 5+ 5+ 7 + 7 + 9}{10}\)
=\(\frac{50}{10}\)
= 5
Variance = \(\frac{\sum{(x - x})^2}{N}\)
\(\frac{9 + 4+ 4+ 1 + 4 + 4 + 16}{10}\)
= \(\frac{42}{10}\)
= 4.2
Source: Myschool Past Questions Archive (Record #50138)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Solution
A circular pond of radius 4m has a path of width 2.5m round it. Find, correct to two decimal places, the area of the path. [Take\(\frac{22}{7}\)]
A
7.83\(m^2\)
B
32.29\(m^2\)
C
50.29\(m^2\)
D
82.50\(m^2\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Area of path = Area of (pond+path) - Area of pond
The area of the pond with the path: The radius = (4 + 2.5)m = 6.5m
Area = \(\pi \times r^{2}\) = \(\frac{22}{7} \times 6.5^{2} \approxeq 132.79m^{2}\)
Area of the pond = \(\frac{22}{7} \times 4^{2} \approxeq 50.29m^{2}\)
Area of the path = (132.79 - 50.29)m^{2} = 82.50m^{2}\)
Source: Myschool Past Questions Archive (Record #50142)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Diagram
Solution
Fig. 1 and Fig. 2 are the addition and multiplication tables respectively in modulo 5. Use these tables to solve the equation (n \(\oplus 4\))
Attached Figure / Diagram
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
(n \(\oplus\) 4) \(\oplus\) 3 = 0 (mod 5)
(3 \(\oplus\) 4) \(\oplus\) 3
12 \(\oplus\) 3 = 15 (mod 5)
(5 x 3 + 0) = 0 (mod 5)
Source: Myschool Past Questions Archive (Record #50148)
Mathematics
WAEC / WASSCE 2017
Number and Numeration
Diagram
Solution
In the diagram, XY is a straight line.
Attached Figure / Diagram
A
60\(^o\)
B
90\(^o\)
C
100\(^o\)
D
120\(^o\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Source: Myschool Past Questions Archive (Record #50155)
Mathematics
WAEC / WASSCE 2017
Geometry and Trigonometry
Diagram
Solution
The diagram shows a circle O. If < ZYW = 33\(^o\) , find < ZWX
Attached Figure / Diagram
A
33\(^o\)
B
57\(^o\)
C
90\(^o\)
D
100\(^o\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
In
Source: Myschool Past Questions Archive (Record #50157)
Mathematics
WAEC / WASSCE 2017
Geometry and Trigonometry
Diagram
Solution
In the diagram, PQ and PS are tangents to the circle O. If PSQ = m,
Attached Figure / Diagram
A
103\(^o\)
B
123\(^o\)
C
133\(^o\)
D
143\(^o\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
< SQP = 180 - (90 + 33) < on a ----
= 180 - (123)
= 57\(^o\)
Therefore, (m + n) = 123\(^o\)
Source: Myschool Past Questions Archive (Record #50161)
Mathematics
WAEC / WASSCE 2017
Geometry and Trigonometry
Solution
Marks
0
1
2
3
4
5
Frequency
7
4
18
12
8
11
The table gives the distribution of marks obtained by a number of pupils in a class test. Using this information, Find the median of the distribution
A
4
B
3
C
1
D
2
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Median is \(\frac{n}{2} = \frac{6}{2}\)
= 3
Median = 3
Source: Myschool Past Questions Archive (Record #50171)
Mathematics
WAEC / WASSCE 2017
Geometry and Trigonometry
Solution
Marks
0
1
2
3
4
5
Frequency
7
4
18
12
8
11
The table gives the distribution of marks obtained by a number of pupils in a class test. Using this information, find the first quartile
A
1.0
B
1.5
C
2.0
D
2.5
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
First quartile = \(\frac{n}{4} = \frac{60}{4}\) = 15
The 15th value is 2
Source: Myschool Past Questions Archive (Record #50174)
Mathematics
WAEC / WASSCE 2017
Statistics and Probability
Solution
In a class of 45 students, 28 offer chemistry and 25 offer Biology. If each student offers at least one of the two subjects, calculate the probability that a student selected at random from the class the class offers chemistry only.
A
\(\frac{2}{9}\)
B
\(\frac{4}{9}\)
C
\(\frac{5}{9}\)
D
\(\frac{7}{9}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
28 - x + x + 25 - x = 45
53 - x = 45
x = 53 - 45
x = 8
chemistry only = 28 - 8
= 20
Probability = \(\frac{20}{45}\)
= \(\frac{4}{9}\)
Source: Myschool Past Questions Archive (Record #50180)