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Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
Hydrochloric acid is not suitable in the preparation of ethanoic acid because it
A
is too acidic
B
is too volatile
C
can attack cork and rubber used as containers
D
turns blue litmus red
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Hydrochloric acid is not suitable for preparing ethanoic acid because it is too volatile.Being too volatile, means it has a low boiling point and is easily evaporated. Thus, HCl is not suitable because it cannot carry out the oxidation process required to convert alcohols into acids like ethanoic acid.
Ethanoic acid, also known as acetic acid, is a weak acid that doesn't fully dissociate in water, while hydrochloric acid is a strong acid that dissociates almost completely.
Source: Myschool Past Questions Archive (Record #70442)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
A radioactive element of mass 1g has half-life of 2 minutes, what fraction of the substance would have disintegrated after 10 minutes?
A
1/4
B
1/8
C
1/16
D
1/32
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
\(\frac{Original mass}{2^n}\) = Residual mass
Where n = number of activity = \(\frac{exposure time}{half life}\)
Given:
Original mass = 1g, exposure time = 10 minutes , half life = 2 minutes, Residual mass = ?
Substituting all the given parameters appropriately, we have
n = \(\frac{10}{2}\)
n = 5
\(\frac{Original mass}{2^n}\) = Residual mass
\(\frac{1}{2^5}\) = Residual mass
\(\frac{1}{32}\) = Residual mass
Residual mass = \(\frac{1}{32}\) or 0.03125g
Source: Myschool Past Questions Archive (Record #70443)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
Hydrogen chloride gas and ammonia can be used to demonstrate the fountain experiment because they are
A
light
B
volatile
C
very soluble in water
D
heavy gases
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The fountain experiment demonstrates the solubility of gases in water. Hydrogen chloride gas and ammonia gas are used in the fountain experiment because they are both highly soluble in water.
Hydrogen chloride: A liquid gas that is highly soluble in water and has an acidic nature. The acidic nature of hydrogen chloride is demonstrated in the fountain experiment when the blue litmus solution turns red. Also, Ammonia: A colourless gas with a pungent smell that is lighter than air
Source: Myschool Past Questions Archive (Record #70444)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
In the conductance of aqueous CuSO\(_4\) solution, the current carriers are the
A
mobile electrons
B
metallic ions
C
hydrated ions
D
hydrated electrons
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The current carriers in an aqueous copper sulphate (CuSO\(_4\)) solution are ions. When copper sulphate is dissolved in water, it dissociates into ions that can carry an electric charge. These ions are the current carriers in the solution.
When dissolved in water as part of CuSO\(_4\), "Cu\(^{2+}\)" is considered a hydrated ion because it is surrounded by water molecules in solution, forming a complex ion like [Cu(H\(_2\)O)\(_6\)]\(^{2+}\).
"Cu\(^{2+}\)" itself represents the copper metal ion, which is considered a metallic ion, but when in aqueous solution, it readily forms bonds with water molecules, becoming a hydrated ion. This means the copper ion is not simply "Cu2+" but is surrounded by water molecules, forming a complex ion like [Cu(H\(_2\)O)\(_6\)]\(^{2+}\)..
Source: Myschool Past Questions Archive (Record #70445)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
A type of isomerism that ClCH=CHCl can exhibit is
A
chain
B
positional
C
functional group
D
optical
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
ClCH=CHCl can exhibit geometrical isomerism and positional isomerism. ClCH=CHCl can exhibit positional isomerism because the positions of the functional groups or substituent atoms are different. Positional isomerism occurs when compounds with the same molecular formula have different properties due to the difference in the position of a functional group, multiple bond, or branched chain.
Source: Myschool Past Questions Archive (Record #70446)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
The basicity of tetraoxophosphate(V) acid is
A
1
B
4
C
2
D
3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The basicity of tetraoxophosphate(V) acid, or H\(_3\)PO\(_4\), is 3, making it a tribasic acid.
Source: Myschool Past Questions Archive (Record #70447)
Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
Which of the following is used in forming slag in the blast furnace for the extraction of iron?
