Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 331–345 of 4783 verified questions
Sort by:
Chemistry
WAEC / WASSCE 2024
Matter & Separation Techniques
Solution
A saturated solution at 30\(^0\)C will normally produce crystals at a temperature of
A
50\(^0\)C
B
40\(^0\)C
C
35\(^0\)C
D
20\(^0\)C
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
A saturated solution at 30^\circC will normally produce crystals when it is cooled below the saturation point for that specific solute at a lower temperature; this means that crystals will typically begin to form as the solution cools down from 30^\circC, with the exact temperature depending on the solubility curve of the dissolved substance.
Source: Myschool Past Questions Archive (Record #72193)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
The following organic compounds are polymers except
A
rubber
B
starch
C
proteins
D
fats
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Although fats are complex molecules that are made up of fatty acids and glycerol, they are not polymers. Polymers are large molecules made up of many smaller units called monomers that are chemically bonded together.
Rubber, starch and proteins are polymers because they have several units of isoprene, glucose and amino acids respectively, chemically bonded together.
Source: Myschool Past Questions Archive (Record #72194)
Chemistry
WAEC / WASSCE 2024
Stoichiometry & Mole Concept
Solution
According to the collision theory of reaction rates, which of the following conditions is not required for two molecules to react? The molecules must
A
come into contact without loss of energy on colliding with each other
B
collide with enough energy to overcome the activation energy barrier
C
collide in an orientation that makes formation of product possible
D
possess enough speed to overcome intermolecular forces of attraction
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The collision theory assumes that the colliding molecules have sufficient energy to be able to overcome the intermolecular forces of attraction and the activation energy barriers, but it does not require that the collision be perfectly elastic. i.e no loss of energy.
Source: Myschool Past Questions Archive (Record #72195)
Chemistry
WAEC / WASSCE 2024
Acids, Bases, and Salts
Solution
A weak acid is one which
A
is not corrosive
B
completely ionizes in water
C
does not produce salt with alkali
D
slightly ionizes in water
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
While a strong acid dissociates or ionizes completely in water, weak acids only partially ionizes in water.
Source: Myschool Past Questions Archive (Record #72196)
Chemistry
WAEC / WASSCE 2024
Acids, Bases, and Salts
Solution
Which of the following conditions are necessary for the preparation of alkanoates from alkanols and alkanoic acid?
A
Water and NaOH
B
Conc. H\(_2\)SO\(_4\) and heat
C
NaOH and heat
D
water and aqueous HCl
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Esterification reaction is the reaction between an alkanol (alcohol) and an alkanoic acid (carboxylic acid) in the presence of an acid catalyst forms an ester (alkanoate) and water. To produce alkanoates (esters) from alkanols and alkanoic acids, you need to perform esterification, which requires a concentrated acid catalyst (like sulphuric acid) and heat.
Source: Myschool Past Questions Archive (Record #72197)
Chemistry
WAEC / WASSCE 2024
Stoichiometry & Mole Concept
Solution
The volume of 22g of CO\(_2\) at stp is equivalent to [C =12, O =16, molar volume at stp = 22.4 dm\(^3\) ]
A
22.0 dm\(^3\)
B
22.4 dm\(^3\)
C
11.2 dm\(^3\)
D
5.6 dm\(^3\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Given:
m = 22g
M.V = 22.4dm\(^3\)
V = ?
First, calculate the number of moles n, by dividing mass of CO\(_2\) by the molar mass of CO\(_2\), since n = \(\frac{mass}{Molar mass}\)
Molar mass of CO\(_2\) = 12 + (2 x 16) = 44g/mol
So, n = \(\frac{mass}{Molar mass}\)
n = \(\frac{22}{44}\) = 0.5 mole
Also recall that number of moles of gases, n = \(\frac{Volume}{Molar Volume}\)
n = \(\frac{V}{M.V}\)
0.5 = \(\frac{V}{22.4}\)
V = 0.5 X 22.4
V = 11.2 dm\(^3\)
Alternatively,
Given the mass of CO\(_2\) = 22g
Molar mass of CO\(_2\) = 12 + (16X2) = 44g
number of moles, n = \(\frac{m}{M}\) = \(\frac{22}{44}\) = 0.5 mole.
If 1 mole of CO\(_2\) = 22.4dm\(^3\)
0.5 mole of CO\(_2\) = X dm\(^3\)
X = 0.5 x 22.4 = 11.2 dm\(^3\)
Source: Myschool Past Questions Archive (Record #72198)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
Pairs of outermost shell electrons which are not used in bonding are
A
lone pairs
B
bonding pairs
C
valence electrons
D
electrovalent electrons
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Pairs of outermost shell electrons that are not used in bonding are called lone pairs or non-bonding pairs.
A lone pair refers to a pair of valence electrons that are not shared with another atom in a covalent bond and is sometimes called an unshared pair or non-bonding pair. Lone pairs are found in the outermost electron shell of atoms.
Source: Myschool Past Questions Archive (Record #72199)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
\(_8\)X\(^{2-}\) and \(_{10}\)Y are
A
isomers
B
isotopes
C
allotropes
D
isoelectronic
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Isoelectronic species are atoms, ions, or molecules that have the same number of electrons and therefore, the same electronic configuration, even if they are different elements.
For \(_8\)X\(^{2-}\)
Number of protons = 8, while Number of electrons = 10, because X gains 2 electrons and outnumbers the number of protons.
