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The fundamental frequency of vibrations of a string is inversely proportional to the square root of mass per unit length (linear density), if the tension and vibrating length of the string are constant.

When drawing a ray diagram for instance drawing two rays from the head of the object, the point of intersection of the two rays represents the position of the head of the image, but in the case of parallel rays of light drawn from the object such that the image is likewise formed at infinity, the ray from the head of the object forms the head of the image, similarly, the ray from the leg of the image. from the diagrams drawn, it is only in W that the ray from the head forms the leg of the image, others are correctly drawn

1 mole of CaCO\(_3\) = 100g or 6.02 X 10\(^{23}\) liberated 1 mole of CO\(_2\) or 44g or 6.02 X 10\(^{23}\) :100g = 6.02 X 10\(^{23}\) 10g of CaCO\(_3\) = x cross multiply [10g X 6.02 X 10\(^{23}\)] / 100g = x ⇒ x = 6.02 X 10\(^{22}\) Since 6.02 X 10\(^{23}\) of CaCO\(_3\) liberated 6.02 X 10\(^{23}\) of CO\(_2\) ⇒ 6.02 X 10\(^{22}\) of CaCO\(_3\) will liberate 6.02 X 10\(^{22}\) of CO\(_2\)

COMPOUNDS BOILING POINTS Butane -1 ^\circC Ethanoic acid 118 ^\circC Water 100 ^\circC Ethanol 78.37 ^\circC

Halide: A binary compound of a halogen with another element or group.

No. of moles = \(\frac{molar conc \times volume}{1000}\) No. of moles = \(\frac{0.108 \times 50}{1000}\) : No. of moles = 0.0054 moles = \( 5.4 \times 10^{-3}\)

Diffusion is the tendency of molecules to migrate and fill an empty space due to their random thermal motions. in diffusion, the diffusing molecules move from the places where their concentration high to places where their concentration is low.

The force required to make an object of mass \( m \), traveling with velocity \( v \), turn in a circle of radius \( r \) is known as the \textbf{centripetal force}. The formula for centripetal force \( F_c \) is given by: \(F_c = \frac{mv^2}{r}\) where:\( m \) = mass of the object, \( v \) = velocity of the object, \( r \) = radius of the circular path.

Gun Momentum = bullet momentum M\(_a\)V\(_a\) = M\(_b\)V\(_b\) 5 x V\(_a\) = 0.05 x 100 V\(_a\) = 1m\(^{-1}\)

In a simple pendulum, T = 2\(\pi\)\(\sqrt{\frac{L}{g}}\) \(\frac{T_1}{T_2} = \sqrt{\frac{L_1}{L_2}}\) but L\(_2\) = 4L\(_1\) \(\frac{T_1}{T_2} = \sqrt{\frac{L_1}{4L_1}}\) T\(_2\) = 2T\(_1\)

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option B.

Option D is correct.

When K is open. Total Resistance = 8 + 2 = 10\(\Omega\) 1 = \(\frac{V}{\Omega}\) = \(\frac{6v}{\Omega}\) = 0.6A Where K is closed, \(\frac{1}{8} + \frac{1}{8} = \frac{1}{\Omega}\) \(\frac{2}{8} = \frac{1}{\Omega}\) \(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\) \(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\) 4\(\Omega\) in series with 2\(\Omega\)= 6\(\Omega\) 1 = \(\frac{V}{\Omega}\) = \(\frac{6}{6}\) = 1A 1 - 0.6A = 0.4A increase

No expanded working has been attached for this question yet. The verified answer is Option C.