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In Faradays law of electrolysis M = It = Q Where M is the mass of substance deposit . Q is the quantity of charge. A graph of m against Q is a straight line passing through the origin with slope equal to the electrochemical equivalent.Z

1/R = 1/R1 + 1/R2 = 1/3 + 1/6 = 3/6 ∴ R = 6/3 = 2 E = I(R + r) = 4(2 + 0) = 8v

Power supplied = I\(^2\) R = 20\(^2\) X 1 = 400 W Power dissipated = IV = 20 X 220 = 4400 W (Power supplied)/Power dissipated = 4400 W / 400 W = 11 / 1 or 11 : 1

The resistors are in series ∴ Reff = R1 + R2 + ..... = 4 + 4 + 4 + 4 + 4 + 4 = 24 \Omega

The lostvolt is the potential drop in a cell due to internal resistance.

Earthing is used to protect you from an electric shock. It does this by providing a path (a protective conductor) for a fault current to flow to earth. It also causes the protective device (either a circuit-breaker or fuse) to switch off the electric current to the circuit that has the fault.

Q = charge i = current t = time in sec Mass(M1) 3hours to sec 60*60*3= 10800 Mass(M2) 10hours to sec 60*60*10 = 36,000 36,000 * 3.0A = 108,000 if it takes 10800 current to discharge 1g how much will it take 108000 10800---->1 108000---x = 108000/10800 =10

According to Faraday's Law, the mass of the substance deposited is directly proportional to the time for which the current flows, assuming a constant current. Therefore, the graph should show a linear increase in mass over time, which corresponds to option A

Voltage across 5\Omega resistor = IR = 2 \times 5 = 10V Since voltage in a parallel connection is the same, voltage across 10\Omega is also 10V Current flowing across the 10\Omega resistor I = V/R = 10/10 Current I= 1A Total current flowing = 2 + 1 = 3A Voltage across 20\Omega resistor = IR = 3 \times 20 = 60V

V= i \times \(_l\) X\(_l\) = inductive reactance → 50 I = current → 0.05A V = 0.05 \times 50 V = 2.5volt

Total resistance = resistance in series + resistance in parallel = 4 + (\(\frac{4 \times 4}{4 + 4}\)) = 6\(\Omega\) Total power drawn = \(\frac{V^2}{\text{R}}\) = \(\frac{12^2}{6}\) = 24W

Current = \(\frac{\text{Voltage}}{\text{Resistance}}\) I\(_1 = \frac{10}{2}\) = 5A I\(_2 = \frac{10}{1}\) = 10A I\(_3 = \frac{20}{3}\) = 6.67A I\(_4 = \frac{20}{2}\) = 10A I\(_5 = \frac{20}{1}\) = 20A

Resistance in series will be given as R = 10+10 → 20 Resistance in parallel will be given as \(\frac{1}{R}\) = \(\frac{1}{10}\) + \(\frac{1}{10}\) \(\frac{1}{R}\) = \(\frac{2}{10}\) → \(\frac{1}{R}\) = \(\frac{1}{5}\) Resistance in parallel = 5 Total resistance = 20 + 5 → 25ohms