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Physics
WAEC / WASSCE 2021
Heat Energy & Temperature
Which of the following set of quantities have members which are all vectors?
A
Pressure, energy and force
B
Force, displacement and momentum
C
Distance, acceleration and work
D
Density, volume and weight
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #62314)
Physics
WAEC / WASSCE 2021
Heat Energy & Temperature
If the relative humidity of the atmosphere increases, the rate of evaporation of sweat from the human body?
A
decreases
B
remains the same
C
increases then decreases
D
increases
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #62315)
Physics
WAEC / WASSCE 2021
Electricity and Magnetism
Which of the following factors is not among that determines the resistance of a wire?
A
mass
B
cross-sectional area
C
length
D
material
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #62316)
Physics
WAEC / WASSCE 2021
Waves and Optics
Solution
State three observable phenomena where a particle behaves like waves. State the scientific principle underlying the operation of fibre optics.
(b) Explain each of the following terms as used in fibre optics: (i) core; (ii) cladding
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Observable phenomena when a particle behaves like Waves: (a) Diffraction: (b) Interference: (c) Compton effect: (d) Polarization: (e) Refraction (f) Reflection.
(b) (i) Core: The inner glass center where light travels. It has a high refractive index to keep the signal contained.
(ii) Cladding: The outer layer surrounding the core. It has a lower refractive index to reflect light back into the core, preventing signal loss.
Source: Myschool Past Questions Archive (Record #62323)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
Solution
(a)(i) State Hooke's law. (ii) A spring has a length of 0.20 m when a mass of 0.30 kg hangs on it, and a length of 0.75 nm when a mass of 1.95 kg hangs on it. Calculate the: (i) force constant of the spring; (ii) length of the spring when it is unloaded. [g = 10m/s\(^2\)]
(b)(i) What is diffusion? (ii) State two factors that affect the rate of diffusion of a substance. (iii) State the exact relationship between the rate of diffusion of a gas and its density.
(c) A satellite of mass, m orbits the earth of mass. M with a velocity, v at a distance R from the centre of the earth. Derive the relationship between the period T, of orbit and R.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Hooke's Law: This states that provided the elastic limit is not exceeded, the extension or compression of an elastic material is directly proportional to the applied force. (ii) Calculation of force constant (K): From Hooke's law:
Mg = Ke = k(l - lo)
0.3 x 10 = k(0.20- lo).. ..(i)
1.95x 10 = k(0.75 - lo) 1) ...(ii)
From (i) lo = \(\frac{3+0.20 k}{lo}\)
From (ii) 19.5 k[0.75 - 0.2 - 3/k]
: K = 30N/m
lo = 0.2 - 3/20
: lo = 0.2 - 0.1 = 0.1m
(b)(i) Definition of diffusion: This is the intimate mixing of substance due to random motion of their molecules/particles.
(b)(ii) Factors that affect the rate of diffusion: (i) Temperature of the environment. (ii) Density of the substance. (iii) Medium of diffusion. (iv) Concentration gradient.
(b)(iii) Relationship between rate of diffusion of a gas and its density:
Rate of diffusion = \(\frac{1}{\sqrtdensity of gas}\)
(c) Derivation of the relationship between the period T, of orbit and R:
\(\frac{MV^2}{R}\) = \(\frac{GMM}{R^2}\)
\(\frac{2\piR}{T}\) = \(\frac{GM}{R}\)
\(T^2\) = \(\frac{4\pi^2R^3}{GM}\)
\(T^2\) \alpha \(R^3\)
Source: Myschool Past Questions Archive (Record #62324)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
Diagram
Solution
c(ii)
(a)(i) Define dew point. (ii) Explain why dew forms more quickly on the metal parts than on the rubber parts of a bicycle placed in the open overnight.
(b)(i) Explain the statement. the specific heat capacity of copper is 400 J/kg/K. (ii) Two metals, P and Q are supplied with the same quantity of heat.
