Question Library

In longitudinal waves, such as sound waves in a liquid or gas, the displacement of the particles in the oscillation is always in the direction of propagation, so these waves do not exhibit polarization.

n = \(\frac{\frac{A+D}{2}}{sin\frac{A}{2}}\) where A = the refracting angle of the prism(60º) D = angle of deviation of the ray (30^\circ) n = \(\frac{\frac{60+30}{2}}{sin\frac{60}{2}}\) = \(\frac{sin45}{sin30}\) v = \(\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\) \(\frac{\frac{\sqrt{2}}{2}}{\frac{1}{2}}\) = \(\frac{\sqrt{2}}{2}\) x \(\frac{2}{1}\) = \(\sqrt{2}\) n = \(\sqrt{2}\)

The iris controls the amount of light by limiting the volume of light admitted. The lens then focuses the light onto the retina, forming an inverted image. The lens changes its shape to adjust the focus on both distant and near objects, a process called accommodation. This adjustment is done by two sets of muscles in the iris

Infrared rays produce a high heating effect. All red-hot bodies such as a heated iron ball, flame, and fire are sources of infrared rays.

X\(_c\) = \(\frac{1}{2\pi f c}\) f = \(\frac{1}{ 2 \pi f C}\) = \(\frac{1}{\pi \times 2 \times 250 \times 2.5 \times 10^{-6}}\) f = \(\frac{1\times 10^6}{ 1250 \pi}\) f = \(\frac{800}{\pi}\)

No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option A.

\(\frac{1}{u} + \frac{1}{v} = \frac{1}{f} = \frac{1}{15} + \frac{1}{10}\) u = 6.00

To find the focal length of the eye lens in a compound microscope, we use the lens formula: \(\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\) Given: Image distance from the eye lens: \( v_2 = 25.0 \, \text{cm}\) Object distance for the eye lens (image from the objective lens): \( u = -3.0 \, \text{cm} \) (negative since it is on the same side as the incoming light) \(\frac{1}{f} = \frac{1}{25.0} - \frac{1}{-3.0}\) \(\frac{1}{f} = \frac{1}{25.0} + \frac{1}{3.0}\) \(\frac{1}{25.0} = 0.04 \quad \text{and} \quad \frac{1}{3.0} \approx 0.3333\) \(\frac{1}{f} = 0.04 + 0.3333 \approx 0.3733\) \(f \approx \frac{1}{0.3733} \approx 2.68 \, \text{cm}\) The focal length of the eye lens is approximately \( 2.68 \, \text{cm} \).

x = \(\frac{vt}{2} = \frac{1560 \times 0.2}{2} = 156m\)

No expanded working has been attached for this question yet. The verified answer is Option A.

No expanded working has been attached for this question yet. The verified answer is Option D.

No expanded working has been attached for this question yet. The verified answer is Option E.

If the size of the hole in a pinhole camera is increased, the image formed becomes blurred and larger. This happens because a larger hole allows more light to enter, creating a larger image. However, the increased size also causes a wider range of rays from different points to converge, resulting in a loss of sharpness and a blurred image. Thus, the image is both larger and blurrier.

No expanded working has been attached for this question yet. The verified answer is Option B.