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Physics
UTME / JAMB 2025
Sound Wave
Solution
The speed of sound in air is 60 m/s. How far from the centre of a storm is an observer who hears a thunder clap 4s after the flash of the lightning?
A
140m
B
100m
C
340m
D
240m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Speed of sound = 60 m/s
Time delay = 4 s (light travel time is negligible)
Distance = speed \times time = 60 \times 4 = 240 m
Source: WAEC / JAMB / NECO Classroom Archive (Record #74545)
Physics
WAEC / WASSCE 2025
Sound Wave
Solution
Which of the following media allow(s) the transmission of sound waves through them? I. Air II. Liquid III. Solid
A
II only
B
III only
C
I, II, and III only
D
I only
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Sound waves are mechanical waves, which means they require a medium to travel through. They can travel through all three states of matter: gases (like air), liquids, and solids.
Source: WAEC / JAMB / NECO Classroom Archive (Record #76376)
Physics
WAEC / WASSCE 2025
Sound Wave
Solution
A sound note of frequency 250 Hz and a wavelength 1.3 m is produced at a point near a hill. If the echo of the sound is received 1 second later at that point, how far away is the hill from the point?
A
248.7 m
B
261.3 m
C
162.5 m
D
131.3 m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
f = 250 Hz; \lambda = 1.3 m; t = 1 s; d = ?
v = f\lambda = 250 \times 1.3 = 325 ms\(^{-1}\)
v = \(\frac{2d}{\text{t}}\)
∴ d = \(\frac{v \times t}{2}\) = \(\frac{(325 \times 1)}{2}\) = 162.5 m
Source: WAEC / JAMB / NECO Classroom Archive (Record #76378)
Physics
WAEC / WASSCE 2025
Sound Wave
Solution
A listener can detect the instrument from which a note is being sounded because different instruments produce the same note with different
A
Loudness
B
Pitches
C
Frequencies
D
Overtones
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Quality (overtones) is a characteristic note of a musical instrument that distinguishes it from another note of the same pitch and loudness produced by another instrument.
Source: WAEC / JAMB / NECO Classroom Archive (Record #76385)
Physics
WAEC / WASSCE 2025
Vibration in Springs and Pipes
Solution
A wire is stretched between two points, 1 m apart. If the speed of the wave generated on plucking the wire is 200 ms\(^{-1}\), what is the minimum frequency which will resonate with the wire?
A
50 Hz
B
100 Hz
C
200 Hz
D
75 Hz
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\lambda = 1 m; v = 200 ms\(^{-1}\); f = ?;
f = \(\frac{\text{v}{ \lambda}\) = \(\frac{200}{1}\) = 200 Hz
Source: WAEC / JAMB / NECO Classroom Archive (Record #76373)
Physics
UTME / JAMB 2025
Application of Lens
Solution
A short-sighted person's far point is 95cm. The defect can be corrected using
A
Diverging mirror of focal length 95cm
B
Plano convex lens of focal length 90cm
C
Diverging lens of focal length 95cm
D
Converging lens of focal length 95cm
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Short-sightedness (myopia) means distant objects focus in front of the retina, with the far point at 95 cm. A diverging lens (concave) corrects this by creating a virtual image of distant objects (u = \infty) at the far point (v = -95 cm). Using the lens formula: 1/f = 1/v - 1/u = -1/95 - 0, so f = -95 cm (diverging lens with focal length 95 cm).
Source: WAEC / JAMB / NECO Classroom Archive (Record #74554)
Physics
UTME / JAMB 2025
Application of Lens
Solution
The focal length of the natural eye lens is variable due to the action of the
A
Optical fluid
B
Ciliary muscle
C
Vitreous humor
D
retina nerves
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
B. Ciliary muscle.
The ciliary muscles control the shape of the lens, allowing the eye to focus on objects at different distances by changing the focal length of the lens.
Source: WAEC / JAMB / NECO Classroom Archive (Record #74567)
Physics
UTME / JAMB 2025
Fundamental and Derived Quantities
Solution
The dimensional symbol of tension in a string is expressed as
A
L T\(^{-2}\)
B
M\(^2\) L\(^{-1}\) T\(^{-2}\)
C
M L T\(^2\)
D
M L T\(^{-2}\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The tension \( T \) in a string is defined as the force acting along the string. The dimensional formula for force is given by:
\([T] = [F] = [M^1 L^1 T^{-2}]\)
Thus, the dimensional symbol of tension in a string is:
\([T] = [M L T^{-2}]\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #74488)
Physics
UTME / JAMB 2025
Electrical Conduction Through Liquids and Gases
Solution
Copper of 0.2g and silver of 1.2g are deposited when current is passed through copper and silver voltameter. Calculate the electrochemical equivalent, Z of silver if that of copper is 0.00028gC\(^{-1}\)
A
1.68 x 10\(^{-3}\)gC\(^{-1}\)
B
2.34 x 10\(^{-3}\)gC\(^{-1}\)
C
2.80 x 10\(^{-3}\)gC\(^{-1}\)
D
3.34 x 10\(^{-3}\)gC\(^{-1}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
From Faraday's first law, the mass deposited \( m = Z Q \), where \( Z \) is the electrochemical equivalent and \( Q \) is the charge passed.