Also, for \(_{10}\)Y,
Number of protons = 10, while Number of electrons = 10, because Y has no charge, it is a neutral atom. Hence, the number of protons = Number of electrons =10
Since the number of electrons are the same in both atoms of element X and element Y, even though they are of different elements, they are said to be isoelectronic species.
Therefore, \(_8\)X\(^{2-}\) and \(_{10}\)Y are Isoelectronic
Source: Myschool Past Questions Archive (Record #72200)
Chemistry
WAEC / WASSCE 2024
Acids, Bases, and Salts
Solution
Pure water contaminated with quicklime will have a pH of
A
1
B
6
C
7
D
8
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Pure water contaminated with quicklime (calcium oxide) will have a highly alkaline pH, significantly above 7. The reason being that quicklime (CaO) reacts vigorously with water to form slaked lime (calcium hydroxide, Ca(OH)₂), a strong base.
Source: Myschool Past Questions Archive (Record #72201)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
The electron configuration of \(_{29}\) Cu is
A
1S\(^2\) 2S\(^2\) 2P\(^6\) 3S\(^2\) 3P\(^6\) 4S\(^1\) 3d\(^{10}\)
B
1S\(^2\) 2S\(^2\) 2P\(^6\) 3S\(^2\) 3P\(^6\) 4S\(^3\) 3d\(^9\)
C
1S\(^2\) 2S\(^2\) 2P\(^5\) 3S\(^2\) 3P\(^6\) 4S\(^2\) 3d\(^{10}\)
D
1S\(^2\) 2S\(^2\) 2P\(^6\) 3S\(^2\) 3P\(^2\) 4S\(^1\) 3d\(^{10}\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The electron configuration of copper (Cu), with atomic number 29, is [Ar] 3d¹⁰ 4s¹ or 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s¹.
Here's a more detailed explanation:
Atomic Number:Copper (Cu) has 29 electrons.
Following the Aufbau principle, the expected configuration would be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁹.
However, copper exhibits an exception to this rule. A full or half-filled d-orbital is more stable than a partially filled one.
Therefore, one electron moves from the 4s orbital to the 3d orbital, resulting in the configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s¹ or [Ar] 3d¹⁰ 4s¹.
Source: Myschool Past Questions Archive (Record #72202)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
When s and p block elements react, the bond formed is
A
electrovalent
B
covalent
C
metallic
D
dative-covalent
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
When s and p block elements react, the bond formed is typically ionic or electrovalent, as s-block elements tend to lose electrons to achieve a stable electron configuration, while p-block elements, especially nonmetals, readily gain electrons. These elements(alkali and alkaline earth metals) have low electronegativity and readily lose electrons to form positively charged ions (cations).
On the other hand,the P-block elements, especially non-metals like halogens and oxygen, have high electronegativity and readily gain electrons to form negatively charged ions (anions). The electrostatic attraction between these oppositely charged ions results in the formation of an ionic bond or electrovalent bond.
Source: Myschool Past Questions Archive (Record #72203)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
The hardest form of carbon is
A
charcoal
B
coke
C
diamond
D
graphite
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Diamond is the hardest form of carbon. It's also the hardest naturally occurring substance on Earth. Diamond is an allotrope of carbon, meaning it's a variation of carbon's structure. In diamond, carbon atoms are arranged in a tetrahedral structure, with each carbon atom bonded to four other carbon atoms. This structure creates a rigid, three-dimensional network of carbon atoms. Thus,the strong bonds between the carbon atoms make diamond extremely hard.
Source: Myschool Past Questions Archive (Record #72204)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
The metallic bonding in aluminium is strong because of large number of
A
delocalized electrons
B
immobile electrons
C
lone pair electrons
D
valence electrons
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The strong metallic bonding in aluminum is due to a large number of delocalized electrons that are shared among the metal atoms, creating a "sea" of electrons that strongly attracts the positively charged metal ions.
In metallic bonding, the outermost electrons of metal atoms are not bound to any specific atom but are free to move throughout the entire structure. These electrons form a "sea" or "cloud" of negative charge. The positively charged metal ions (cations) are attracted to this "sea" of delocalized electrons, creating a strong electrostatic attraction that holds the metal atoms together.
Source: Myschool Past Questions Archive (Record #72205)
Chemistry
WAEC / WASSCE 2024
Atomic Structure and Periodic Table
Solution
How many covalent bonds are formed by Nitrogen?
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Nitrogen typically forms three covalent bonds. However, it can form four or five bonds in some cases.
Explanation
Nitrogen has five valence electrons.
To fill its outer shell, it needs three more electrons.
Each covalent bond adds one electron to its outer shell.
Therefore, nitrogen forms three covalent bonds.
Source: Myschool Past Questions Archive (Record #72206)
Chemistry
WAEC / WASSCE 2024
Acids, Bases, and Salts
Solution
When an element exists in two or more forms in the same physical state, it exhibits
A
isotopy
B
allotropy
C
isobars
D
isomerism
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
When an element exists in two or more forms in the same physical state, it exhibits allotropy or allotropism.
Allotropy refers to the property of some chemical elements to exist in two or more different forms, known as allotropes, in the same physical state (solid, liquid, or gas).
Allotropes are different forms of the same element that have different physical properties but the same chemical properties.
Examples of elements that exhibit allotropy include carbon (graphite, diamond), sulphur etc
Source: Myschool Past Questions Archive (Record #72207)