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Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Which of the following quantities has the same unit as energy?
A
power
B
work
C
force
D
momentum
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #34458)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Which of the following source of energy is renewable?
A
sun
B
petroleum
C
coal
D
uranium
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #34459)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Solution
Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10ms2]
A
0.119oC
B
0.840oC
C
1.190oC
D
8.400oC
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
mgh = mc\(\theta\)
\(\theta = \frac{gh}{c} = \frac{10 \times 50}{4200}\)
= 0.119oC
Source: Myschool Past Questions Archive (Record #34473)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
The energy required to change a solid to liquid at constant temperature is called
A
thermal capacity
B
has lower specific heat capacity
C
latent heat of fusion
D
latent heat of vaporisation
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #34478)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Which of the following statements about boiling and evaporation at atmospheric pressure is correct?
A
evaporation and boiling of water take place at 100o
B
evaporation of water takes place at a temperature greater than 100oC, while boiling takes place at 100oC
C
evaporation of water takes place at 100oC while boiling takes place at a higher temperature
D
boiling takes place at 100o while evaporation my take place at temperatures lower than 100oC
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #34480)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
The pressure exerted by a given mass of gas in a container
A
decreases if the container is heated
B
increases if the molecules of the gas move faster
C
increases if the container is doubled
D
decreases as the kinetic energy of the gas molecules inceases
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #34485)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Solution
The mass and weight of a body on earth are 8kg and 80N respectively. Determine the mass and weight of the body respectively on a planet where the pull of gravity is \(\frac{1}{8}\) that on earth
A
8kg, 8N
B
1kg, 10N
C
64kg, 10N
D
8kg, 10N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
m = 8kg, wt = 80 x \(\frac{1}{8}\) = 10N
Source: Myschool Past Questions Archive (Record #34559)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Solution
Light of energy 5.0 eV falls on a metal of work function 3.0 eV and electrons are emitted, determine the stopping potential. [electronic charge, e = 1.60 x 108ms-19]
A
1.7V
B
2.0V
C
8.0V
D
15.0V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(V_8 \frac{hf - w_o}{e} = \frac{5.0 \times 1.60 \times 10^{-19} - 3.0 \times 1.6 \times 10^{-19}}{1.6 \times 10^{-19}} = 2.0V\)
Source: Myschool Past Questions Archive (Record #34604)
Physics
WAEC / WASSCE 2005
Mechanics and Properties of Matter
Solution
The mass of a proton is 1.0089\(\mu\) and that of a neutron is 1.0089\(\mu\). Determine the energy evolved in stabilizing the nucleus of nitrogen of mass number 14 with 7 protons and 7 neutrons. [speed of light = 3.0 x 108ms-1; 1\(\mu\) = 1.67 x 10-27kg]
A
1.710 x 10-8J
B
3.131 x 10-8J
C
1.476 x 10-8J
D
2.332 x 10-9J
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
E = DMC2 = 14,1141 x 1.67 x 10-27 x 9 x 1016
= 2.332 x 10-9J
Source: Myschool Past Questions Archive (Record #34609)
Physics
UTME / JAMB 2005
Mechanics and Properties of Matter
Solution
The velocity of sound in air will be doubled if it's absolute temperature is
A
Quadrupled
B
Constant
C
Halved
D
Doulbed
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
In general, the velocity of sound in air varies directly as the square root of temperature measured in kelvin.
That V \( \propto \sqrt{T} \implies V^2 \propto T.\)
\(\text{Therefore} \frac{V^2_1}{T_1} = \frac{V^2_2}{T_2}\)
\(\text{Thus Let } V_1\) = 4m/s
T\(_1\) = 10K
\(\text{Therefore } V_2 = 2V_1\) = 8m/s
\(\implies \frac{4^2}{10} = \frac{8^2}{T_2}\)
T\(_2 = \frac{64 \times 10}{16}\) = 40K
T\(_2 = 4T_1 \)
Thus, when the velocity of sound in air is doubled, its absolute temperature will be quadrupled.
Source: Myschool Past Questions Archive (Record #41430)
Physics
UTME / JAMB 2005
Mechanics and Properties of Matter
Solution
A force of 200N acts between two objects at a certain distance apart. The value of the force when the distance is halved is
A
400N
B
200N
C
100N
D
800N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Let the masses of the two objects be M1 and M2
and their distance apart = r
Therefore the force acting F1 = \( \frac{GM1M2}{r^2}\)
for a new distance of r/2, we have a force of
F2 = \( \frac{GM2M2}{r/2}\)
\(\text{Thus } F1 \times r^2 = GM_1M_1 \text{and}\)
F2 \(\times (r/2)^2 = GM_1M_1\)
\(\text{Since } GM1M1 = GM_1M_1\)
\(\implies F_1 \times r^2 = F2 \times (r/2)^2\)
\(\text{Therefore } 200 \times r^2 = F2 \times r^2/4\)
F2 = \(\frac{4 \times 200 \times r^2}{r^2} = 800N\)
Source: Myschool Past Questions Archive (Record #41440)
Physics
NECO SSCE 2005
Mechanics and Properties of Matter
A body moves along a circular path with uniform angular speed of 0.6 rad s-1 and at a constant speed of 3.0 ms-1.
Calculate the acceleration of the body towards the centre of the circle.
A
0.2.ms-2
B
1.8 ms-2
C
5.0 ms-2
D
5.4 ms-2
E
25.0 ms-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #42998)
Physics
NECO SSCE 2005
Mechanics and Properties of Matter
Which of the statements is/are true of two bodies involved in an inelastic collision? After collision.
I. the kinetic energy increases
II. The momentum decreases
III. Their velocities are the same.
A
I only
B
II Only
C
III only
D
I and II only
E
II and III only
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #42999)
Physics
NECO SSCE 2005
Mechanics and Properties of Matter
Solution
A projectile is projected with an initial velocity u, at an angle \theta to the horizontal. The maximum height attained is.
A
U2 sin \(\frac{\theta}{g}\)
B
2U2 sin2 \(\frac{\theta}{g}\)
C
U sin2 \(\frac{\theta}{g}\)
D
U2 sin2\(\frac{\theta}{2g}\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Using V\(^2\) = (Uy)\(^2\) - 2gH
But Uy = usin\theta
At max. Height, V = 0
0 = (Uy)\(^2\) - 2gH
- (Uy)\(^2\) = - 2gH
H = \(\frac{u^2(sin)^2\theta}{2g}\)
Source: Myschool Past Questions Archive (Record #43006)
Physics
NECO SSCE 2005
Mechanics and Properties of Matter
Calculate the magnitude of the force due to a magnetic field of 0.40T on an electron moving perpendicular to the field with a speed of 4.00 × 106ms-1 (e 1.60 × 10-19C]
A
6.40 × -10
B
6.40× 10-13N
C
2.56 × 10-13N
D
1.60 × 10-12N
E
2.30 × 10-11N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43008)