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Chemistry
UTME / JAMB 2018
Stoichiometry & Mole Concept
Solution
Calculate the percentage composition of oxygen in calcium trioxocarbonate(IV) [Ca=40, C=12, O=16]
A
16
B
48
C
40
D
12
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Calcium trioxocarbonate (IV) = CaCO\(_3\)
Percentage of Oxygen = \(\frac{\text{Molar mass of 3O}}{\text{Molar mass of} CaCO_3}\) \times 100%
Percentage of Oxygen = \(\frac{(3 \times 16)}{(40 + 12 + 48)}\) x 100%
Percentage of Oxygen = \(\frac{48}{100}\) x 100%
Percentage of Oxygen = 48%
Source: Myschool Past Questions Archive (Record #47662)
Chemistry
UTME / JAMB 2018
Acids, Bases, and Salts
Solution
Which of these alloys contains copper?
A
solder
B
steel
C
permallory
D
bronze
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Bronze is an alloy consisting primarily of copper, commonly with about 12% tin and often with the addition of other metals (such as aluminium, manganese, nickel or zinc) and sometimes non-metals or metalloids such as arsenic, phosphorus or silicon.
Source: Myschool Past Questions Archive (Record #47663)
Chemistry
UTME / JAMB 2018
Stoichiometry & Mole Concept
Solution
If the molecular mass of tetraoxosulphate (VI) acid is 98, calculate its vapour density.
A
196
B
49
C
106
D
82
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Molecular mass = Vapour Density x 2
Vapour Density = \(\frac{\text{Molecular Mass}}{2}\)
Where Molecular mass = 98g/mol
Vapour Density = \(\frac{98}{2}\)
Vapour Density = 49g/mol
Source: Myschool Past Questions Archive (Record #47664)
Chemistry
UTME / JAMB 2018
Atomic Structure and Periodic Table
Solution
The elements in the periodic table are listed in order of increasing
A
relative atomic number
B
atomic mass
C
relative isotopic mass
D
nuclear charge
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The periodic number table is arranged in order of atoms increasing atomic number
Source: Myschool Past Questions Archive (Record #47670)
Chemistry
UTME / JAMB 2018
Atomic Structure and Periodic Table
Solution
H\(_2\) S\(_{(g)}\) + Cl\(_{2(g)}\) → 2HCl\(_{(g)}\) + S\(_{(g)}\) In the reaction above, the substance that is reduced is
A
H\(_2\)S
B
S
C
HCl
D
Cl\(_2\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
H \(_2\) S + Cl \(_2\) → 2HCl + S
Please note: substance oxidized or reduced are always the reactants. So, one can easily cross out the two products.
Reduction is
1. Addition of hydrogen
2. Removal of Oxygen
3. Addition of Electron
Oxidation is
1. Removal of hydrogen
2. Addition of hydrogen
3. Removal of Electron
From the question we can see that H was added to Cl in the product, thereby making hydrogen to be removed from S in the reactant hence S is oxidized as a result of the removal of hydrogen and Cl \(_2\) has been reduced due to addition of hydrogen.
Cl \(_2\) is reduced
Source: Myschool Past Questions Archive (Record #47671)
Chemistry
UTME / JAMB 2018
Matter & Separation Techniques
Solution
Which of the compounds is composed of Al, Si, O and H?
A
Epson salt
B
Limestone
C
Clay
D
Urea
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Between the five main minerals found in clay, kaolinite is the most common. Kaolinite holds the chemical composition A\(l_2\) S\(i_2\)\(O_5\)(OH)\(_{4}\) and is an aluminum silicate material with a low “shrink-swell” capacity. It is a soft, white mineral but is often colored orange or red by iron oxide found in the soil.
Source: Myschool Past Questions Archive (Record #47672)
Chemistry
UTME / JAMB 2018
Stoichiometry & Mole Concept
Solution
When large hydrocarbon molecules are heated at high temperature in the presence of a catalyst to give smaller molecules, the process is known as
A
disintegration
B
polymerization
C
cracking
D
degradation
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Cracking is the breakdown of a large alkane into smaller, more useful alkenes. Simply put, hydrocarbon cracking is the process of breaking a long-chain of hydrocarbons into short ones. This process might require high temperatures and high pressure.
