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Chemistry
WAEC / WASSCE 2022
Acids, Bases, and Salts
Solution
Consider the following reaction equation:
CaO + Si\(O_2\) ------> CaSi\(O_3\)
Silicon(IV) oxide is acting as
A
a basic oxide
B
a reducing agent
C
an acidic oxide
D
an oxidizing agent
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Silicon dioxide is an acidic oxide. It will react with strong bases to form silicate salts, Si\(O_2\) is acidic oxide because Si is non-metal. Oxides of non-metals are acidic in nature.
Source: Myschool Past Questions Archive (Record #65809)
Chemistry
WAEC / WASSCE 2022
Acids, Bases, and Salts
Solution
Which of the following acids would form normal salt only?
A
Tetraoxosulphate(VI) acid
B
Trioxonitrate(V) acid
C
Tetraoxophosphate(V) acid
D
Trioxosulphate(IV) acid
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Normal salts are formed when all the replaceable hydrogen ions in the acid have been completely replaced by metallic ions. Trioxonitrate(V) acid, HNO\(_3\) has only one replaceable hydrogen ion(monobasic), that can be replaced by a metallic ion or ammonium ion. Thus, it cannot form an acidic nor basis salt or any other type aside normal salt.
Source: Myschool Past Questions Archive (Record #65810)
Chemistry
WAEC / WASSCE 2022
Acids, Bases, and Salts
Solution
Graphite is used as a dry lubricant due to the presence of
A
mobile electrons
B
free electrons
C
octahedral structures
D
layered structures
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Graphite is an excellent dry lubricant. This is because its layered structure allows one layer to slide over another easily. It is non-volatile and not sticky.
Source: Myschool Past Questions Archive (Record #65812)
Chemistry
WAEC / WASSCE 2022
Kinetics, Energetics and Equilibrium
Solution
Which of the following statements about an equilibrium system is correct?
A
Forward and backward reactions occur
at the same rate
B
The concentrations of reactants must
equal that of the products
C
The concentrations of, reactants and products can be changed by adding a catalyst,
D
The concentrations of reactants and
products are not affected by a change in temperature
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Equilibrium is a state of a system where there is no observable change in the properties of the system with respect to time
Source: Myschool Past Questions Archive (Record #65814)
Chemistry
WAEC / WASSCE 2022
Kinetics, Energetics and Equilibrium
Solution
Consider the following reaction equation
\(N_2\)(g) + 3H\(_{2(g)}\) ⇌ 2NH3(g) ∆H = -92kJ
Increasing the temperature of the reaction would
A
shift the equilibrium to the right
B
increase the yield of ammonia
C
decrease the amount of hydrogen
D
decrease the yield of ammonia
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
In this case, an increase in in temperature will cause the equilibrium position to shift to the left thereby decreasing the yield of ammonia.
Source: Myschool Past Questions Archive (Record #65815)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
When air in a syringe is compressed such that there is no change in temperature, the
A
air liquefies
B
pressure increases
C
intermolecular space increases
D
density decreases
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Since the temperature of air remain constant.So, it is a isothermal process.
PV=K
This eq. shows that on increasing pressure, the volume gets reduced and vice-versa.
Since the syringe is slowly compressed, volume is decreasing.
Therefore, the pressure inside the syringe will increases because the molecules now hit the syringe walls more frequently.
Source: Myschool Past Questions Archive (Record #65816)
Chemistry
WAEC / WASSCE 2022
Matter & Separation Techniques
Solution
Which of the following statements about liquids is/are true?
I. Liquids maintain their volume at constant temperature.
II. Liquids have fixed shape
III. Liquids do not diffuse
IV. Change in pressure affects volume of liquids
A
I only
B
IV only
C
I and IV only
D
II and III only
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure
Source: Myschool Past Questions Archive (Record #65817)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
A hydrogen chloride gas reacted with oxygen gas to yield water and chlorine gas. The mole ratio of the hydrogen chloride gas to water is
A
1:3
B
2:1
C
3:1
D
4:1
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
4HCl + \(O_2\) -- 2C\(l_2\) + 2\(H_2\)O
4:2 = 4/2
2:1
Source: Myschool Past Questions Archive (Record #65818)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{3}\) cylinder?
