Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 466–480 of 2096 verified questions
Sort by:
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Simplify 10\(\frac{2}{5} - 6 \frac{2}{3} + 3\)
A
6\(\frac{4}{15}\)
B
6\(\frac{11}{15}\)
C
7\(\frac{4}{15}\)
D
7\(\frac{11}{15}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
10\(\frac{2}{5} - 6 \frac{2}{3} + 3\)
\(\frac{52}{5} - \frac{20}{3} + \frac{3}{1}\)
= \(\frac{156 - 100 + 45}{15}\)
\(\frac{156 + 45 - 100}{15}\)
= \(\frac{201 - 100}{15}\)
= \(\frac{101}{15}\)
= 6\(\frac{11}{15}\)
Source: Myschool Past Questions Archive (Record #36931)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
If 23x = 325, find the value of x
A
7
B
6
C
5
D
4
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
23x = 325
2 \(\times x^1 + 3 \times x^0 = 3 \times 5^1 + 2 \times 5^0\)
= 2x + 3 = 15 + 2
2x + 3 = 17
2x = 17 - 3
2x = 14
x = \(\frac{14}{2}\)
x = 7
Source: Myschool Past Questions Archive (Record #36932)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
The volume of a cube is 512cm3. Find the length of its side
A
6cm
B
7cm
C
8cm
D
9cm
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
volume of cube = L x L x L
512cm3 = L3
L3 = 512cm3
L = 3\(\sqrt{512}\)
L (512)\(\frac{1}{3}\)
= (29)\(\frac{1}{3}\)
23 = 8cm
Source: Myschool Past Questions Archive (Record #36933)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Simplify: \(\sqrt{12} ( \sqrt{48} - \sqrt{3}\))
A
18
B
16
C
14
D
12
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\sqrt{12} ( \sqrt{48} - \sqrt{3}\))
\(\sqrt{4 \times 3} (6 \times 3 - \sqrt{3}) = 2 \sqrt{3}(4 \sqrt{3} - \sqrt{3})\)
= 2\(\sqrt{3} \times \sqrt{3} (4 - 1) 2\sqrt{9}(3) = 2 \times 3 \times 3 = 18\)
Source: Myschool Past Questions Archive (Record #36935)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Given that x > y and 3 3 ii. x y > 3
A
i
B
i and ii
C
i and iii
D
i, ii and iii
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
x > y and 3 3
x > 3 to give the possible
x > y > 3
Source: Myschool Past Questions Archive (Record #36936)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Three quarters of a number added to two and a half of the number gives 13. Find the number
A
4
B
5
C
6
D
7
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
let the number be x
2\(\frac{1}{2}x + \frac{3}{4}x = 13\)
\(\frac{5}{2}x + \frac{3}{4}x = 13\)
multiply through by 4
4(\(\frac{5}{2}\))x + 4(\(\frac{3}{4}\))x = 13 x 4
2(5x) + 3x = 52
10x + 3x = 52
13x = 52
x = \(\frac{52}{13}\)
x = 4
Source: Myschool Past Questions Archive (Record #36937)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
If x = {0, 2, 4, 6}, y = {1, 2, 3, 4} and z = {1, 3} are subsets of u = {x:0 \(\geq\) x \(\geq\) 6}, find x \(\cap\) (Y' \(\cup\) Z)
A
{0, 2, 6}
B
{1, 3}
C
{0, 6)
D
{9}
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
x = {0, 2, 4, 6}; y = {1, 2, 3, 4}; z = {1, 3}
u = {0, 1, 2, 3, 4, 5, 6}
y' = {0, 5, 6}
to find x \(\cap\) (Y' \(\cup\) Z)
first find y' \(\cup\) z = {0, 1, 3, 5, 6}
then x \(\cap\) (Y' \(\cup\) Z) = {0, 6}
Source: Myschool Past Questions Archive (Record #36938)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Make u the subject of formula, E = \(\frac{m}{2g}\)(v2 - u2)
A
u = \(\sqrt{v^2 - \frac{2Eg}{m}}\)
B
u = \(\sqrt{\frac{v^2}{m} - \frac{2Eg}{4}}\)
C
u = \(\sqrt{v- \frac{2Eg}{m}}\)
D
u = \(\sqrt{\frac{2v^2Eg}{m}}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
E = \(\frac{m}{2g}\)(v2 - u2)
multiply both sides by 2g
2Eg = 2g (\(\frac{M}{2g} (V^2 - U^2)\)
2Eg = m(V2 - U2)
2Eg - mV2 - mU2
mU2 = mV2 - 2Eg
divide both sides by m
\(\frac{mU^2}{m} = \frac{mV^2 - 2Eg}{m}\)
U2 = \(\frac{mV^2 - 2Eg}{m}\)
= \(\frac{mV^2}{m} - \frac{2Eg}{m}\)
U2 = V2 - \(\frac{2Eg}{m}\)
U = \(\sqrt{V^2 - \frac{2Eg}{m}}\)
Source: Myschool Past Questions Archive (Record #36944)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
F x varies inversely as y and y varies directly as Z, what is the relationship between x and z?
