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Area of \(\Delta\) VYZ = Area of \(\Delta\) VWZ (same base and within same parallel)

PQR = 180o - 86o = 94o ∴PRQ = 180o - 94o - 36o = 48o

360º - 290º = 70º \(\frac{70}{2}\) = 35º

From the figure < TAB = < BTQ = 40^\circ (alternate segment) \(\therefore\)< ATB = 180^\circ - (70^\circ + 40^\circ) = 70^\circ (angle on a straight line) < BTC = \(\frac{40^\circ}{2} = \frac{< BTQ}{2}\) \(\therefore < BTQ = 40^\circ\) x^\circ = 180^\circ - (40^\circ + 70^\circ + 20^\circ) = 50^\circ

No expanded working has been attached for this question yet. The verified answer is Option D.

(cos 40^\circ - sin 30^\circ) = 0.7660 - 0.5 = 0.2660

tan θ - 7/3.5 = 2 tan θ= 2.0000 θ = 63o

tan21o =x/10 x = 10 tan 21o = 3.3839 = 3.8m

< YXS = 74^\circ (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\)) N\(_2\) E\(_2\) S\(_2\) = 180^\circ \(\therefore\) Bearing of Y from X = 180^\circ + 74^\circ = 254^\circ

Agric project = \(\frac{120}{360} \times N12,000.00\) = \(N4,000.00\)

Mode = 12

No expanded working has been attached for this question yet. The verified answer is Option C.

Probability that a student in favor is group A = \(\frac{128}{128 + 32 + 96 + 48}\) = \(\frac{128}{304}\) = \(\frac{8}{19}\)

Probability that the student is against the proposal = \(\frac{32 + 48}{128 + 32 + 96 + 48}\) = \(\frac{80}{304}\) = \(\frac{5}{19}\)

a2bx + ab2x; a2b - b2 abx(a + b); b(a2 - b2) b(a + b)(a + b) ∴ H.C.F. = (a + b)