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Using y = A sin (wt + 0) Given y = 0.25 x 10\(^{-3}\)sin (500t - 0.025x) By comparing, w = 5.00 x 10\(^{2}\)rads\(^{-1}\)

No expanded working has been attached for this question yet. The verified answer is Option D.

No expanded working has been attached for this question yet. The verified answer is Option B.

V = \(\frac{\lambda}{T}\) : v = 330ms\(^{-1}\) \(\lambda\) = 1.65m T = ? 330 = 1.65 T = \(\frac{1.65}{330}\) = 0.005s

V = \(\frac{2d}{t}\) v = 340ms\(^{-1}\) t = 0.5s d= ? d = \(\frac{2d}{2} = \frac{340 \times 0.5}{2}\) = 85m

\(\Delta\) = \(\frac{\bigtriangleup\theta}{\delta} = \frac{80-20}{0.02}\) = 3.0 x 10\(^{3}\)km\(^{-1}\)

No expanded working has been attached for this question yet. The verified answer is Option A.

\(f_0\) = 40\(H_3\) 1st overtone = 2\(f_0\) = 80\(H_3\) 2nd overtone = 3\(f_0\) = 120\(H_3\) 3rd overtone = 4\(f_0\) = 160\(H_3\) 4th overtone = 5\(f_0\) = 200\(H_3\) \(\therefore\) Number of overtones between 40\(H_3\) and 180\(H_3\) = 3

A normal arrangement is an arrangement where the principal focus of objective coincides with the eyepiece so that the final image is at infinity

Only 'mass' is a fundamental quantity

AT resonance; \(X_L\) = \(X_c\) \(\therefore\) = \(V_L\) = \(V_c\) = 40V

Given amount remaining = \(\frac{1}{64}\) = \(\frac{1}{64} = \frac{1}{(2)^{6}}\) \(\therefore\) = \(\frac{120 \text {years}}{6}\) = 20 years \(\Rightarrow\) T\(\frac{1}{2}\) = 20 years

Vernier calipers are also used to measure the internal and external diameters of a tube

- Acceleration, a = \(\frac{\text{v}}{\text{t}}\) = \(\frac{25}{20}\) = 1.25ms\(^{-2}\) - Force, F = ma = 800 x 1.25 = 1,000N - Average power = Force \times average velocity = 1000 \(\times \frac{0 + 25}{2}\) = 12,500W = 1.25 x 10\(^4\) W

Mass is a measure of how much matter is in an object.