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Physics
WAEC / WASSCE 2022
Thermal Physics
Solution
State:
(a) The S.I. unit of the intensity of a blackbody radiation.
(b) Two features of the intensity-wavelength graph of a perfect blackbody at different temperatures.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) S.l unite for the intensity of a blackbody radiation = Wm-² OR Js\(^{-1}\)m-²
(b) Two features of the graph
i. The shape of the graph is non-symmetric.
ii. Peaks of the intensity have lower wavelengths/Peaks decrease with wavelength.
iii. The line joining the peaks have a negative gradient.
Source: Myschool Past Questions Archive (Record #63503)
Physics
WAEC / WASSCE 2022
Heat Energy & Temperature
Solution
Using venier calipers, which of the following readings gives the correct measurement for the length of a rod?
A
4.1 cm
B
4.13cm
C
125 cm
D
1254 cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Vernier calipers commonly used in industry provide a precision to 0.01 mm (10 micrometres), or 0.01cm or one thousandth of an inch.
Usually, it is the total length of the main scale. Vernier calipers, generally, have a range of 300 mm
300 millimeters equal 30.0 centimeters (300mm = 30.0cm).
Source: Myschool Past Questions Archive (Record #63416)
Physics
WAEC / WASSCE 2022
Heat Energy & Temperature
Diagram
Solution
The diagram above illustrates the trajectory of a fired missile from point P at 250 ms-1
If the missile point Q after 40 s, calculate the distance |PQ|
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
|PQ| = Range = Ux.T
= UT Cos\(\theta\)
= 250 x 40 Cos 42º
= 7431 m (7.4 km)
Source: Myschool Past Questions Archive (Record #63437)
Physics
WAEC / WASSCE 2022
Electricity and Magnetism
Solution
State three differences between magnetic and non-magnetic materials.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Magnetic materials Non-magnetic materials
They are attracted to/by magnets They are not attracted to/by magnets
The domains of the magnetic fields align The domains of the magnetic fields are randomly aligned
themselves in an orderly fashion.
They can be magnetized They cannot be magnetized
Source: Myschool Past Questions Archive (Record #63507)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Solution
(a)(i) State the law of inertia.
(ii) Use the law stated in (a)(I) to explain how wearing a safety belt in a moving vehicle could reduce the possibilities of severe injuries when the vehicle is involved in a collision.
(b)(I) Define the term moment of a force.
(ii) A uniform plank measures 2 m long from its ends point A to point B. If the weight of the plank is 54 N and it rests on a knife edge 0.50 m from end B and point A is supported by a vertical string so that AB balances horizontally:
i. Draw a force diagram for the arrangement;
ii. Determine the tension, T, in the string.
iii. Determine the force, F, acting on the knife edge
(c) State three differences between solid friction and viscosity
(d) State one method of increasing the velocity ration of a pulley system.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) (i) The Law of Inertia states that: A body continues in its state of rest or uniform linear motion unless acted upon by an external force to act otherwise.
(ii) Explanation of wearing safety: The safety belt acts as an external force that prevents a passenger from an otherwise forward motion after impact.
(b)(i)Mmoment of a force: The product of a force and the perpendicular distance from a reference point to the line of action of the force.
(b)(ii) Force diagram:
(ii) Determination of the tension, T, in the string;
Taking moment about the knife edge
Sum of clockwise moment = sum of anti-clockwise moment.
T x 1.5 = 54 x 0.5
\(\therefore\) T = 18 N
(ii) Determination of the force, F, acting the knife edge;
At equilibrium, the sum of upward forces = the sum of forces acting downward
T + F = 54
T = 18 N
18 + F = 54
F = 36 N
Solid friction
Viscosity
It occurs on solid surfaces
It occurs within fluids
It is independent of areas of surfaces on
It depends on the area of the surfaces in
It depends on the speed of motion of the surface in contact
It is independent of the speed of motion of the surfaces in contact
It is independent of temperature
It depends on the temperature
It depends on the normal reaction.