If the ratio of the specific heat capacity of P to Q is 3: 1 and their masses are in the ratio I:2 respectively.
calculate the ratio of the temperature rise of P to Q.
(c)(i) Define coefficient of thermal conductivity of a material.
The diagram above c(ii) illustrates a composite bar of iron and copper. The bar is insulated along its sides and it has a diameter of 10 mm. The length and thermal conductivity of the iron are 0.15 m and 40 W/m/K, respectively and those of copper are 0.05 m and 360 W/m/K, respectively. If the free ends of the iron and copper are kept at 100^\circC and 0^\circC respectively. calculate the (i) temperature at the interface between the bars; (ii) rate of heat flow along the bar.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Dew Point: This is the temperature at which the water vapour/miosture present in the atmosphere/air is just sufficient to saturate it.
(a)(ii) Explanation of why dew forms more quickly on metal parts than rub Metal is a better conductor of heat than rubber. At night. metal loses heat faster than rubber and becomes colder.
Warm air gains latent heat of vaporization from the faster than rubber. Dews are thus formed on the metal parts.
9: (b)(i) Explanation of the statement: 400J of heat/energy is required to charge or raise the temperature of lkg of copper by 1k.
(ii) Heat = mc\DeltaΘ
Hence; MpCp\DeltaΘP = MqCq\DeltaΘq
Given that: Cp : Cq = 3:1 and
Mp : Mq = 1:2
\(\frac{\DeltaΘp}{\DeltaΘq}\) = \(\frac{Cp * Mq}{Cp * Mp}\) → \(\frac{1}{3}\) * \(\frac{2}{1}\)
\DeltaΘp : \DeltaΘq = 2:3
Heat = mc\DeltaΘ
Hence; MpCp\DeltaΘP = MqCq\DeltaΘq
1 * 3 * \DeltaΘp = 2 * 1 * \DeltaΘp
\(\frac{ \DeltaΘp }{ \DeltaΘq}\) = \(\frac{2}{3}\)
\DeltaΘp : \DeltaΘq = 2:3
(c) Definition of Coefficient of Thermal Conductivity: The time rate of flow of heat per unit cross sectional area per unit temperature gradient.
(cii) \(\frac{Θ}{t} = \frac{KA\DeltaΘ}{\DeltaL}\)
\(40 \times \pi \frac{(10 \times10^{-3})^2}{4}\times\frac{(100 - Θ)}{0.15}\)
= \(360 \times \pi \frac{(10 \times10^{-3})^2}{4} \times\frac {Θ - 0}{0.05}\) = 3.6^\circC
(c)(iii) \(\frac{Θ}{t} = 40\pi (\frac{10^{-2}}{4})^3 (\frac{100 - 3.6}{0.15}) = 2.02J/S\)
Source: Myschool Past Questions Archive (Record #62325)
Physics
WAEC / WASSCE 2021
Waves and Optics
Solution
(a)(i) Define each of the following terms as it relates to converging lenses (i) focal length; (ii) optical Centre.
(iii) Draw a ray diagram to illustrate how a converging lens is used to produce a virtual image of an object.
(b)(i) Name the primary colors of light. (ii) Match each primary color to its corresponding complementary color.
(c) A ray passes symmetrically through a glass prism of angle 60^\circ and refractive index of 1.5. Calculate the angle of: (i) incidence; (ii) minimum deviation.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Definition of Terms: (1) Focal length of a converging lens is the distance between the optical centre and the principal focus.
(2) The geometric centre of the lens through which rays of light pass undev1ated. OR Optical centres of a converging lens is a point in the lens through which the principal axıs and light rays pass undeviated.
