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No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option A.

If two cells of equal emf s are connected in parallel then the effective emf is equal to the emf of any one of the cells.

Is independent of the relative velocity of the layers is not true because: Viscosity is dependent on the relative velocity of the layers in a fluid; it describes how the fluid flows when layers move relative to each other. Viscosity depends on the area of the surface in contact Viscosity is independent of normal reaction Viscosity depends on the relative velocity between layers

Calculation of the force needed to produce extension of material F = Ke = 988.3 x 3 x 3 = 8840.74N

(a) Function of metal flat plate of solar panel - Receives and absorbs solar radiation to produce heat (b) Function of internal insulator of solar panel - Minimises heat loss (c) Function of tubes of solar panel - Helps to circulate the heat

(a) Type of material most suitable for the design of the core of an optical fibre - Glass/plasties (b) Condition necessary confine signal to the core of an optical fibre - The refractive index of the core must be greater than that of the cladding,

Expression for v c = kT\(^a\)U\(^b\), k is dimensionless [v] = k[T]\(^a\)[\(\mu\)]\(^b\) Lt\(^{-1}\) = kM\(^{a \div b}\) L\(^{a + b}\) T\(^{-2a}\) For T, -1 = 2a a = \(\frac{1}{2}\) For M, 0 = a + b b = -a = \(\frac{1}{2}\) v = KT\(^{\frac{1}{2}}\)\(\mu^{- \frac{1}{2}}\) OR v = k\(\sqrt{\frac{T}{\mu}}\)

To show that V\(_E\) = \(\sqrt{20R}\) KE = Gravitational Potential Energy \(\frac{1}{2}\)MV\(_E^2\) = \(\frac{GmM}{R}\) V\(_E^2\) = \(\frac{2GM}{R}\) but GM = gR\(^2\) V\(_E^2\) = \(\frac{2gR^2}{R}\) = 2gR V\(_E^2\) = \(\sqrt{2 \times 10 \times R}\) = \(\sqrt{20R}\) OR P.E = K.E mgR = \(\frac{1}{2}\)mv\(^2\) v\(^2\) = 2gR v = \(\sqrt{2gR}\) = \(\sqrt{20R}\)

Calculation of velocity of fired bullet Time of flight T = \(\frac{2u sin \theta}{g}\) 25 = \(\frac{2u sin 30}{g}\) u = 250ms\(^{-1}\)

- Travels a very long distance without losing its intensity - Has a very narrow optical bandwidth. - Gives more intense light/power - Is monochromatic

(a)i) Definition of a torque - The turning effect of force about an axis/pivot (ii) Factors that determine a torque - perpendicular distance of the force from the pivot - direction of the force. - magnitude of the force (b)(i) Definition of free fall: - The vertical motion of a body only under the influence of gravity/its own weight (ii) Calculation of the time taken by a body thrown vertically upward to reach the ground S = 10t - \(\frac{1}{2}\)10t\(^2\) -40 = 10t - \(\frac{1}{2}\)10t\(^2\) x 10 t\(^2\) (t + 2)(t - 4) = 0 Time to fall to the ground, t = 4s (c) Calculation of the mass of wood: - Mass of wood = upthrust due to water displace + upthrust due to oil displaced = 1000 x 2 x 8 x 8 x 10 + 720 x 6 x 8 x 8 x 10 = 0.404kg