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Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
Ethanol could be prepared in the laboratory by
A
reduction of ethanoic acid
B
oxidation of primary alkanol
C
oxidation of alkenes
D
hydration of ethene
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Ethanol (C\(_2\)H\(_5\)OH) can be prepared in the laboratory by the hydration of ethene (C\(_2\)H\(_4\)). This process involves an acid-catalyzed addition reaction where water (in the form of steam) is added across the double bond of ethene in the presence of a concentrated acid catalyst, such as phosphoric(V) acid (H\(_3\)PO\(_4\)) or sulphuric acid (H\(_2\)SO\(_4\)).
Source: Myschool Past Questions Archive (Record #77135)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
Alkali metals are good conductors of heat and electricity because they
A
contain delocalised electrons
B
are found in the d-block
C
have vibrating ions
D
are all metals
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Alkali metals (Group 1 elements) have a single valence electron in their outermost shell. In a metallic lattice, these valence electrons are weakly held by the nucleus and become delocalised, meaning they are free to move throughout the entire structure.
Source: Myschool Past Questions Archive (Record #77136)
Chemistry
WAEC / WASSCE 2025
Kinetics, Energetics and Equilibrium
Solution
In a chemical reaction, \DeltaH is positive when
A
ΔH\(_{product}\) > ΔH\(_{reactants}\)
B
ΔH\(_{product}\) < ΔH\(_{reactants}\)
C
ΔH\(_{product}\) = ΔH\(_{reactants}\)
D
ΔH\(_{product}\) = 0
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
In a chemical reaction, \DeltaH(change in enthalpy) is positive when the reaction is endothermic, meaning the system absorbs heat from its surroundings. i.e \DeltaH\(_{product}\) must be greater than \DeltaH\(_{reactant}\).
Source: Myschool Past Questions Archive (Record #77137)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
How many pi-bond(s) is/are present in propene?
A
three
B
six
C
two
D
one
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Propene (C\(_3\)H\(_6\)) is an alkene that contains one carbon-carbon double bond (C=C) and one carbon-carbon single bond (C-C).
According to bonding rules:
A single bond consists of exactly one sigma (σ) bond.
A double bond consists of one sigma (σ) bond and one pi (\pi) bond.
Because propene has only one double bond in its structure (CH\(_2\)=CH-CH\(_3\)), it contains exactly one pi bond.
Source: Myschool Past Questions Archive (Record #77138)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
Which of the following compounds would readily undergo addition reaction?
A
ethane
B
butene
C
ethanol
D
benzene
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Addition reactions typically occur in unsaturated hydrocarbons, which contain at least one double or triple bond between carbon atoms.
As an alkene, butene contains a carbon-to-carbon double bond (C=C). This double bond can break (specifically the pi bond), allowing new atoms or groups of atoms to attach to the carbon atoms, resulting in a single saturated product. Common examples include hydrogenation (adding H\(_2\)) and halogenation (adding Cl\(_2\) or Br\(_2\))
Source: Myschool Past Questions Archive (Record #77139)
Chemistry
WAEC / WASSCE 2025
Stoichiometry & Mole Concept
Solution
The number of moles of KOH present in 200cm\(^3\) of 5.6 g dm\(^{-3}\) solution is [KOH = 56 g mol\(^{-1}\)]
A
2.01
B
1.12
C
0.02
D
0.01
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Given:
Volume, V = 200 cm\(^3\)
Concentration, C = 5.6 g/dm\(^3\)
Molar mass of KOH, M = 56 g/mol
Number of moles, n = \(\frac{CV}{1000}\)
But because mass concentration was given in g/dm\(^3\) instead of molar concentration (mol/dm\(^3\)) to enable us calculate the number of moles, we'll have to convert concentration from mass to molar using the relationship below:
Molar concentration (mol/dm\(^3\)) = \(\frac{mass concentration}{Molar Mass}\)
= \(\frac{5.6}{56}\) = 0.1 mol/dm\(^3\)
Now, we can find the number of moles using, Number of moles, n = \(\frac{0.1 X 200}{1000}\) = 0.02 mole
The correct answer is option C
Source: Myschool Past Questions Archive (Record #77140)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
A covalent hydride which does not exist as a gas at room temperature is
A
H\(_2\)O
B
BH\(_3\)
C
HCl
D
H\(_2\)S
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Water is the only covalent hydride in the list that is a liquid at room temperature due to intermolecular hydrogen bonding. Oxygen is highly electronegative and small in size, allowing it to form strong hydrogen bonds between molecules. These forces are much stronger than the simple van der Waals or dipole-dipole interactions found in the other hydrides, resulting in a higher boiling point that keeps water in the liquid state at standard room conditions.
Source: Myschool Past Questions Archive (Record #77141)
Chemistry
WAEC / WASSCE 2025
Acids, Bases, and Salts
Solution
In the electrolysis of dilute hydrochloric acid at the anode
A
Oxygen gas is given off
B
hydrogen gas is given off
C
chlorine gas is given off
D
hydrogen chloride gas is given off
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
In the electrolysis of dilute hydrochloric acid (HCl), two anions are present at the anode: chloride ions(Cl\(^-\)) and hydroxide ions (OH\(^-\)) from water. According to the electrochemical series, hydroxide ions are more easily discharged than chloride ions when the solution is dilute. Therefore, the (OH\(^-\)) ions undergo oxidation to produce oxygen gas (O\(_2\)) and water.