[R=0.082 atm dm\(^{-3}\) mol\(^{-1}\) K\(^{-1}\)]
A
0.32
B
1.52
C
3.13
D
31.25
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
P = 10atm, T= 320K, V= 8.2dm\(^{3}\)
PV =nRT
n = P * V/R * T
10 * 8.2/0.082 * 320
= 82/26.24
n = 3.13
Source: Myschool Past Questions Archive (Record #65819)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
If 50 cm\(^{3}\) of a saturated solution of KN\(O_3\) at 40 ^\circC contained 5.05 g of the salt, its solubility at the same temperature would be
[KN\(O_3\) = 101]
A
1.0 mol dm\(^{-3}\)
B
1.5 mol dm\(^{-3}\)
C
2.0 mol dm\(^{-3}\)
D
5.0 mol dm\(^{-3}\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
V= 50cm\(^{3}\)
Mass= 5.05g
Relative molecular mass of KN\(O_3\) = (39+14+(3*16)) = 101
Convert 50cm\(^{3}\) to dm\(^{3}\) which is
1000cm³ = 1dm\(^{3}\)
50cm³ = 50*1/1000
= 0.05dm\(^{3}\)
Moles = mass/ molar mass
= 5.05/101 =0.05mole
Solubility= mole/volume
Solubility=0.05mol/0.05dm\(^{3}\)
Solubility=1.0mol/dm_\(^{3}\)
Source: Myschool Past Questions Archive (Record #65820)
Chemistry
WAEC / WASSCE 2022
Matter & Separation Techniques
Solution
Which of the following elements would displace copper from a solution of copper ions?
A
silver
B
gold
C
lead
D
mercury
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The reactivity series allows us to predict how metals react. A more reactive metal displaces a less reactive metal from a compound. Lead is more reactive metal than copper hence, copper is displaced from copper solution by lead.
Source: Myschool Past Questions Archive (Record #65872)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
What is the percentage composition of carbon
in Ca(HCO3)\(_{2}\) ?
[ Ca = 40.0, 0= 16.0, C = 12.0, H= 1.0]
A
22.2%
B
14.8%
C
7.4%
D
3.7%
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
. % of C in Ca(HCO3)2
Molar mass of Ca(HCO3)2 = 40+(1+12+(16*3))2
=40+(13+48)2
=40+122
=162
C/Ca(HCO3)2 x 100
=12 * 2/162 * 100
=14.8%
Source: Myschool Past Questions Archive (Record #65873)
Chemistry
WAEC / WASSCE 2022
Atomic Structure and Periodic Table
Solution
Which of the following bond types is intermolecular?
A
Covalent bond
B
Hydrogen bond
C
Ionic bond
D
Metallic bond
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Hydrogen bond is an intermolecular force which arises when hydrogen is covalently linked to elements like nitrogen, oxygen and fluorine.
Source: Myschool Past Questions Archive (Record #65874)
Chemistry
WAEC / WASSCE 2022
Atomic Structure and Periodic Table
Solution
The maximum number of covalent bonds formed by nitrogen is
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Nitrogen has three unpaired electrons and one lone pair of electrons; therefore, it can form three covalent bonds and one coordinate bond. E.g ammonium ion.
Source: Myschool Past Questions Archive (Record #65875)
Chemistry
WAEC / WASSCE 2022
Stoichiometry & Mole Concept
Solution
The IUPAC name of the compound CH3CH(CH3)CHCH2 is
A
2 - methyl but - 1 - ene
B
2 - methyl but - 2 - ene
C
3 - methyl but - 1 - ene
D
3 - methyl but - 2 - ene
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
- Recognise the functional group in the compound. This will determine the suffix of the name
- Find the longest continuous carbon chain that contains the functional group (it won't always be a straight chain) and count the number of carbon atoms in this chain. This number will determine the prefix (the beginning) of the compound's name
- Number the carbons in the longest carbon chain (Important: If the molecule is not an alkane (i.e. has a functional group) you need to start numbering so that the functional group is on the carbon with the lowest possible number). Start with the carbon at the end closest to the functional group.
- Look for any branched groups:
Name them by counting the number of carbon atoms in the branched group and referring to Table 4.6, these groups will all end in -yl.
Note the position of the group on the main carbon chain. If there is more than one of the same type of branched group then both numbers must be listed (e.g. 2,4 -) and one of the prefixes listed in Table 4.7 must be used. Important: If the molecule is an alkane the branched group must be on the carbon with the lowest possible number.
The branched groups must be listed before the name of the main chain in alphabetical order (ignoring di/tri/tetra).
If there are no branched groups this step can be ignored.
- For the alkyl halides the halogen atom is treated in much the same way as branched groups:
To name them take the name of the halogen atom (e.g. iodine) and replace the -ine with -o (e.g. iodo)
Give the halogen atom a number to show its position on the carbon chain. If there is more than one halogen atom the numbers should be listed and a prefix should be used (e.g. 3,4-diiodo- or 1,2,2-trichloro-). See Table 4.7 for a list of the prefixes.
The halogen atoms must be listed before the name of the main chain in alphabetical order (ignore di/tri/tetra).
If there are no halogen atoms this step can be ignored.
- Combine the elements of the name into a single word in the following order:
branched groups/halogen atoms in alphabetical order (ignoring prefixes)
prefix of main chain
name ending according to the functional group and its position on the longest carbon chain.
Source: Myschool Past Questions Archive (Record #65876)