It is independent of normal reaction
(d)Increasing the number of pulleys
Source: Myschool Past Questions Archive (Record #63522)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Diagram
Solution
(a)(i) State Coulomb's law of electrostatics.
(ii) The electron and proton of a hydrogen atom are separated by a mean distance of 5.2 x 10\(^{-11}\)m.
Calculate the magnitude of the electrostatic force between the particles.
[e = 1.6 x 10\(^{-19}\) C, (4\(\pi\) \(\mathcal{E}_{0}\))\(^{-1}\) = 9.0 x 10\(^{9}\) mF\(^{1}\)]
(b) The diagram above shows a potential divider circuit. (see diagram above)
i. Show that V\(_{out}\) = V\(_{in}\) (\(\frac{R_{1}}{R_{1} + R_{2}})\)
ii. If \(\frac{V_{in}}{V_{out}}\) = 2.5 and \(R_2\) = 30\(\Omega\), calculate \(R_1\)
iii. Define the volt.
(c) Explain why wood is not suitable for use as the core of transformers.
(d) State one application for the cathode ray tube.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)(i) Coulomb's law of electrostatics
The electrostatic force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
(ii) Calculation of the magnitude of the electrostatic force
F = \(\frac{kq_{1}q_{2}}{d^{2}}\)
F = \(\frac{9.0 \times 10^{9} \times 1.6 \times 10^{-19} \times 1.6 \times 10^{-19}}{(5.2 \times 10^{-11})^{2}}\)
= 8.52 x 10\(^{-8}\) N
(b)(I) Proof of V\(_{out}\)
Let the current through the circuit be I
V\(_{in}\) = I(\(R_1\) + \(R_2\))
OR
I = \(\frac{V_{in}}{R_{1} + R_{2}}\)
V\(_{out}\) = I\(R_2\)
II. Calculation of \(R_1\);
V\(_{out}\) = V\(_{in}\)(\(\frac{R_{1}}{R_{1} + R_{2}}\))
OR
\(\frac{V_{out}}{V_{in}} = \frac{R_{1}}{R_{1} + R_{2}}\)
\(\frac{1}{2.5} = \frac{R_{1}}{R_{1} + R_{30}}\)
\(R_1\) = 20\(\Omega\)
(ii) The Volt The unit of potential difference between two points when one joule of work is done in taking one coulomb of charge between the points,
(c) Why wood is not suitable for use as the Core of transformers Wood is a non-magnetic material and would not provide magnetic coupling between the coils for electromagnetic induction.
(d) Applications of cathode ray tube
i. For studying alternating current waveform
ii. For measuring frequency/voltage/ reactance/power factor and resistance of an electronic device
iii. Used to monitor signals/check FM/AM characteristics
Source: Myschool Past Questions Archive (Record #63534)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Solution
(a) State one condition each necessary for the characteristics each of the following occurrences:
(i) Constructive interference of waves.
(ii) Total internal reflection.
(iii) Production of beats.
(b) In a resonance tube experiment using a tuning fork of frequency 256 Hz, the first position of resonance was 35 cm, the next position was 100 cm. Calculate the velocity of sound in air from the experiment.
(c)(i) State the three classifications of musical instalments
(ii) Give one example each of the classifications stated in (c)(i).
(d) Calculate the critical angle for light traveling from glass to air. [refractive index of glass = 1.5].
(e) The speed of sound in a medium at a temperature of 102 ^\circC is 240 m s\(^{-1}\). If the speed of sound in the medium is 3 10 m s\(^{-1}\). Calculate its temperature
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Conditions necessary for:
Constructive interference of waves
i. lt must involve at least two waves.
ii. Waves must vibrate in phase.
iii. The distance between the sources of the wave must be of the order of the wavelength.
