Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 541–555 of 1709 verified questions
Sort by:
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
An object of mass 5.0 kg moves with a velocity of 10ms-1. Calculate its momentum.
A
50.0 kgms-1
B
15.0 kgms-1
C
2.0 kgms-1
D
0.5 kgms-1
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Momentum = MV
= 5 x 10 = 50
Source: Myschool Past Questions Archive (Record #35438)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
A
0.75m
B
2.25m
C
8.22m
D
15.00m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S = U\(\sqrt{\frac{2h}{g}}\)
= 15\(\sqrt{\frac{2 \times 1.5}{10}}\)
= 8.22m
Source: Myschool Past Questions Archive (Record #35440)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
Which of the following assumptions is not valid for an ideal gas ?
A
molecules of a particular gas are identical
B
molecules moves freely throughout the volume of the container
C
force of attraction between molecules is negligible
D
molecules move at constant speed between collisions
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
In an ideal gas, molecules do not move at constant speed between collisions. Their speeds vary due to elastic collisions with other molecules and the walls of the container. The other assumptions—identical molecules, free movement throughout the container, and negligible forces of attraction—are valid for an ideal gas.
Source: Myschool Past Questions Archive (Record #35449)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
A body is pulled over a distance of 500m by a force of 20N. If the power developed is o.4 kW, calculate the time interval during which the force is applied
A
0.2s
B
2.5s
C
25.0s
D
250.0s
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
t = \(\frac{fs}{p} = \frac{20 \times 500}{0.4 \times 1000} = 25s\)
Source: Myschool Past Questions Archive (Record #35452)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
A wire of length 30cm is moved with a speed of 2ms-1 at right angles to a magnetic field of flux density 0.4T. calculate the emf induced in the wire
A
0.15V
B
0.24V
C
2.70V
D
24.00V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35495)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Which of the following practices will lead to losses in electrical power transmission?
A
using transmission cables of large diameter
B
transmitting at high voltage and low current
C
transmitting at relatively low voltage and high current
D
using a set-up transformer at the production end
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35496)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
The change in mass of fuel during a nuclear reaction is 2.0 x 10-27 kg. Calculate the amount of energy released. (Speed of light = 2.0 x 108ms-1)
A
1.8 x 10-10J
B
9.0 x 10-11J
C
6.0 x 10-19J
D
1.2 x 10-45J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Q = \(\Delta MC^2\)
= 2 x 10-27(3 x 10)2
= 1.8 x 10-10J
Source: Myschool Past Questions Archive (Record #35500)
Physics
UTME / JAMB 2011
Mechanics and Properties of Matter
Solution
If the volume of a gas increases steadily as the temperature decreases at constant pressure, the gas obeys
A
Graham's Law
B
Boyle's Law
C
Pressure law
D
Charles Law
E
No Correct Option
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Rate of diffusion is inversely proportional to the square root of density - Graham's law
\( P \propto \frac{1}{v} \) at constant temperature - Boyle's law
\( P \propto T \) at constant volume - Pressure law
\( P \propto T \) at constant pressure - Charles law
therefore no correct option
Source: Myschool Past Questions Archive (Record #41404)
Physics
UTME / JAMB 2011
Mechanics and Properties of Matter
Solution
Two resistors 5\Omega and 10\Omega are arranged first in series and later in parallel to a 24V source, the ratio of total power dissipated in the series and parallel arrangements respectively is
A
5:3
B
1:50
C
50:1
D
3:5
E
No Correct Option
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Power in Series Arrangement
Total Resistance (R_series): R\(_{series}\) = R\(_1\) + R\(_2\) = 5\Omega + 10\Omega = 15\Omega
Total Power (P_series): P = \(\frac{V^2}{\text{R}}\) = \(\frac{24^2}{15}\) = 38.4W
Power in parallel Arrangement
Total Resistance(R\(_{parallel}\)): R\(_{parallel}\) = \(\frac{R_1 \times R_2}{R_1 + R_2}\) = \(\frac{5 \times 10}{5 + 10}\) = 3.33
Total Power(P_{parallel}\): P = \(\frac{V^2}{\text{R}}\) = \(\frac{24^2}{3.33}\) = 172.8W
Ratio of Powers
Power ratio = \(\frac{\text{Pseries}}{\text{Pparallel}}\) = \(\frac{38.4}{172.8}\) = \(\frac{1}{4.5}\) = \(\frac{2}{9}\)
Therefore, there is no correct answer.
Source: Myschool Past Questions Archive (Record #41409)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
(a) Explain diffusion.
(b) Give one reason why the rate of diffusion is higher in gases than in liquids at the same temperature.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) Diffusion is a process whereby fluids mix intimately with one another due to random molecular motion.
(b) Diffusion rate in gases is higher than that in liquids at the same temperature because molecular motion in gases are faster, the intermolecular forces is less and the density is also less than those in liquids.
Source: Myschool Past Questions Archive (Record #53323)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
State: (a) the difference between plane polarized light and ordinary light;
(b) two uses of polaroids.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) In plane polarized light the vibrations of light waves are perpendicular in one plane only while in ordinary light the vibrations of the particles are in all planes.
(b) Two uses of polaroids are:
- in sunglass to reduce sunlight intensity
- to eliminate reflected light or glare
- in the measurement of sugar solution concentration or saccharimetry; and
- in photo elasticity or stress analysis.
Source: Myschool Past Questions Archive (Record #53324)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
In fig. la and fig.1 b above, Ida and Wb represent the respective loads on a spring placedtiear a 30 cm rule, when in air and when in water:
(a) Identify the force causing a shrink in the spring in fig.(b).
(b) Given that the force constant of the spring is 2.0 x 10\(^{11}\) Nm\(^{-1}\), calculate the work done by the force in causing the shrink.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
(a) The force causing a shrink is the upthrust of the water.
(b) Work done = \(\frac{1}{2}ke^2\)
= \(\frac{1}{2}(2 \times 10^{11}) \times (2 \times 10^{-2})^2\) = 4.0 x 10\(^7\)
Source: Myschool Past Questions Archive (Record #53328)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
Explain why water in a narrow glass tube has a concave meniscus while mercury, in the same tube, has a convex meniscus.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
In the case of water in axarrow glass tube, the force of adhesion between the water and glass molecules is greater than the cohesive force among water molecule, hence, water clings to the glass tube forming a concave meniscus. In the case of mercury, the cohesive force among its molecules is greater than the adhesive force, between mercury molecules and water molecules hence mercury molecules cling to each other forming a convex meniscus in the capillary glass tube.
Source: Myschool Past Questions Archive (Record #53329)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
An electron of charge 1.60 x 10\(^{-19}\) C is accelerated under a potential difference of 1.0 x 10\(^5\) V. Calculate the energy of the electron in joules.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
E = eV= 1.6 x 10\(^{-19}\) x 1.0 x 10\(^5\)
=1.6 x 10\(^{-14}\)J
Source: Myschool Past Questions Archive (Record #53331)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
The uncertainty in determining the duration during which an electron remains in a particular energy level before returning to the ground state is 2.0 x 10\(^{-9}\)s. Calculate the uncertainty in determining its energy at that level. (\(\frac{h}{2 \pi}\) = h = 1.054 x 10\(^{-34}\)Js)
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
\(\Delta E \geq \frac{h}{2 \pi} \times \frac{1}{\Delta t}\)
\(\geq 1.054 \times 10^{-37} \times \frac{1}{2 \times 10^{-9}}\)
\(\geq 5.27 \times 10^{-28}\)J
Source: Myschool Past Questions Archive (Record #53333)