Source: Myschool Past Questions Archive (Record #47673)
Chemistry
UTME / JAMB 2018
Matter & Separation Techniques
Solution
In the removal of water hardness, permutit is regenerated with a strong solution of
A
NaOH
B
Na\(_3\)SO\(_4\)
C
Na\(_3\)CO\(_3\)
D
NaCl
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
permutit water softener can be regenerated by washing the spent resin with brine( saturated sodium chloride solution). The solution ions replace the calcium or magnesium ions present in it.
\(CaR_{2(s)}\) + 2\(NaCl_{aq}\) → \(CaCl_{2(aq)}\) + 2\(NaR_{2(s)}\)
Source: Myschool Past Questions Archive (Record #47674)
Chemistry
WAEC / WASSCE 2018
Electrochemistry and Redox
Which of the following equations represents a redox reaction?
A
\(HNO_{{3}{(aq)}} + NaOH_{(aq)} \to NaNO_{{3}{(aq)}} + H_{2}O_{(l)}\)
B
\(AgNO_{{3}{(aq)}}+KCl_{(aq)} \to AgCl_{(s)}+KNO_{{3}{(aq)}}\)
C
\(CaCO_{{3}{(s)}} \to CaO_{(s)} + CO_{{2}{(g)}}\)
D
\(2H_{2}S_{(s)} + SO_{{2}{(g)}} \to 2HO_{2} + 3S_{(g)}\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #48961)
Chemistry
WAEC / WASSCE 2018
Electrochemistry and Redox
Solution
The process of extraction of iron from its ore is
A
decomposition
B
oxidation
C
reduction
D
sublimation
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The Iron is to to be gotten by the removal of oxygen from its ore, and this is called a reduction reaction.
Source: Myschool Past Questions Archive (Record #48963)
Chemistry
WAEC / WASSCE 2018
Acids, Bases, and Salts
Solution
What is the solubility of a salt if 0.4g of it is obtained on evaporating 200\(cm^{3}\) of its saturated solution to dryness?
A
0.08\(gdm^{-3}\)
B
2.00\(gdm^{-3}\)
C
8.00\(gdm^{-3}\)
D
80.00\(gdm^{-3}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
1000\(cm^{3}\) = 1\(dm^{3}\)
200\(cm^{3}\) = 0.2\(dm^{3}\)
⇒ 0.2\(dm^{3}\) contains 0.4g
hence, solubility of the salt which is the amount of the salt dissolvable in 1\(dm^{3}\) is
\(\frac{0.4g}{0.2dm^{3}} = 2.0gdm^{-3}\)
Source: Myschool Past Questions Archive (Record #48965)
Chemistry
WAEC / WASSCE 2018
Acids, Bases, and Salts
Solution
An acidic salt has
A
double anions in its aqueous solution
B
a single cation in its aqueous solution
C
hydrogen ions in its aqueous solution
D
hydrogen atoms in its aqueous solution
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Acid salts are salts whose aqueous solutions are acidic in character, implying that their aqueous solutions possess hydrogen ions.
Source: Myschool Past Questions Archive (Record #48966)
Chemistry
WAEC / WASSCE 2018
Kinetics, Energetics and Equilibrium
Solution
A reaction is endothermic if the
A
reaction vessel feels cool during the reaction
B
enthalpy change is negative
C
bond forming energy exceeds bond breaking energy
D
heat of formation of reactants exceeds heat of formation of products
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Endothermic reactions absorb heat from their surroundings during the reaction process. This means that in the course of the reaction the vessel being used in the reaction will be cool in the process.
Source: Myschool Past Questions Archive (Record #48967)
Chemistry
UTME / JAMB 2018
Acids, Bases, and Salts
Solution
A sample of hard water contains some calcium sulphate and calcium hydrogen carbonate. The total hardness may therefore be removed by
A
boiling the water
B
adding excess calcium hydroxide
C
adding a calculated amount of calcium hydroxide
D
adding sodium carbonate
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
its D because when sodium carbonate reacts with calcium hydrogentrioxocarbonate it gives sodium hydrogentrioxocarbonate and calcium trioxocarbonate. However, when it react with calcium sulphate, calcium carbonate and sodium tetraoxosulphate is formed
Source: Myschool Past Questions Archive (Record #47675)
Chemistry
UTME / JAMB 2018
Matter & Separation Techniques
Solution
Which of the following separation techniques can be employed in obtaining solvent from its solution?
A
Evaporation
B
Distillation
C
Filtration
D
Precipitation
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Distillation is the process of separating the components or substances from a liquid mixture by using selective boiling and condensation.
Source: Myschool Past Questions Archive (Record #47676)