(b)(i) Primary Colours of Light: (1) Red (2) Blue (3) Green (b)(ii) Match each primary colour to list Corresponding complementary colour:
(1) Red >Cyan (2) BIlue>Yellow (3) Green Magenta
(c)(i) Angle of Incidence: n = \(\frac{Sin i }{Sin r}\);
1.5 = \(\frac{Sin i }{Sin 30}\);
i = 48.6^\circ
Angle of Min Deviation
n = sin \(\frac{D min + A}{2}\)/ [Sin 1/2]
1.5 = Sin \(\frac{D min + A}{2}\)/[sin30]^\circ
D min = 37.2^\circ
Source: Myschool Past Questions Archive (Record #62326)
Physics
WAEC / WASSCE 2021
Electricity and Magnetism
Solution
(a)(i) What is meant by the root-mean-square value of an alternating current? (ii) Define impedance of an alternating current circuit.
(b) An electrical device rated 120 V, 60 W is opened on a 240 V, 50Hz mains supply. The circuit has a capacitor connected in series with ihe electrical device and the supply. Calculate the capacitance of the capacitor. [\pi=3.142].
(c)(i) Define the capacitance of a capacitor.
(ii)
The circuit diagram above illustrates two capacitors of capacitance C\(_1\) and C\(_2\) connected in series across a 2V source.
(i)Obtain an expression for the total capacitance in terms of C\(_2\). 2 mm 5 n (ii) Calculate the potential difference across each capacitor.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)G) Root-mean-square value of an alternating Current 1s the value of a.c. current that has the same heating effect as d.c. current.
(ii) Impedance is the effective resistance of an electric circuit arising from the combined effects of ohmic resistance, capacitance and inductive reactance.
(b) Current in circuit I = 60/120 = 0.5A
Voltage across device V\(_R\) = 120v
Voltage across capacitor = V\(_C\) = \sqrt[V\(^2\) - V\(_R\)\(^2\)]
V\(_C\) = \sqrt[240\(^2\) - 120^\circ]
V\(_C\) = 207.847v
I\(_C\) = I = 0.5A
X\(_C\) = V\(_C\) / I\(_C\)
= \(\frac{207.846}{0.5) → 415.7\Omega
Capicitance, C = \(\frac{X_c}{2\pif}\)
= \(\frac{415.7}{2 * 3.142 * 50}\)
= 1.323F
The capacitance C of a capacitor is the ratio of the amount of charge q on its plates to the potential difference between them, i.e C = q/v
(ii) I - charge on both capacitors are the same q1 = q2
Total capacitance, C = \(\frac{C_1 C_2}{C_1 + C_2}\)
C = \(\frac{C_2}{1 + C_1/C_2}\) = \(\frac{C_2}{1 + V_1 + C_2}\)
C = \(\frac{C_2 V_2}{V_1 + C_2}\) = \(\frac{C_2 V_2}{2}\)
C = 1/2 = \(C_2 V_2\)
II - voltage across V\(_1\) = \(\frac{C_2}{C_1 + C_2}\) * V
V\(_1\) = \(\frac{1}{C_1_{C_2} + 1}\) * V
but \(\frac{C_1}{C_2}\) = \(\frac{C_1}{C_2}\) = \(\frac{5}{2}\)
V\(_1\) = \(\frac{1}{5}{2} + 1}\) * 2
= \(\frac{2}{7}\) * 2 = \(\frac{4}{7}\) V
Voltage across C\(_2\) : V\(_2\) = 2 = \(\frac{4}{7}\) = \(\frac{10}{7}\) V
Source: Myschool Past Questions Archive (Record #62327)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
Diagram
Solution
The load-extension graph of an elastic material is illustrated above. Use the graph to determine the work done in stretching the material
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Determination of work done from the graph: Work done is the area under the graph
Area = \(\frac{1}{2}\) b * h = \(\frac{1}{2} \times 10^{-2} \times 4\) = \(2 \times10^{-2}\)J
Source: Myschool Past Questions Archive (Record #62318)
Physics
WAEC / WASSCE 2021
Heat Energy & Temperature
Solution
(a) Name two artificial satellites.