Source: Myschool Past Questions Archive (Record #77142)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
In which of the following arrangements are the ions arranged in decreasing order of ionic size?
A
F\(^-\),Na\(^+\), Mg\(^{2+}\), Al\(^{3+}\)
B
Na\(^+\), Mg\(^{2+}\), Al\(^{3+}\),F\(^-\)
C
Al\(^{3+}\), Na\(^+\), Mg\(^{2+}\), F\(^-\)
D
Al\(^{3+}\), Mg\(^{2+}\), Na\(^+\), F\(^-\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The ions F\(^−\),Na\(^+\), Mg\(^{2+}\), Al\(^{3+}\) are isoelectronic species, meaning they all have the same number of electrons (10 electrons). For isoelectronic ions, the ionic size is determined by the nuclear charge (number of protons). As the number of protons increases, the attraction between the nucleus and the electrons becomes stronger, pulling the electrons closer and decreasing the ionic radius.
Order of Protons:
F\(^−\) = 9 protons (Lowest charge → Largest size
Na\(^+\)= 11 protons
Mg\(^{2+}\)=12 protons
Al\(^{3+}\)= 13 protons (Highest charge → Smallest size)
Therefore, the decreasing order of ionic size is F\(^−\), Na\(^+\), Mg\(^{2+}\), Al\(^{3+}\)
Source: Myschool Past Questions Archive (Record #77143)
Chemistry
WAEC / WASSCE 2025
Stoichiometry & Mole Concept
Solution
The filter in a cigarette reduces the amount of nicotine inhaled by
A
adsorption
B
absorption
C
burning
D
evaporation
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The cigarette filter reduces nicotine levels through adsorption, a surface phenomenon where nicotine molecules (the solute) from the smoke (mobile phase) adhere to the surface of the filter material (stationary phase).
Source: Myschool Past Questions Archive (Record #77144)
Chemistry
WAEC / WASSCE 2025
Stoichiometry & Mole Concept
Solution
If 25cm\(^3\) of a saturated solution contains 0.02 moles of the solute, determine the solubility of the solute.
A
5.0 X 10\(^{-4}\) mol dm\(^{-3}\)
B
0.8 mol dm\(^{-3}\)
C
0.4 mol dm\(^{-3}\)
D
5.0 X 10\(^{-2}\) mol dm\(^{-3}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Solubility in this context refers to the molar concentration of the saturated solution.
Given:
Volume of Solution = 25 cm\(^3\)
Number of moles of solute, n = 0.02 mole
Solubility = ?
Solubility = \(\frac{n X 1000}{Volume of solvent}\)
= \(\frac{0.02 X 1000}{25}\) = 0.8 moldm\(^{-3}\)
Source: Myschool Past Questions Archive (Record #77145)
Chemistry
WAEC / WASSCE 2025
Acids, Bases, and Salts
Solution
Biotechnology is applied in the following processes except
A
baking of bread
B
production of wine
C
production of antibiotics
D
manufacturing of soap
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Biotechnology is defined as the use of living organisms or their components to create products or services.
Soap is traditionally made through a purely chemical process called saponification, which involves reacting fats or oils with a strong base (like sodium hydroxide). This process does not typically require the use of living cells or biological systems.
Source: Myschool Past Questions Archive (Record #77146)
Chemistry
WAEC / WASSCE 2025
Stoichiometry & Mole Concept
Solution
The percentage by mass of water in Na\(_2\)CO\(_3\).10H\(_2\)O is [ Na\(_2\)CO\(_3\).10H\(_2\)O = 286, H\(_2\)O = 18 ]
A
68.4%
B
62.9%
C
9.7%
D
6.3%
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Given:
mass of water = 18 ; but there are 10 moles of H\(_2\)O = 10 x 18 = 180
mass of Na\(_2\)CO\(_3\).10H\(_2\)O= 286
.: Percentage by mass of water = \(\frac{mass of water}{mass of Na{_2}CO{_3}.10H{_2}O}\) x 100
= \(\frac{180}{286}\) X 100
= 62.9%
Source: Myschool Past Questions Archive (Record #77147)
Chemistry
WAEC / WASSCE 2025
Acids, Bases, and Salts
Solution
Which of the following conditions are necessary for the preparation of alkanoates from alkanols and alkanoic acids?
A
Water and NaOH
B
Conc. H\(_2\)SO\(_4\) and heat
C
NaOH and heat
D
Water and aqueous HCl
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The chemical reaction illustrated in the question above is an esterification reaction. Esterification reaction is the reaction between an alkanol (alcohol) and an alkanoic acid (carboxylic acid) in the presence of an acid catalyst forms an ester (alkanoate) and water. To produce alkanoates (esters) from alkanols and alkanoic acids, you need to perform esterification, which requires a concentrated acid catalyst (like H\(_2\)SO\(_4\)) and heat.
Source: Myschool Past Questions Archive (Record #77148)
Chemistry
WAEC / WASSCE 2025
Atomic Structure and Periodic Table
Solution
All the following compounds are covalent except
A
NO\(_2\)
B
SO\(_3\)
C
SO\(_2\)
D
KNO\(_3\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
KNO\(_3\) (Potassium Nitrate) is primarily an ionic compound. It consists of a metal cation (K\(^+\)) and a polyatomic non-metal anion (NO\(_3\)). While covalent bonds exist within the nitrate ion itself (NO\(_3\)\(^-\)), the overall structure is held together by ionic bonds.
Source: Myschool Past Questions Archive (Record #77149)