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Mathematics
WAEC / WASSCE 1993
Trigonometry, Elevation & Bearings
Cos 75o has the same value as
A
cos 115o
B
cos 255o
C
cos 285o
D
-sin165o
E
-sin 255o
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #23218)
Mathematics
WAEC / WASSCE 1993
Trigonometry, Elevation & Bearings
Solution
If sin x = 12/13, where 0^\circ < x < 90^\circ, find the value of 1 - cos\(^2\)x
A
25/169
B
64/169
C
105/169
D
144/169
E
8/13
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\sin x = \frac{12}{13}\)
\(\cos x = \frac{5}{13}\)
\(\cos^{2} x = (\frac{5}{13})^2 = \frac{25}{169}\)
\(1 - \cos^{2} x = 1 - \frac{25}{169}\)
= \(\frac{144}{169}\)
Source: Myschool Past Questions Archive (Record #23219)
Mathematics
WAEC / WASSCE 1993
Trigonometry, Elevation & Bearings
Solution
The angle of elevation of the top of a tower from a point on the horizontal ground, 40m away from the foot of the tower is 30o. Find the height of the tower.
A
20m
B
40√3m /3
C
20√3m
D
40√3m
E
60cm
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
\(\tan 30 = \frac{x}{40}\)
\(x = 40 \tan 30 = \frac{40}{\sqrt{3}}\)
= \(\frac{40\sqrt{3}}{3} m\)
Source: Myschool Past Questions Archive (Record #23220)
Mathematics
WAEC / WASSCE 1993
Trigonometry, Elevation & Bearings
Solution
At a point 500m from the base of a water tank the angle of elevation of the top of the tank is 45o. Find the height of the tank,
A
250m
B
353m
C
354m
D
433m
E
500m
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
\(\tan 45 = \frac{x}{500}\)
\(x = 500 \tan 45\)
= \(500 m\)
Source: Myschool Past Questions Archive (Record #23221)
Mathematics
WAEC / WASSCE 1993
Statistics (Data Representation, Central Tendency & Dispersion)
Solution
Find the median of the following set of numbers: 28, 29, 39, 38, 33, 37, 26, 20, 15, 25
A
33
B
29.5
C
29
D
28.5
E
28
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
15, 20, 25, 26, 28, 29, 33, 37, 38, 39
median = \(\frac{28 + 29}{2}\)
= 28.5
Source: Myschool Past Questions Archive (Record #23222)
Mathematics
WAEC / WASSCE 1993
Sets, Logic & Venn Diagrams
Diagram
What is A∩B in the diagram above?
Attached Figure / Diagram
A
(2,3)
B
(2,3,4)
C
(1,2,3)
D
(2,3,8)
E
(6,4,7)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #23223)
Mathematics
WAEC / WASSCE 1993
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
The table above shows the scores of a group of 40 students in a physics test.
If the mode is m and the median is n, then (m,n) is
Attached Figure / Diagram
A
(5,5)
B
(5,6)
C
(6,5)
D
(9,4)
E
(9,5)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
Mode = 5
Median = 5
(m, n) = (5, 5)
Source: Myschool Past Questions Archive (Record #23224)
Mathematics
WAEC / WASSCE 1993
Statistics (Data Representation, Central Tendency & Dispersion)
Solution
Find the median of the set of numbers 12, 15, 13, 14, 12, 12.
A
12
B
12.5
C
13
D
13.5
E
14
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
12, 12, 12, 13, 14, 15
Median = \(\frac{12 + 13}{2}\)
= 12.5
Source: Myschool Past Questions Archive (Record #23226)
Mathematics
WAEC / WASSCE 1993
Statistics (Data Representation, Central Tendency & Dispersion)
Solution
The distribution by state of 840 students in the Faculty of Science of a Nigerian University in a certain session is as follows:
Bendel
45
kwara
410
Ogun
105
Ondo
126
Oyo
154
In a pie chart drawn to represent this distribution, the angle subtended by Ondo is
A
36o
B
42o
C
45o
D
48o
E
54o
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
Ondo = \(\frac{126}{840} \times 360^\circ\)
= \(54^\circ\)
Source: Myschool Past Questions Archive (Record #23227)
Mathematics
WAEC / WASSCE 1993
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
How many student took the examination
Attached Figure / Diagram
A
18
B
20
C
21
D
23
E
24
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
= 2 + 4 + 3 + 6 + 6 + 2 + 1
= 24 students
Source: Myschool Past Questions Archive (Record #23228)
Mathematics
WAEC / WASSCE 1993
Plane Geometry, Polygons & Circle Theorems
Diagram
Solution
How many students scored less than 7 marks?
Attached Figure / Diagram
A
9
B
15
C
18
D
21
E
25
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
= 2 + 4 + 3 + 6
= 15 students scored less than 7 marks.
Source: Myschool Past Questions Archive (Record #23229)
Mathematics
WAEC / WASSCE 1993
Permutations, Combinations & Probability
Solution
What is the probability that an integer selected from the set of integers (20, 21, ...., 30) is a prime number?
A
2/11
B
5/11
C
6/11
D
9/11
E
2/3
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
S = {20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30}
n(S) = 11
P = {23, 29}
n(P) = 2
Prob(P) = \(\frac{2}{11}\)
Source: Myschool Past Questions Archive (Record #23230)
Mathematics
WAEC / WASSCE 1993
Permutations, Combinations & Probability
Solution
A fair die is rolled once. What is the probability of obtaining a number less than 3?
A
1/6
B
1/3
C
2/3
D
1/2
E
5/6
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Prob(less than 3) = \(\frac{2}{6}\)
= \(\frac{1}{3}\)
Source: Myschool Past Questions Archive (Record #23231)
Mathematics
WAEC / WASSCE 1993
Permutations, Combinations & Probability
Solution
What is the probability of having an even number in a single toss of a fair die?
A
1/6
B
1/3
C
1/2
D
2/3
E
5/6
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Prob(even number in single toss) = \(\frac{3}{6}\)
= \(\frac{1}{2}\)
Source: Myschool Past Questions Archive (Record #23232)
Mathematics
WAEC / WASSCE 1993
Permutations, Combinations & Probability
Solution
What is the probability that a total sum of seven would appear in two tosses of a fair die?
A
5/36
B
1/6
C
7/36
D
5/6
E
1
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
No of possible outcome = 36
Required outcome (R) = {(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)}
n(R) = \(\frac{6}{36}\)
= \(\frac{1}{6}\)
Source: Myschool Past Questions Archive (Record #23233)