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Physics
UTME / JAMB 1978
Thermal Physics
A few grains of table salt were put in a cup of water, kept at constant temperature and left undisturbed. Eventually all the water tasted salty. The action is due to
A
convection
B
osmosis
C
capillarity
D
diffusion
E
conductivity
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #29259)
Physics
UTME / JAMB 1978
Thermal Physics
Solution
A temperature 20^\circC is the same as
A
36oF
B
68oF
C
11.1oF
D
43.1oF
E
25oF
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
212^\circF ... 100^\circC
\(\theta\)^\circF ... 20^\circC
32^\circF ... 0^\circC
\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)
180 = 5(\(\theta\) - 32)
5\(\theta\) = 180 + 160 = 340
\(\theta\) = 68^\circF
Source: Myschool Past Questions Archive (Record #29265)
Physics
UTME / JAMB 1978
Thermal Physics
Solution
The latent heat of fusion of ice is 80cal g\(^{-1}\). How much heat is required to change 10g of ice at 0ºC into water at the same temperature?
A
80 cal
B
10 cal
C
8 cal
D
800 cal
E
400 cal
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Quantity of heat = ml
= 10 x 80
= 800 cal
Source: Myschool Past Questions Archive (Record #29269)
Physics
UTME / JAMB 1978
Thermal Physics
The amount of heat required to raise the temperature of a body is
A
Thermal energy
B
thermal conduction
C
heat loss
D
specific heat capacity
E
thermal capacity
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #41579)