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0.0000152 x 0.00042 = A x 10\(^{B}\) 1 \(\leq\) A < 10, it means values of A include 1 - 9 0.0000152 = 1.52 x 10\(^{-5}\) 0.00042 = 4.2 x 10\(^{-4}\) 1.52 x 4.2 = 6.384 10\(^{-5}\times 10^{-4}\) = 10\(^{-5-4}\) = 10\(^{-9}\) = 6.38 x 10\(^{-9}\) A = 6.38, B = -9

By re-arranging 21, 23, 29, 40, 41, 43| 47, 50| 50, 55, 56, 70, 70, 73 The median = \(\frac{47 + 50}{2}\) \(\frac{97}{2}\) = 48\(\frac{1}{2}\)

\(\begin{array}{c|c} Scores & Frequency \\\hline 55 & 1\\ 60 & 4\\ 65 & 6\\ 70 & 4\\ 75 & 1 \end{array}\) Median = 65(middle number) Mode = 65(most common) Median + Mode = 65 + 65 = 130

Vowels of letters are 6 in numbers prob. of vowel = \(\frac{6}{13}\)

\(\frac{24.57 + 25.63 + 24.32 + 26.01 + 25.77}{5}\) mean = \(\frac{126.3}{5}\) = 25.26

Re-arrange in ascending order: 110, 113, 113, 116, |117|, 118, 119, 127 a= 117

\(\bar{x}\) = \(\frac{fx}{N}\) = \(\frac{6705}{50}\) = 1341 = N134.10

1st 30 pupils at average age of 15.3 yrs. give total age of 15.3 x 30 = 459yrs 2nd group of 30 pupils at average age of 15.2 yrs give total age of 15.2 x 30 = 456yrs Difference in age = 459 - 456 = 3 yrs

Arranging the scores in ascending order: 12, 17, 25, 25, 25, 25, 26, 26, 26, 29, 29, 29, 35, 35. The median is the average of the 7th and 8th marks. = \(\frac{26 + 26}{2} = 26\)

Add all the No.s together to give 100 \(\sum\)xf = 100 N = 20 x = \(\frac{\sum xf}{N}\) = \(\frac{100}{20}\) = 5

x 5 6 7 8 9 f 6 4 8 7 5 Mode is the No having the highest frequency = 7

Total score for 2A & 2B = 4200 mean score = \(\frac{4200}{40 + 35}\) = \(\frac{4200}{75}\) = 56

\(\frac{1.2 + 1.0 + 0.9 + 1.4 + 0.8 + 0.8 + 1.2}{8}\) = \(\frac{8.4}{8}\) = 1.05

Mean = 5, 42 Median = 6 Mode = 7 The mean is less than the median

By re-arranging the goals in ascending order 0. 0. 0. 0. 0, 1. 1. 1. 1. 1. 1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5. Mean = \(\frac{36}{20}\) = 1.8 Median = \(\frac{1 + 2}{2}\) = \(\frac{3}{2}\) = 1.5 Mode = 1 = 1.8, 1.5 and 1