(b) A geostationary satellite moves in an orbit of radius 6300 km. Calculate the speed with which it moves in the orbit. \pi = \(\frac{22}{7}\)
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Artificial Satellites: (i) Sputrik (ii) Explorer (iii) Astrosat (iv) Skylab (v) GOES (vi) ANIK (vii) GPS (viii) TERRIER (ix) MILSTAR (x) ISS.
(b) Calculation of speed:
V = \(\frac{2\piR}{T}\) = \(\frac{2 * 22 *6300 * 10^3}{7 * 24 * 3600}\) = \(458.33ms^{-1}\)
Source: Myschool Past Questions Archive (Record #62319)
Physics
WAEC / WASSCE 2021
Electricity and Magnetism
Diagram
Solution
The circuit diagram above is a simple current rectifier circuit. Use it to answer the questions that follow
(a) State the function of each of the parts labeled A and B. Sketch the output signal produces.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Functions of parts labeled:
A - Produces the alternating current (a.c.)
B- Smoothens the rectified current.
(b) Output signal:
see the diagram above.
Source: Myschool Past Questions Archive (Record #62321)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
Solution
Explain the wave-particle duality of light. (b) A particle of wavelength 4.2x 10\(^{-11}\)m travels (a) With a momentum of 1.6 x 10\(^{-23}\) kg m/s,
Determine the value of the Planck's constant, h.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Explanation of wave-particle duality of light: Light can act as a particle (by way of Photon) and also simultaneously).
(b) Determination of Planck's Constant
h = \pi P = 4.2 x 10\(^{-11}\) x 1.6 x 10\(^{-23}\) as waves
= 6.72 x 10\(^{-34}\) JS
Source: Myschool Past Questions Archive (Record #62322)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
(a)(i) State the principal factor that determines the relative stability of a radioactive nucleus.
(ii) Arrange the following radioactive nucleus in decreasing order of stability. Justify your answer: X,W and Y:
\(^40{X}_20\) \(^920{Y}_36\) and \(^95{Z}_42\)
(b)(i) Explain the term ionization potential.
(ii)
The diagram above illustrates energy levels in the hydrogen atom. E, is the energy of the E\(_0\) ground state.
(i) When an electron makes a transition from level n = 3 to level n = 1, it emits a photon of wavelength 1.02x 10\(^{-7}\)m. Calculate E\(_0\).
(ii) Calculate the ionization potential of the hydrogen atom.
(c)(i) Explain the statement, the work function of sodium is 2.0 eV. (ii) Light of wavelength 160 mm is shone on the surface of a sodium metal of work function 2.0 eV. Determine whether photoelectrons will be emitted. [h = 6.6 x 10\(^{-34}\) Js, e = 3.0 x 10\(^{8}\)m/s, I eV = 1.6 x 10\(^{-19}\) J]
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option .
Source: Myschool Past Questions Archive (Record #62328)
Physics
WAEC / WASSCE 2021
Mechanics and Properties of Matter
Diagram
Solution
(a) You are provided with a set of masses, a metre rule, a thread, two retort stands and clamps, a stop watch, a knife edge and split corks.
Carry out the following instructions using the diagram above as a guide.
(i) Determine the centre of gravity, C, of the metre rule using the knife edge.
(ii) Read and record the mass, M, of the metre rule written on the reverse side of it.
(iii) Suspend the metre rule by means of two parallel threads of equal length, h =70 cm, with one at the 10 cm mark and the other at 90 cm mark of the metre rule.
(iv) Attach a mass m = 30g firmly to the metre rule at C. Ensure that the graduated face of the metre rule is facing upwards and that d= 80 cm throughout the experiment. (v) Set the metre rule into small angular oscillations about the vertical axis through its centre of gravity by displacing its ends in opposite directions.
(VI) Determine the time,i, for 20 oscillations and evaluate the period T, T\(^2\) and T\(^{-2}\).
(vii) Repeat the procedure for four other values of m =40 g, 50 g, 60 g and 70 g n each case, determine I and evaluate T\(^2\) and T\(^{-2}\).
