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Physics
UTME / JAMB 1982
Heat Energy & Temperature
Solution
If the refractive index of a medium is \(\sqrt{2}\), what is the critical angle?
A
45o
B
50o12'
C
56o25'
D
75o
E
90o
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
sin C = \(\frac{1}{n}\) ; sin C = \(\frac{1}{\sqrt2}\)
C = sin-1\(\frac{1}{\sqrt2}\)
= 45o
Source: Myschool Past Questions Archive (Record #28923)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
Solution
The equation P\(^x\)V\(^y\)T\(^z\) = constant
A
x = 0, y = 0, z = 1
B
x = 1, y = 0, z = 0
C
x = 1, y = 1, z = 0
D
x = 1, y = 1, z = 1
E
x = 1, y = 1, z = -1
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
From general gas equation
\(\frac{P V }{T}\) = P\(^1\)V\(^1\)T\(^{-1}\) = constant.
Comparing this with P\(^x\)V\(^y\)T\(^z\) = constant
x = 1, y = 1 and z = -1
Source: Myschool Past Questions Archive (Record #28932)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
The range of accommodation of a normal human eye is
A
0m to 0.1m
B
0m to 0.25m
C
0.10m to 0.25m
D
0.10m to infinity
E
0.25m to infinity
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #28938)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
A hydrometer is an instrument for measuring the
A
depth of water in a vessel
B
relative density of a liquid by the method of flotation
C
relative dendity of a liquid by finding the apparent loss in weight
D
relative humidity of the air
E
atmospheric pressure when the air is humid
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28940)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
The point beyond which a stretched spring does not return to its original length is called the
A
breaking point
B
elastic limit
C
spring constant
D
elasticity point
E
release point
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28941)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
Solution
a body of mass 10kg on a smooth inclined plane is connected to a smooth pulley to a mass of 15kg as shown above, the acceleration of the system is
A
\(\frac{1}{4}\)g
B
\(\frac{8}{25}\)g
C
\(\frac{1}{2}\)g
D
\(\frac{2}{5}\)g
E
\(\frac{3}{4}\)g
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Given:
- \( m_1 = 10 \, \text{kg} \) (on incline)
- \( m_2 = 15 \, \text{kg} \) (hanging)
- \( \theta = 30^\circ \)
Inclined mass:
\( F_{\text{incline}} = m_1 g \sin(\theta) = 10g \cdot 0.5 = 5g\)
Hanging mass:
\(F_{\text{weight}} = m_2 g = 15g\)
Net Force: \(F_{\text{net}} = F_{\text{weight}} - F_{\text{incline}} = 15g - 5g = 10g\)
Total Mass
\(m_{\text{total}} = m_1 + m_2 = 25 \, \text{kg}\)
Using \( F_{\text{net}} = m_{\text{total}} \cdot a \):
\(10g = 25a \quad \Rightarrow \quad a = \frac{10g}{25} = \frac{2g}{5}\)
The acceleration is:
\(a = \frac{2g}{5} \, \text{m/s}^2\)
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 1982
Heat Energy & Temperature
Diagram
Two taxis leave benin and agbor some 80km apart at 1200hr as shown above. from the distance time graph shown the distance of their meeting point P, from Benin and the time of their meeting are
Attached Figure / Diagram
A
27km, 1218hr
B
29km, 1315hr
C
40km, 1418hr
D
53km, 1436hr
E
60km, 1500hr
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #41619)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
Diagram
Solution
what is the resultant capacity of the circuit
Attached Figure / Diagram
A
1.5µF
B
18.0µF
C
6.0µF
D
6.8µF
E
8.83µF
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
1\muf and 5\muf are parallel;
Ceff = 1 + 5 = 6\muf
6\muf, 4\muf and 4\muf are in series.
total capacitance of the circuit in series( \(\frac{1}{C_T}\)) = \(\frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}\)
= \(\frac{1}{4} + \frac{1}{4} + \frac{1}{6}\)
= \(\frac{ 6 + 6 + 4}{ 24}\) = \(\frac{ 16}{ 24}\)
\(\frac{1}{C_T}\) = \(\frac{ 16}{ 24}\)
\(C_T\) = \(\frac{24}{ 16}\) = 1.5\muf.
Source: Myschool Past Questions Archive (Record #41623)
Physics
UTME / JAMB 1982
Heat Energy & Temperature
Diagram
Solution
The value of the series resistor required to convert the above galvanometer into a voltmeter with a full range deflection of 15V is
Attached Figure / Diagram
A
985 ohms
B
990 ohms
C
995 ohms
D
1000 ohms
E
1005 ohms
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The value of the resistor R = \(\frac{V_{fs}}{I_s}\) - R\(_g\)
R = \(\frac{15}{0.015}\) - 5
R = 1000 - 5 = 995\(\Omega\)
Source: Myschool Past Questions Archive (Record #41628)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Heat was supplied to a block of ice at 0oC until half of it melted. Which of the following statements is true?
A
the temperature rises and the ice expand
B
the temperature remains constant and the volume of the ice decreases
C
the ice gives out heat as it melts and the temperature decreases
D
the mass remains constant and the temperature increases
E
the temperature decreases because some heat is lost
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28995)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Solution
An aircraft travelled from calabar to kano as follows: it flew first to ilorin convering a distance of 300km, 30o west of North, and then flew 400km, 60o East of North to kano. What is the resultant displacement?
A
567km
B
410km
C
594km
D
500km
E
600km
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
R2 = 3002 + 4002
R2 = 90000 + 160000
R = \(\sqrt{250000}\)
= 500km
Source: Myschool Past Questions Archive (Record #29006)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Which of the following statements is CORRECT?
A
charges generated on glass rubbed with silk are called negative
B
charges in various media can be carried by protons detached from their atom
C
the magnitude of any charge is a multiple of the charge of an electron
D
the intensity of an electric field is a scalar quantity
E
if 500 joules of work are required to move a 2-coulomb charge between two points, the potential difference between the two point is 100V
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #29013)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Solution
The mass of a proton is approximately equal to that of
A
an \(\alpha\)-particle
B
a \(\beta\)-particle
C
\(\gamma\)-ray
D
an electron
E
a neutron
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Protons and neutrons have approximately the same mass, about 1.67 \times 10\(^{-24}\) grams
Source: Myschool Past Questions Archive (Record #29025)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Solution
The extension in a spring when 5g wt was hung from it was 0.56cm. If Hooke's law is obeyed, What is the extension caused by a load of 20g wt?
A
1.12m
B
2.14cm
C
2.52cm
D
2.80cm
E
2.24cm
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Extension & Load
Extension = K constant
\(\frac{\text{load}}{0.56cm}\) = \(\frac{X}{20g}\)
X = 2.24cm
Source: Myschool Past Questions Archive (Record #29030)
Physics
UTME / JAMB 1981
Heat Energy & Temperature
Solution
in a light experiment with a convex lens a student plotted a graph as shown above of the reciprocal of object distance (1)/u against the reciprocal of image distance (1)/v . the focal length of the lens is given as
A
slope of line PQ
B
Reciprocal of either OP or OQ
C
Length OP or OQ
D
area under the graph E ratio OP/OQ
E
100Hz
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The intercept on either of the axes of the graph of \(\frac{1}{u}\) against \(\frac{1}{v}\) gives the value of \(\frac{1}{f}\). Hence, the reciprocal of this intercecpt gives the value of the focal length.
Source: Official Exam / Past Question Archive