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Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
The quality of a note produced by a vibrating string is determined by the
A
pitch of the note
B
tension of the string
C
material of the string
D
presence of overtones
E
thickness of the string
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #25018)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
Which of the following is a percussion instrument?
A
Flute
B
Organ
C
Bell
D
Piano
E
Sonometer
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25019)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
The unit of inductance is
A
farad
B
henry
C
hertz
D
weber
E
tesla
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #25023)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
What is the gravitational potential due to a point mass m at a distance from it? (G = gravitational constant)
A
-Gm2/r2
B
-Gm2/r
C
–Gm/Gr2
D
–Gm/r
E
–Gm/2
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #25026)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
The function of the magnanese (IV) oxide in a leclanche cell is to
A
decrease the e.m.f. of the cell
B
prevent local action in the cell
C
prevent polarization in the cell
D
increase the density of the electrolyte
E
increase the resistance of the cell.
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25034)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
Diagram
ln the diagram below, the galvanometer indicates a null-deflection. What is the potential difference between P and Q?
Attached Figure / Diagram
A
0.0 V
B
1.5 V
C
2.0 V
D
3.0V
E
4.0 V.
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #25039)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
The phenomenon of radioactivity was first discovered by
A
Marie Curve
B
Sir J.J Thomson
C
Henn Becquerel
D
Niels Bohr
E
Enrico Fermi
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25046)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
Eight or - particles and size B - particles are emitted from an atom of 92238U before it achieves stability. What is the nucleon number of the final product in the chain reaction?
A
206
B
234
C
238
D
240
E
252
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #25050)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
When an atom is in the ground state, it is said to be
A
grounded
B
excited
C
stable
D
ionized
E
radiating
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #25051)
Physics
WAEC / WASSCE 1993
Heat Energy & Temperature
Solution
(a)(i) Explain what is meant by a machine (ii) Define the terms: mechanical advantage, velocity ratio and efficiency as applied to a machine. Derive the equation connecting the three terms.
(b) Explain why the efficiency of a machine is usually less than 100%
(c) A screw jack whose pitch is 4.4mm is used to raise a body of mass 8000 kg through a height of 20cm. The length of the tommy bar of the jack is 70cm. If the efficiency of the jack is 80%, calcuate the: (i) velocity ratio of the jack; (ii) mechanical advantage of the jack (iii) effort required in raising the body, (iv) work done by the effort in raising the body \((g = 10ms^{-2}; \pi = \frac{22}{7}\))
A
Gamma rays
B
Alpha particles
C
Beta particles
D
Protons
E
Neutrons
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
(a)(i) A machine is a device used to overcome a load at one end by the application of an effort at another end. Examples of simple machine include the screw jack, can opener, pulley system. (ii) M.A. is the ratio of the load (L) to the Effort (E).
\(M.A = \frac{Load}{Effort}\)
V.R. is the ratio of the distance moved by the effort tc the distarice moved by the load (at the same time).
\(V.R = \frac{\text{distance moved by effort}}{\text{distance moved by load}}\)
Efficiency (E) is the ratio of the useful work done by the machine (work output) to the total work put into the machine (work input).
\(Efficiency = \frac{\text{work done on load}}{\text{work done by effort}} \times 100%\)
\(Efficiency = \frac{M.A}{V.R} \times 100%\);
\(Work = Force \times Distance\)
\(Efficiency = \frac{\text{work output}}{\text{work input}} \)
= \(\frac{Load \times \text{distance moved by load}}{Effort \times \text{distance moved by effort}}\)
= \(M.A \times \frac{1}{V.R} \times 100%\)
(b) The efficiency of a simple machine is not 100% because of the work done in overcoming friction.
(c) length of tommy bar. L = 70cm = 0.7m; Pitch = 4.4mm = 0.0044m.
(i) \(V.R = \frac{2\pi L}{pitch} = \frac{2 \pi \times 0.7}{0.0044}\)
= \(2 \times \frac{22}{7} \times \frac{0.7}{44 \times 10^{-4}}\)
\(V.R = 1000\)
(ii) \(Efficiency = \frac{M.A}{V.R} \times 100%\)
\(\frac{80}{100} = \frac{M.A}{1000} \implies M.A = 800\)
(iii) \(M.A = \frac{Load}{Effort}\)
\(Effort = \frac{8000 \times 10}{800} = 100N\)
(iv) Work done = \(\frac{load \times \text{distance moved by load}}{effort \times \text{distance moved by effort}}\)
= \(\frac{8000 \times 10 \times 0.2}{0.8} = 20,000J\)
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 1993
Heat Energy & Temperature
Solution
In the network shown above, determine the potential difference across the 5µF capacitor
A
3V
B
6V
C
12V
D
18V
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
For capacitors in series
C\(_{\text{eq}} = \frac{C_1 C_2}{C_1 + C_2}\)
C\(_{\text{eq}} = \frac{5 \times 15}{5 + 15} = \frac{75}{20}\) = 3.75μF
Charge on the series branch
Q = Ceq \times V =3.75 \times 24 = 90 μC.
Potential difference across the 5 µF capacitor
V\(_{5} = \frac{Q}{C} = \frac{90}{5}\) = 18 V
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 1993
Heat Energy & Temperature
Which of the following quantities has the same unit as the watt?
A
Force x time
B
Force x distance
C
Force x acceleration
D
Force x velocity
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27945)
Physics
UTME / JAMB 1993
Heat Energy & Temperature
Solution
The external and internal diameter of a tube are measured as (32 \pm 2)mm and (21 \pm 1)mm respectively. Determine the percentage error in the thickness of the tube.
A
27%
B
14%
C
9%
D
3%
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The thickness of the tube is given by:
thickness = (external diameter − internal diameter) / 2
= (32 − 21) / 2
= 11 / 2
= 5.5 mm
Let t = thickness = \(\frac{(D − d)}{2}\), where D = external diameter and d = internal diameter.
The absolute error in thickness is found using the rules for propagation of errors (for subtraction and division by a constant):
\Deltat = \(\frac{(\DeltaD + \Deltad)}{2}\)
= \(\frac{(2 + 1)}{2}\) = \(\frac{3}{2}\)
=1.5 mm.
The percentage error in thickness is:
Percentage error = \(\frac{\Deltat }{\text{t}}\) \times 100%
= (\(\frac{1.5}{ 5.5}\)) \times 100%
= (\(\frac{15}{ 55}\)) \times 100%
= (\(\frac{3}{11}\)) \times 100% ≈ 27.27%
Source: Myschool Past Questions Archive (Record #27952)
Physics
UTME / JAMB 1993
Heat Energy & Temperature
The thermometric properties of the thermocouple is that is
A
e.m.f. changes with temperature
B
resistance changes with temperature
C
volume changes with temperature
D
pressure changes with resistance
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27974)
Physics
UTME / JAMB 1993
Heat Energy & Temperature
Solution
A metal rod 800mm long is heated from 10oC to 95oC. If it expands by 1.36mm, the linear expansivity of the metal is
A
2.0 x 102K-1
B
2.0 x 102K-1
C
5.0 x 10-3K-1
D
2.0 x 10-5K-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
a = \(\frac{1.36}{800 \times (95 - 10)}\)
= 2.0 x 10-5K-1
Source: Myschool Past Questions Archive (Record #27978)