Total internal reflection
i. The waves must travel from a denser medium to a less dense medium.
ii. The angle of incidence (in the denser medium) must be greater than the critical angle.
iii. It must involve two media of different optical densities.
Production of beats
1. The amplitude of the two interfering waves should be the same.
ii. The difference between the frequencies of interfering waves should be small.
iii. The two sources of waves must be sounded together.
(b) Calculation of velocity of sound in air
V = f\(\lambda\)
V = 2f(\(l_2\) - \(l_1\))
= 2 x 256(100 - 35)
= 33280 cm s\(^{-1}\)
= 332.80 m s\(^{-1}\)
(c)(i) Classification of musical instruments
i. Wind
ii. Stringed
iii. Percussion
(ii) Examples of classified instruments saxophone
I. Wind: flute, trumpet, pipe, organ,
iii. Stringed: piano, guitar, violin
iii. Percussion: piano, drum, bell, gong. xylophone
(d) Calculation of critical angle
\(\eta\) = \(\frac{1}{\text {Sin C}}\)
1.5 = \(\frac{1}{\text {Sin C}}\)
Sin C = 0.667
C = 41.80º
(e) Calculation of temperature
\(\frac{V_{1}}{\sqrt T_{1}} = \frac{V_{2}}{\sqrt T_{2}}\)
\(\frac{240} {\sqrt 375} = \frac {310} {\sqrt T_{2}}\)
240 \(\sqrt T_{2}\) = 310 x 19.36
\(\sqrt T_{2}\) = 625 K = 352 ºC
Source: Myschool Past Questions Archive (Record #63664)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Solution
(a) State two factors that affect the rate of evaporation of a liquid.
(b) Explain the term latent heal.
(c) Explain each of the following phenomena:
(i) On a dry day, water in a clay pot is cooler than water in a rubber container:
(ii) Cooking of food is faster in a pressure cooker than in an ordinary pot.
(d) A 40 V electric heater is used to supply a current of 12 A for 1400 seconds to a body mass of 1.5 kg at its melting point. The body melts and its temperature rises by 60^\circC in an extra 1.2 minutes, Calculate the:
(i) Latent heat of fusion of the body
(ii) Specific heat capacity of the body.
(e) State two differences between evaporation and boiling.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Factors affecting the rate
i. Surface area of the liquid (exposed surface area)
ii. Temperature of the liquid
iii. Wind/ drought.
iv. Humidity/ amount of water vapour
v. Nature of the liquid
vi. Air pressure
(b) Explanation of latent heat;
The energy needed to change the state of a substance without a change in temperature.
(c)(i) Water in a clay pot cooler than in a rubber container;
A clay pot has pores which allows evaporation to occur while a plastic container has no pores.
(ii) Pressure cooker cooks faster than ordinary pot;
Pressure cooker raises the pressure within it, which raises the temperature to/above the boiling point thus cooks faster.
(d)(i) Calculation of latent heat of fusion of the body
Ivt = mL
mL = 12 x 40 x 1400
= 6.72 x 10\^{5}\)j
(ii) Calculation of specific heat capacity of the body
C = \(\frac{Ivt}{m \bigtriangleup \theta}\)
= \(\frac{12 \times 40 \times 72}{1.5 \times 60}\)
= 384 jkg\(^{-1}\) K\(^{-1}\)
(e) difference between evaporation and boiling
Evaporation
Boiling
It takes place at the surface of the liquid
It occurs throughout the entire volume of the liquid
It takes place across all temperatures
It takes place at specific temperatures
It produces a cooling effect
It produces no cooling effect
It is wind aided
It is not wind aided
Source: Myschool Past Questions Archive (Record #63692)
Physics
UTME / JAMB 2022
Heat Energy & Temperature
Solution
The secondary pigments consist of?
A
blue, green, and violet
B
yellow, green, and magenta
C
magenta, yellow, and cyan
D
red, green, and blue
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The primary colors of pigment are red, blue, and green.