Since the same charge \( Q \) passes through both voltmeters:
\(Q = \frac{m_{\mathrm{Cu}}}{Z_{\mathrm{Cu}}} = \frac{m_{\mathrm{Ag}}}{Z_{\mathrm{Ag}}} \)
Rearranging for \( Z_{\mathrm{Ag}} \):
\(Z_{\mathrm{Ag}} = \frac{m_{\mathrm{Ag}} \cdot Z_{\mathrm{Cu}}}{m_{\mathrm{Cu}}} \)
But: \( m_{\mathrm{Cu}} = 0.2 \, \mathrm{g} \), \( m_{\mathrm{Ag}} = 1.2 \, \mathrm{g} \), \( Z_{\mathrm{Cu}} = 0.00028 \, \mathrm{g \, C^{-1}} \)
\(Z_{\mathrm{Ag}} = \frac{1.2 \times 0.00028}{0.2} = \frac{0.000336}{0.2} = 0.00168 \, \mathrm{g \, C^{-1}} \)
Source: WAEC / JAMB / NECO Classroom Archive (Record #74479)
Chemistry
UTME / JAMB 2025
Atomic Structure and Bonding
Solution
Atom with the electron configuration of 1S\(^2\)2S\(^2\)2P\(^6\)3S\(^2\) belongs to
A
Group 3 and Period 2
B
Group 8 and Period 3
C
Group 2 and Period 3
D
Group 2 and Period 6
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Magnesium (Mg) belongs to Group 2 (the Alkaline Earth metals) and Period 3 of the periodic table, meaning it has 2 valence electrons and three electron shells, placing it in the s-block.
Source: WAEC / JAMB / NECO Classroom Archive (Record #74220)
Chemistry
UTME / JAMB 2025
Chemical Bonding
Solution
The type of bond between copper(II) tetraamine and chlorine in [Cu(NH\(_3\))\(_4\)]Cl\(_2\)
A
dative
B
van der waals
C
ionic
D
covalent
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The compound [Cu(NH\(_3\))\(_4\)]Cl\(_2\) is an ionic compound composed of a complex cation, the tetraamminecopper(II) ion ([Cu(NH\(_3\))\(_4\)]\(^{2+}\)), and two chloride anions (Cl\(^−\)).
The primary force connecting the positively charged complex ion and the negatively charged chloride ions is the electrostatic attraction known as an ionic bond. This bond forms between species with a significant difference in electronegativity, specifically between a cation and an anion.
Dative bonds (coordinate covalent bonds) exist within the complex ion itself, specifically between the central copper(II) ion and the nitrogen atoms of the ammonia ligands.
Van der Waals forces and typical covalent bonds are not the main attractive forces between the distinct cation and anion units in this solid salt structure.
The correct answer is ionic - option C
Source: WAEC / JAMB / NECO Classroom Archive (Record #74137)
Chemistry
UTME / JAMB 2025
Unsaturated Saturated and Supersaturated Solutions
Solution
Commercial deodorant is an example of a colloid called
A
aerosol
B
sol
C
foam
D
emulsion
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The commercial deodorant (specifically spray or mist form) is an example of a colloid called an aerosol.
In this type of colloid, the dispersed phase (the substance being spread out) is a liquid, while the dispersion medium (the substance the phase is dispersed in) is a gas (air or propellant).
Source: WAEC / JAMB / NECO Classroom Archive (Record #74248)
Chemistry
UTME / JAMB 2025
Endothermic and Exothermic Reactions
Diagram
Solution
The reaction above illustrated is
Attached Figure / Diagram
A
spontaneous
B
endothermic
C
exothermic
D
reversible
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In the reaction given, the chemical reaction can be re-written as A + B → C + D
This implies, A and B are the reactants, while C and D are the products.
The energy level of the products (C+D) is higher (50) on the graph than the energy level of the reactants (A+B), (20). The arrow representing the overall enthalpy change (\DeltaH) points upward, showing a gain in energy, resulting in a positive \DeltaH value.
i.e \DeltaH\(_{reaction}\) = \DeltaH\(_{product}\) - \DeltaH\(_{reactant}\)
\DeltaH\(_{reaction}\) = (C+D) - ( A+B)
= 50 - 20 = +30
\DeltaH\(_{reaction}\) = + ve , hence, it is an endothermic reaction - option B
Source: WAEC / JAMB / NECO Classroom Archive (Record #74881)
Physics
UTME / JAMB 2025
Waves and Optics
Solution
Which of these colours in the visible spectrum has the longest wavelength?
A
Red
B
Blue
C
Yellow
D
Violet
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Answer: A. Red (Visible spectrum: red ~700 nm, longest; violet ~400 nm, shortest.)
Source: Myschool Past Questions Archive (Record #74347)
Physics
UTME / JAMB 2025
Mechanics and Properties of Matter
Solution
The power of a lens in diopters is
A
3f
B
\(\frac{1}{\text{f}}\)
C
2f
D
f
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Lens power P = 1/f, where f is focal length in meters; unit is diopter.
Source: Myschool Past Questions Archive (Record #74348)