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Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
The time rate of change of momentum is
A
impulse
B
force
C
power
D
pressure
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The time rate of change of momentum is defined as force.
Source: Myschool Past Questions Archive (Record #33873)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
Which of the following statements about elastic collision is correct?
A
momentum is lost due to the sound produced
B
loss of momentim is equal to loss in kinetic energy
C
both kinetic energy and momentum are conserved
D
kinetic energy is lost while momentum is conserved
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
In an elastic collision, both kinetic energy and momentum are conserved.
Therefore, the correct answer is C. Both kinetic energy and momentum are conserved.
Source: Myschool Past Questions Archive (Record #33874)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
Electrical resistance is a property of an electrical energy to be converted into
A
mechanical energy
B
heat energy
C
magnetic energy
D
chemical energy
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Electrical resistance is a property that causes electrical energy to be converted into heat energy
Therefore, the correct option is B heat energy.
Source: Myschool Past Questions Archive (Record #33875)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
A simple machine with an efficiency of 75% lifts a load of 5000N when a force of 500N is applied to it. Calculate the velocity ratio of the machine
A
10.0
B
13.3
C
17.5
D
25.0
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
M.A = \(\frac{load}{effort} \frac{5000N}{500N} = 10\)
V.R = \(\frac{M.A \times 100}{V} = \frac{10 \times 100}{75} = 13.3\)
Source: Myschool Past Questions Archive (Record #33876)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
A screw jack with a Tommy bar of length 12cm is used to raise a car through a vertical height of 25cm by turning the Tommy bar through 50 revolutions. Calculate the approximate velocity ratio of the jack [\(\pi = 3.142\)]
A
21
B
38
C
48
D
151
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
P = \(\frac{25}{50} = 0.5\)
V.R = \(\frac{2\pi D}{p} = \frac{2 \times 3.142 \times 12}{0.5}\)
= 151
Source: Myschool Past Questions Archive (Record #33880)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
A given mass of an ideal gas has a pressure of 500Nm-2 at -13ºC. If its volume remains constant. Calculate its pressure at 247ºC.
A
25Nm-2
B
50Nm-2
C
500Nm-2
D
1000Nm-2
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(P_2 = \frac{p_1 \times T_2}{T_1} = \frac{500 \times 520}{260}\)
= 1000N\(m^{-2}\)
Source: Myschool Past Questions Archive (Record #33893)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
The volume of an ideal gas at a pressure of 77 cmHg and a temperature of 60 ^\circC is 240 cm\(^3\). If the temperature and pressure are increased to 98oC
and 81cmHg respectively, calculate the new volume of the gas
A
411.5cm3
B
267.1cm3
C
254.2cm3
D
112.7cm3
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
V2 = \(\frac{P_1V_1T_2}{P_2T_1} = \frac{77 \times 240 \times 371}{81 \times 333}\)
= 254.2cm3
Source: Myschool Past Questions Archive (Record #33897)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
Which of the following physical qualities affects the saturated vapour pressure of a liquid ?
A
temperature
B
volume
C
mass
D
density
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The saturated vapor pressure of a liquid is primarily affected by temperature. As the temperature increases, the vapor pressure also increases.
Source: Myschool Past Questions Archive (Record #33901)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
Which of the following statements about magnetic lines of force is not correct?
A
a magnnetic line of force is an imaginary line which the north pole of a magnet would describe if it is free to moves
B
magnetic lines of force do not cross one another
C
magnetic lines of force are closely packed together at neutral point
D
the presence of magnetic lines of force in a region indicates the presence of a magnetic field
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
At a neutral point, the magnetic field is weak or zero, so the magnetic lines of force are not closely packed together. Instead, they are sparse in that region.
Source: Myschool Past Questions Archive (Record #33940)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Diagram
Solution
In the circuit diagram above. Calculate the energy stored in the inductor at resonance
Attached Figure / Diagram
A
0.100J
B
0.050J
C
0.010J
D
0.005J
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
To calculate the energy stored in the inductor at resonance, we can use the formula for the energy stored in an inductor:
Energy stored in an inductor = \(\frac{1}{2}\) x L x I\(^2\) = 0.5 x 0.1 x 1x1 = 0.050J
Source: Myschool Past Questions Archive (Record #33942)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
The magnitude of the gravitational force between two particles 0.10m apart is 10N. If the distance between them is increased to 0.20m, calculate the magnitude of the new force
A
40.0N
B
20.0N
C
5.0N
D
2.5N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(g_1 = \frac{Gm_1m_2}{r^2_1}\)
\(m_1m_2 = \frac{gr^2_1}{G}\)
\(g_2 = \frac{Ggr^2_1}{Gr^2_2} = \frac{10 \times 0.1^2}{0.2^2}\)
= 2.5N
Source: Myschool Past Questions Archive (Record #33933)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Diagram
Solution
What is the total energy stored by the capacitors?
Attached Figure / Diagram
A
2.0 x 10-4J
B
1.0 x 10-4J
C
9.0 x 10-2J
D
1.0 x 10-2J
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2}CV^2 = \frac{1}{2} \times 2 \times 10^{-6} \times 100^2\)
= 1.0 x 10-2J
Source: Myschool Past Questions Archive (Record #33936)
Physics
WAEC / WASSCE 2001
Mechanics and Properties of Matter
Solution
Three identical lamps each power 100W are connected in parallel across a potential difference of 250V. Calculate the current in the circuit
A
7.5A
B
2.5A
C
1.2A
D
0.8A
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
P = IV
I = \(\frac{P}{V} = \frac{3 \times 100}{250} = 1.2A\)
Source: Myschool Past Questions Archive (Record #33937)
Physics
UTME / JAMB 2001
Mechanics and Properties of Matter
Solution
Find the frequencies of the first three harmonics of a piano string of length 1.5m, if the velocity of the wave on the string is 120ms-1
A
40Hz, 80Hz, 120Hz
B
80Hz, 160Hz, 240Hz
C
180Hz, 360Hz, 540Hz
D
369Hz, 180Hz, 90Hz
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
in vibrations in string, the fundamental frequency happens to be the first harmonic, and is given as
f\(_0\) = \(\frac{V}{2l}\)
Where V = Velocity of the sound wave, I = Length of the string.
The second harmonic is the first overtone given by
f1 = \(\frac{V}{l}\) = 2f0 ;
and the third harmonic happens to be the second overtone, given by
f2 = \(\frac{3V}{2l}\) = 2f0.
Thus if V = 120m/s and l = 1.5m
Thus f1 = 2f0 = 2 x 40 = 80Hz
Thus f2 = 3f0 = 3 x 40 = 120Hz
Thus we have in order, 40Hz, 80Hz, 120Hz
Source: Myschool Past Questions Archive (Record #41482)
Physics
UTME / JAMB 2001
Mechanics and Properties of Matter
Solution
A bread toaster uses a current of 4A when plugged in a 240V line. it takes 1 minute to toast slices of bread. what is the energy consumed by the toaster
A
5.76 x 104J
B
1.60 x 104J
C
3.60 x 103J
D
1.60 x 102J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Electrical Energy = IVt
= 4 x 240 x (1 x 60)
= 57600J
= 5.76 x 104J
Source: Myschool Past Questions Archive (Record #41483)