Mixing these primary colors of pigment gives us the three secondary colors:
red+blue=magenta, red+ green = yellow, and blue + green = cyan
Source: Myschool Past Questions Archive (Record #64927)
Physics
UTME / JAMB 2022
Waves and Optics
Solution
A person standing waist-deep in a swimming pool appears to have short legs because of light?
A
diffraction
B
refraction
C
reflection
D
interference
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The refractive index of water is greater than that of air.
So, A person legs appear to be short while standing in the tank due to refraction.
Source: Myschool Past Questions Archive (Record #64929)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Solution
(a)(i) What is meant by the term artificial radioactivity?
(ii) Complete the table below
Emission
Nature
Charge
Ionizing
High speed electron
Moderately ionizing
Neutral
Negligible ionizing ability
Alpha particles
Positive
(b) In an x-ray tube, an electron is accelerated from rest towards a metal target by a 30 kV source. Calculate the kinetic energy of the electron. [e=1.6 x 10\(^{-19}\)C]
(c) The table below shows the frequencies of radiations incident on a certain metal and the corresponding kinetic energies of the photoelectrons.
Frequency x 10\(^{14}\)(Hz)
6.8
8.0
9.2
10.0
11.0
Kinetic energy x 10\(^{-19}\)(j)
0.8
1.6
2.4
2.9
3.8
(i) Plot a graph of kinetic energy, K.E, on the vertical axis and frequency, f, on the horizontal axis starting both axes from the origin (0,0).
(ii) From the graph, determine the:
i. Planck's constant;
ii. Threshold frequency of radiations;
iii. Work function of the metal.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a)() Meaning of artificial radioactivity;
The process by which a stable nucleus is bombarded with a neutron to make it unstable and so disintegrates/decays with the emission of particles/radiation and. energy.
Emission
Nature
Charge
Ionizing
Beta (\(\beta\))
High speed electron
Negative
Moderately ionizing
Gamma (\(\gamma\))
Electro-magnetic radiation
Neutral
Negligible ionizing ability
Alpha particles
Helium nucleus
Positive
Highly ionizing
(b) Calculation of kinetic energy
K.E = eV
= 1.6 x 10\(^{-19}\) x 30 x 10\(^{3}\)
= 4.8 \times 10\(^{-15}\)J
(c)(i) graph of K.E versus f
i. Both axes correctly distinguished
ii. Reasonable scale on both axes
(ii) (I) Planck's constant. h = slope of the graph Slope
i. \(\bigtriangleup\)K.E and \(\bigtriangleup\)f correctly determined
ii. \(\frac{\bigtriangleup K.E}{\bigtriangleup f}\) corectly determined and recorded within range.
(II) Threshold frequency, \(f_0\) .
The intercept on the horizontal or frequency axis.
(III) Threshold frequency, \(W_o\)
Negative intercept on K.E axis.
Source: Myschool Past Questions Archive (Record #63727)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Diagram
Solution
You are provided with a metre rule, a weight hanger, slotted masses, M, a piece (if string, a weighing balance and a knife edge. Use the diagram above as a guide to perform the experiment.
(i) Using the weighing balance, determine and record the mass, \(M_o\), of the unloaded metre rule.
(ii) Determine and record the mass, m, of the weight hanger.
(ii) Suspend the metre rule horizontally on the knife edge. Adjust the knife edge to a point G on the metre rule where it balances horizontally.
(iv) Record the distance, d = AG.
(v) Suspend the weight hanger securely at a point, P, on the metre rule such that AP= 5 cm. Keep the hanger at this point throughout the experiment
(vi) Add a mass, M = 20 g to the hanger, adjust the knife edge to a point K on the metre rule such that it balances horizontally as shown in the diagram above.
(vii) Determine and record the distance z = AK.
(vii) Record M and evaluate y - (z - 5), x - (d - z] and v = \(\frac{x}{y}\)
(ix) Repeat the experiment for M = 40 g, 60 g, 80 g and 100 g. In each case, evaluate y, x and v.
