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Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Solution
When two flat plate conductors are arranged in such a way that they possess equal and opposite charges seperated by a dielectric, they form a/an
A
electroscope
B
electrophorus
C
capacitor
D
cell
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Most capacitors contain at least two electrical conductors often in the form of metallic plates or surfaces separated by a dielectric medium.
Source: Myschool Past Questions Archive (Record #49743)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Diagram
Solution
Which electrical device is illustrated above?
Attached Figure / Diagram
A
a.c. generator
B
a.c. motor
C
d.c. generator
D
d.c. motor
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
In a DC generator, the coil rotates within a magnetic field, and the commutator is employed to convert the alternating current generated in the coil into direct current. The presence of the magnetic field, represented by the north (N) and south (S) poles, further confirms its identification as a DC generator.
Source: Myschool Past Questions Archive (Record #49748)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
A resistor with fixed resistance value is called a
A
resistance box
B
standard resistor
C
shunt resistor
D
multiplier resistor
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #49808)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
In which of the following activities is an induction coil not useful?
A
Investigation of high voltages
B
Study of electric discharge
C
Operation of X-ray tubes
D
A.C. power transmission
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #49869)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Diagram
Solution
A student uses two compass needles to investigate the magnetic field around a bar magnet. Which of the following diagrams show the correct directions of the needles?
Attached Figure / Diagram
A
A
B
B
C
C
D
D
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
By convention, the field direction is taken to be outward from the North pole and in to the South pole of the magnet. Also, they form closed lines.
Source: Myschool Past Questions Archive (Record #49876)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Solution
State three materials used for making optical fibres.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Materials for making optical fibre are Glass, Polycarbonate, Teflon sheath, Silica, quartz, Silicon, Sapphire. Feromagnetic
Source: Myschool Past Questions Archive (Record #52864)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Solution
Name three classes of magnetic materials.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Three classes of magnetic materials are
(i) Diamagnetic
(ii) Paramagnetic
(iii) Feromagnetic
Source: Myschool Past Questions Archive (Record #52865)
Physics
WAEC / WASSCE 2018
Electricity and Magnetism
Solution
(a) What is an intrinsic semiconductor?
(b) Distinguish between the p-type and n-type semi-conductors.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) An intrinsic semiconductor contains equal number of free electrons and holes.
(b)
p— TYPE
n - TYPE
i
The majority carrier of electricity is holes.
The majority carrier of electricity is electron.
ii
Carries a net positive charge
Carries a net negative charge
iii
The impurity is trivalent
The impurity is pentavalent.
Source: Myschool Past Questions Archive (Record #52866)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
A
18.57NC\(^{-1}\)
B
53.06N C\(^{-1}\)
C
2.28NC\(^{-1}\)
D
0.80NC\(^{-1}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Electric Field Intensity (E) = \(\frac{v}{d}\)
= \(\frac{\text{potential difference}}{\text{distance}}\)
= \(\frac{6.5v}{35cm}\)
= \(\frac{6.5}{35 \times 10^{- 2}}\)
= 18.57NC\(^{-1}\)
Source: Myschool Past Questions Archive (Record #46376)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
A cell of internal resistance 2\Omega supplies current to a 6\Omega resistor. The efficiency of the cell is
A
12.0%
B
25.0%
C
33.3%
D
75.0%
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Internal resistance determine the maximum current that can be supplied
Efficiency = \(\frac{R}{R+ r}\) \times 100
= \(\frac{6}{8}\) \times 100
= 75%
Source: Myschool Past Questions Archive (Record #46384)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
Three 3ω resistance are connected in parallel what is the equivalent resistance?
A
1ω
B
9ω
C
3ω
D
0.33ω
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Resistor connected in a parallel have an equivalence given by
\(\frac{1}{\text{Reff}}\) = \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)
= \(\frac{1 + 1 + 1}{3}\) = \(\frac{3}{3}\) = 1
Reff = 1ω
Source: Myschool Past Questions Archive (Record #46390)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
When the r.m.s value of a source of electricity supply is given as 240v, it means that the peak value of the supply is
A
240v
B
340v
C
480v
D
57600v
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The relationship between the peak value and r.m.s value of electricity supply is given as
V\(_{r.m.s}\) = \(\frac{V_o}{\sqrt{2}}\)
where Vo = peak voltage
∴ Vo = V\(_{r.m.s}\) × √2
= 240 × √2
= 339.5v
= 340v
Source: Myschool Past Questions Archive (Record #46398)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
Which of the following operations can be used to convert an alternative current dynamo into a direct current dynamo
A
number of turns in the coil is increased
B
strength of the field magnet is increased
C
slip rings are replaced with split ring commutator
D
coil is wound on a soft iron armature
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
A d.c generator is one in which its current is allowed to flow in one direction even through it may vary in value an a.c generator can only be made to produce a d.c by replacing the two slip rings with a single split ring or commutator.
Source: Myschool Past Questions Archive (Record #46399)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Solution
Which of the following is correct about an electric cell?
A
Primary cell produces a large current for a long time
B
Secondary cell has a very high internal resistance
C
Primary cell has a very low internal resistance
D
Secondary cell has a very low internal resistance
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
About electric cell
Primary cells are used up gradually often the cells are use and it can't be recharged
Secondary cells or accumulated can be recharged and used for a long period of time and their main advantage is that they have low internal resistance
Source: Myschool Past Questions Archive (Record #46432)
Physics
UTME / JAMB 2017
Electricity and Magnetism
Diagram
Solution
From the diagram above, calculate the total current in the circuit
Attached Figure / Diagram
A
5.0A
B
3.7A
C
4.5A
D
4.0A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
V = IR from ohms law
I = \(\frac{V}{R}\)
Since the resistances are in parallel
\(\frac{1}{Reff}\) = \(\frac{1}{18}\) + \(\frac{1}{12}\) + \(\frac{1}{6}\)
= \(\frac{2 + 3 + 6}{36}\) = \(\frac{11}{36}\)
R\(_{eff}\) = \(\frac{36}{11}\) = 3.27
I = I\(_1\) + I\(_2\) + I\(_3\)
= \(\frac{V}{Reff}\)= \(\frac{12}{3.27}\)
= 3.669A
I = 3.7A
Source: Myschool Past Questions Archive (Record #46451)