(viii) Plot a graph of T on the vertical axis and m on the horizontal axis.
(ix) Determine the slope, s, of the graph.
(x) Evaluate Q= 0.68 / s.
(xi) State two precautions taken to ensure accurate results.
(b) (i) Give two examples of simple harmonic motion other than the motion of a simple pendulum.
(ii) Explain the term centre of gravity of a body.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(ai) M = 50.0cm
S\N
m(g)
t(s)
T = \(\frac{t}{20}\)(s)
T\(^2\)(S\(^2\))
T\(^{-2}\)(\(^{-2}\))
1
20.0
30.00
1.50
2.2500
0.4444
2
30.0
32.00
1.60
2.5600
0.3906
3
50.0
35.00
1.75
3.0625
0.3265
4
70.0
37.00
1.85
3.4225
0.2922
5
100.0
40.00
2.00
4.0000
0.2500
Slope, s = \(\frac{\Delta T^2}{\Deltam}\) = \(\frac{0.15 - 0.4}{112 - 34}\) = \(\frac{- 0.25}{78}\) = - 0.0032
(i) Avoid error due to parallax error in the reading my metre rule.
(ii) Ensured that support was rigid
Definition of the period of an oscillatory motion.
(b)(i) The period of an oscillatory motion is the time taken to complete one oscillation.
(ii) Differences between mass and weight
Mass is the measure of the amount of matter in a body. Mass is denoted using m or M.
Weight is the measure of the amount of force acting on a mass due to the acceleration due to gravity. Weight usually is denoted by W.
SEE THE GRAPH ABOVE.
Source: Myschool Past Questions Archive (Record #62349)
Physics
WAEC / WASSCE 2021
Waves and Optics
Solution
You have been provided with a ray box, a converging lens, a lens holder, a screen, a metre rule, and half- metre rule. Use the diagram above as a guide to perform the experiment.
(i) Determine the approximate focal length f, of the lens by focusing a distant object on the screen.
(ii) Place the ray box and the screen such that the distance between the illuminated cross-Wire and the screen, D= 150 cm.
(iii) Place the lens at a position L where a sharp mage of the cross-Wire Is obtained on the screen Note L.
(iv) Move the lens at a position L, to 0btain another sharp image of the cross-wire on the screen. Note L
(V) Measure the distance, d. between L\(_1\) and L\(_2\).
(Vi) Evaluate D\(^2\): d\(^2\) and D\(^2\) - d\(^2\).
(vii) Repeat the procedure for four other values of D = 130cm, 100 cm, 90 cm and 80 cm. in each case.evaluate D\(^2\); d\(^2\) and D\(^2\) - d\(^2\).
(viii) Tabulate the result
(ix) Plot a graph with D\(^2\) - d\(^2\) on the vertical axis and D on the horizontal axis.
(x) Determine the r values of D axis and Determine the slopes, S, of the graph.
(xi) Evaluate k = \(\frac{s}{4}\)
(xii) State two precautions taken to ensure accurate results.
(bi) Distinguish between a virtual image and. plain image?
(ii) With the aid of a ray diagram, explain how a converging lens produces a Virtual image
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Slope = \(\frac{\Deltad^2/d^2}{\DeltaD^{-1}\) → \(frac{y_2 - y_1}{x_2 - x_1}\)
= \(\frac{0.4697 - 0.6638}{0.431 - 0.0254}\)
S = \(\frac{-0.1941}{0.0177}\) → -10,97
K = \(\frac{s}{4}\) → \(\frac{-10.97}{4}\)
= 2.74
Precautions:
(i) Lens was placed vertically on the lens holder. (ii) Avoided zero error in reading my metre rule.
(b)(ii) Differences between real and virtual images:
(i) Real image is formed on the screen while virtual image cannot be found on the screen. (ii) Real images are inverted while virtual images are erect.
Source: Myschool Past Questions Archive (Record #62350)