A
x \(\alpha\) z
B
x \(\alpha \frac{1}{z}\)
C
x \(\alpha z^2\)
D
x \(\alpha \frac{1}{z^2}\0
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
x \(\alpha \frac{1}{y}\)
y \(\alpha z\)
the relationship = x \(\alph \frac{1}{z}\)
Source: Myschool Past Questions Archive (Record #36946)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
If (x - a) is a factor pf bx - ax + x2, find the other factor.
A
(x + b)
B
(x - b)
C
(a + b)
D
(a - b)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #36951)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
The area of a sector a circle with diameter 12cm is 66cm2. If the sector is folded to form a cone, calculate the radius of the base of the cone [Take \(\pi = \frac{22}{7}\)]
A
3.0cm
B
3.5cm
C
7.0cm
D
7.5cm
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
diameter = 12cm
radius = \(\frac{12}{2}\)cm = 6cm
area of sector = 66cm2
area of sector = area of cone
66 = \(\pi rl\)
66 = \(\frac{22}{7} \times r \times 6\)
divide both sides by 6
11 = \(\frac{22}{7}r\)
22r = 11 x 7
r = \(\frac{77}{22}\)
= 3.5cm
Source: Myschool Past Questions Archive (Record #36959)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Which of the following is a measure of dispersion?
A
range
B
percentile
C
median
D
quartile
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
The range is a measure of dispersion that indicates the difference between the highest and lowest values in a dataset.
Source: Myschool Past Questions Archive (Record #36961)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
If x : y = 3 : 2 and y : z = 5 : 4, find the value of x in the ratio x : y : z
A
8
B
10
C
15
D
20
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #36964)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
approximate 0.0033780 to 3 significant figures
A
338
B
0.338
C
0.00338
D
0.003
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #36976)
Mathematics
WAEC / WASSCE 2014
Number and Numeration
Solution
Simplify \(\sqrt{\frac{8^2 \times 4^{n + 1}}{2^{2n} \times 16}}\)
A
16
B
8
C
4
D
1
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\sqrt{\frac{8^2 \times 4^{n + 1}}{2^{2n} \times 16}}\)
= \(\sqrt{\frac{2^{3(2)} \times 2^{2(n + 1)}}{2^{2n} \times 2^4}}\)
= \(\sqrt{\frac{2^6 \times 2^{2n + 2)}}{2^{2n} + 4}}\)
= \(\sqrt{\frac{2^6 + 2^{2n + 2)}}{2^{2n} + 4}}\)
= \(\sqrt{\frac{2^{2n + 8}}{2^{2n} + 4}}\)
= \(\sqrt{2^{2n + 8} \div 2^{2n} + 4}\)
= \(\sqrt{2^{2n - 2n} + 8 - 4}\)
= \(\sqrt{2^4}\)
= \(\sqrt{16}\)
= 4
Source: Myschool Past Questions Archive (Record #36978)