(x) Tabulate the results.
(xi) Plot a graph with M on the vertical axis and v on the horizontal axis, sinning both axes from the origin (0,0).
(xii) Determine the slope, s, of the graph.
(xii) Determine the intercept, c, on the vertical axis.
(xiv) State two precautions taken to ensure accurate results.
(b) (i) Under what condition is an object said to be in a stable equilibrium
(ii) Auniform beam of weight 50 N has a body of weight 100 N hung at one end of it. If the beam is 12 m long, determine the distance of a support from a 100 N body for it to balance horizontally.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) OBSERVATIONS
(i) Value of \(M_0\) correctly determined and recorded to at least 1 d.p in grammes
(ii) Value of m correctly determined and recorded to at least 1 d.p in grammes
(iii) Value of d correctly read and recorded to at least 1 d.p in cm
(iv) Five values of M correctly recorded in grammes
(v) Five values of Z = AK correctly read and recorded to at least1 d.p in cm and in trend.
Trend: As M increases Z decreases.
(vi) Five values of y = (Z - 5) correctly evaluated and recorded.
(vii) Five values of x = (d - Z) correctly evaluated and recorded
(vii) Five values of v = \(\frac{x}{y}\) correctly evaluated and recorded to at least 3 d.p
(ix) Composite table showing at least M, Z,y, x and v.
(b)(i) Condition for a body to be in stable
- The algebraic sum of all external forces on the object is zero
OR
- The algebraic sum of all external torques from the external forces acting on the object is zero.
OR
- The sum of clockwise moments about a point in the object is equal to the sum of anticlockwise moment about the same point.
OR
- The algebraic sum of all moments about a point on the object is zero.
(ii) If the distance is y,
100y = 50(6 - y)
100y = 300 - 50y
150y = 300
y = 2m
Source: Myschool Past Questions Archive (Record #63747)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Diagram
Solution
You are provided with a loaded boiling tube with a centimeter scale fixed inside it, a transparent vessel filled with water, standard masses 2 g, 5g and 10 g, and a slide vernier caliper. Use the diagram above as a guide to perform the experiment.
(i) Use the slide vernier caliper to measure and record the external diameter, D, of the boiling tube.
(ii) Evaluated A = 0.25\(\pi\)D\(^{2}\), where \(\pi\) = 3.14.
(iii) Place the loaded boiling tube gently in the water in the transparent vessel such that it floats vertically.
(iv) Read and record the depth of immersion, y, from the zero mark of the scale fixed inside, the boiling tube.
(v) Add a mass, m = 2g, to the boiling tube. Read and record the new depth of immersion, y, from the zero mark of the scale.
(vi) Evaluate h = (y - \(y_0\)), log h and log m.
(vii) Repeat the experiment for four other values of m = 5g, 7g, 10 g, and 12g. In each case, record y and evaluate h, log h, and log m.
(viii) Tabulate the results.
(ix) Plot a graph with log m on the vertical axis and log h on the horizontal axis starting both axes from the origin (0,0).
(b)(i) State in full the law on which the experiment in (a) is based.
(ii) A uniform cylindrical rod is 0.63 m long and it has a cross-sectional area of 0.1 m\(^{2}\). Calculate the depth of immersion of the rod if it floats vertically in a liquid of relative density 1.26. [density of rod =720 kg m\(^{-3}\), g = 10 m s\(^{-2}\)].
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) OBSERVATIONS
(i) Value of D correctly measure and recorded to at least 2 d.p in cm
(ii) Value of A = 0.25\(\pi\)D\(^{2}\) correctly evaluated
(iii) Value of \(y_0\) correctly read and recorded to at least 1 d.p in cm.
(iv) Five values of m correctly recorded in grammes.
(v) Five values of y correctly read and recorded to at least 1 d.p in cm and in trend.
(vi) Five values of h = (y - yo) correctly evaluated.
