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C \(\frac{69}{12}\) H \(\frac{15.3}{1}\) O \(\frac{30.7}{16}\) C = 5.75, H = 15.3, O = 1.92 C \(\frac{5.75}{1,92}\) H \(\frac{15.3}{1.92}\) O \(\frac{1.92}{1.92}\) C\(_3\)H\(_8\)O

Solid in gas mixture: Smoke, ice clouds, dust. Liquid in gas mixture: fog, mist, vapour and hair sprays. Gas in solid mixture: aerogel, Styrofoam.

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.

Alkaline gases are any gaseous compounds that form an alkali (or basic) solution with a pH greater than 7 when dissolved in water. Ammonia is the most common alkaline gas

Charles' law is a special case of the ideal gas law in which the pressure of a gas is constant. Charles's law defines the direct relationship between temperature and volume. GIVEN DATA: V\(_1\) = 29.5cm\(^3\), V\(_2\) = ? , T\(_1\) = 0ºc or 273k, T\(_2\) = 15ºc or 288k \(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\) V\(_2\) = \(\frac{V_1 x T_2}{T_1}\) → \(\frac{29.5 x 288}{273}\) V\(_2\) = 31.1cm\(^3\)

Partial pressure is found by Dalton's Law: Px = PTotal ( nx / nTotal ) where Px = partial pressure of gas x PTotal = total pressure of all gases nx = number of moles of gas x nTotal = number of moles of all gases Step 1 Find PTotal Standard pressure is 1 atm. Step 2 Add up the number of moles of the component gases to find nTotal nTotal = noxygen + nnitrogen nTotal = 100 + 900 nTotal =1000cm3 Step 3 Now you have all the information needed to plug the values into the equation and solve for Poxygen P-oxygen = PTotal ( n-oxygen / nTotal ) oxygen = 1 atm ( 100 / 1000 ) oxygen= 0.1atm

The method used to prepare a salt depend on: the solubility of the salt in water. the heat stability of the salt

If you add salt to water, you lower its freezing point as well as raise its boiling point.

Shells and subshells are filled in energy level order, so electrons will fill the 2p subshell before the 3s shell. And the x subshell before the y and z.

Activated Carbon filters are excellent at removing chlorine and related poor taste and odor.

To make a fixed amount of a dilute solution from a stock solution, use the formula: C\(_1\)V\(_1\) = C\(_2\)V\(_2\) where: V\(_1\) = Volume of stock solution needed to make the new solution. C\(_1\) = Concentration of stock solution. V\(_2\) = Final volume of new solution. C\(_2\)= Final concentration of stock solution 2 * 10 = 0.5 * V2 20 = 0.5V2 \(\frac{20}{0.5}\) = V2 V\(_2\)= 40dm\(^3\) What would be added = V\(_2\) - V\(_1\) = 40 - 10 = 30dm\(^3\)

Since 2 mol H\(_2\) reacted with 1 mol of O\(_2\) : 50cm\(^3\) of hydrogen reacted with 25cm\(^3\) of oxygen Remainder oxygen = Supplied amount - Reacted amount → 75cm\(^3\) - 25cm\(^3\) = 50cm\(^3\)

The arrangement of elements in order of increasing electrode potential values is called electrochemical series. K > Na > Ca > Mg > Al > Zn > Fe > Ni > Sn > Pb > H > Cu > Ag > Au.

The steel spoon to be coated with silver is the cathode of the electrolytic cell and the anode of the electrolytic cell is made of a silver metal

high temperature and high pressure favor the highest yield for N\(_2\)O\(_4\) high temperature favours the production of the reactant since it is endothermic, while high pressure favours the side involving a decrease in volume.