(vii) Five values of log h correctly evaluated to at least 3 d.p
(viii) Five values of log m correctly evaluated to 3d.
(ix) Composite table showing at least m, y, h, log h and log m.
(b)(i) The Law of Flotation;
A floating body displaces its own weight of fluid in which it floats.
(ii) Weight of rod = 0.63 x 0.1 x 720 x 10 = 453.6
Let y be the depth of immersion
\(\therefore\) Weight of water displaced
= (0.1y) x 1.26 x 1000 x 10
1260y = 453.6 y=453.6=9.36
= 1260y = 453.6
y = \(\frac{453.6}{1260}\) = 9.36
Source: Myschool Past Questions Archive (Record #63754)
Physics
WAEC / WASSCE 2022
Mechanics and Properties of Matter
Diagram
Solution
You are provided with a battery of e.m.f, E, a standard resistor, R, of resistance 2 \(\Omega\), a key, K, an ammeter, A, a jockey, J, a potentiometer, UV, and some connecting wires.
(i) Measure and record the emf, E, of the battery.
(ii) Set up the circuit as shown in the diagram above with the key open.
(iii) Place the jockey at the point, U, of the potentiometer wire. Close the key and record the reading, i, of the ammeter.
(iv) Place the jockey at a point T on the potentiometer wire UV such that d = UT = 30.0 cm.
(v) Close the circuit, read and record the current, I, on the ammeter,
(vi) Evaluate I\(^{1}\).
(vi) Repeat the experiment for four other values of d = 40.0 cm, 50.0 cm, 60.0 cm and 70.0 cm. In each case, record I and evaluate I\(^{1}\).
(vii) Tabulate the results
(ix) Plot a graph with d on the vertical axis and I on the horizontal axis stalling both axes from the origin (0,0).
(x) Determine the slope, s, of the graph.
(xi) From the graph determine the value \(I_1\), of I when d = 0. (ci) Given that=s, calculate 8.
(xii) State two precautions taken to ensure accurate results.
(xii) Given that \(\frac{E}{\delta}\) = s, calculate \(\delta\).
(b)(i) Write down the equation that connects the resistance, R, of a wire and the factors on which it depends. State the meaning of each of the symbols.
(ii) An electric fan draws a current of0.75 A in a 240 V circuit. Calculate the cost of using, the fan for 10 hours if the utility rate is $ 0.50 per kWh.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) OBSERVATIONS
(i) Value of E correctly read and recorded to at least 1 d.p in volts.
(ii) Value of i correctly read and recorded to at least 1 d.pin amperes.
(iii) Five values of d correctly determined and recorded to at least 1 d.p in cm.
(iv) Five values of I correctly read and recorded to at least 1 d.p in amperes and in trend.
Trend; As d increases, I decreases
(v) Five values of I\(^{1}\) correctly evaluated to at least 3 s.f.
(vi) Composite table showing at least d, I, and I\(^{-1}\).
(ii) P = IV
Power P = \(\frac{240 \times 0.75}{100}\)
0.18kw
Energy consumed in 10hr = 0.18 x 10
= 1.8kWh
Cost of energy = 1.8 x 0.5 = $0.9
OR
Cost of energy = \(\frac{\text {P x cost x time}}{100}\)
\(\frac{0.7 \times 240 \times 10}{1000}\)
= $0.9
Source: Myschool Past Questions Archive (Record #63755)
Physics
UTME / JAMB 2022
Mechanics and Properties of Matter
Solution
Water is not a good thermometric liquid because it?
A
expands unevenly between 0 ºC and 4 ºC
B
maintains fixed density
C
has low freezing point
D
wets glass
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Water is most anomalous at low temperatures, with a remarkable density maximum at 4^\circC.
water is not used as a thermometric liquid because it has low thermal expansivity, high specific capacity, high vapor pressure and wets glass.
Source: Myschool Past Questions Archive (Record #64945)