A
Ca(CO\(_3\) )\(_2\)
B
Ca(OH)\(_2\)
C
CaCO\(_3\)
D
CaO
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
In the extraction of iron, "slag" refers to a molten, glassy by-product that forms on the surface of the molten iron during the smelting process, primarily composed of impurities like silicon dioxide (from the ore) that react with a flux (like limestone) added to the furnace, effectively separating these impurities from the pure iron and allowing them to be removed as a separate layer; essentially, it's a waste product created to remove unwanted materials from the iron ore during extraction. Slag is mainly a mixture of metal oxides and silicon dioxide.
Limestone, CaCO\(_3\) is used to form slag in the blast furnace process during the extraction of iron.
The limestone decomposes in the furnace to form calcium oxide (CaO), which then reacts with impurities like silicon dioxide, SiO\(_2\) to form calcium silicate, Ca\(_2\)SiO\(_4\)
Source: Myschool Past Questions Archive (Record #70448)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
Calculate the number of moles of Copper that will be deposited, if 2 Faraday of electricity is passed through the copper during the electrolysis of copper(II)tetraoxosulphate(VI)
[1F = 96500C ]
A
0.5 mole
B
1.0 mole
C
2.0 moles
D
3.0 moles
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
NB: 1F = 1 mole of electrons of the atom of an element
In the case of copper (Cu), the valency is 2+.
⇒ Cu\(^{2+}\) + 2e\(^-\) → Cu
So, 2F = 1 mole of Cu
then, 2F = x mole
x = \(\frac{2\times1}{2}\)
x = 1 mole
Source: Myschool Past Questions Archive (Record #70449)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
The volume occupied by 1 mole of an ideal gas at a temperature of 13\(^0\)C and a pressure of 1.58 atm is
[ R = 0.082 atm dm\(^3\) K\(^{-1}\)mol\(^{-1}\) ]
A
14.84 dm\(^3\)
B
14.84 cm\(^3\)
C
0.64 dm\(^3\)
D
0.64 cm\(^3\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
According to the Ideal gas equation, PV = nRT
Given: P = 1.58 atm, V = ?, n = 1 mole, R = 0.082, T= 13 + 273K = 286K
Substituting all the given parameters,
V = \(\frac{nRT}{P}\)
V = \(\frac{1\times0.082\times286}{1.58}\)
V = 14.84 dm\(^3\)
Source: Myschool Past Questions Archive (Record #70450)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
If a salt weighs 2g and upon exposure to the atmosphere weighs 1.5g, this is as a result of
A
hygroscopy
B
effervescence
C
efflorescence
D
deliquescence
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
If a salt weighs 2g and upon exposure to the atmosphere weighs 1.5g, it simply means it has lost some moisture content from it. This process is called efflorescence.
Efflorescence is the process by which a hydrated salt loses water spontaneously when the aqueous vapour pressure of the hydrate is greater than the partial pressure of water vapour in the air. This causes the salt to lose all or part of its water of hydration, resulting in a powdery appearance on its surface.
Source: Myschool Past Questions Archive (Record #70451)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
The compound of Copper used as a fungicide is
A
CuCO\(_3\)
B
Cu(NO\(_3\))\(_2\)
C
CuSO\(_4\)
D
CuCl\(_2\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
CuCO\(_3\), is primarily used as a pigment in paints, ceramics, and fireworks due to its distinctive green colour, and is also utilized in agriculture as a fungicide and pesticide, as well as in some industrial applications like wood preservation and catalyst production; essentially, its main uses are as a colourant and in various chemical reactions as a precursor to other copper compounds.
Cu({NO\(_3\)})2, also known as copper(II) nitrate, is primarily used as a source of copper ions in various applications, including: catalysis in organic chemistry, electroplating, textile dyeing, ceramic glazes, pyrotechnics, analytical chemistry, and as a component in some metal patinas;
CuSO\(_4\), also known as copper sulphate, is primarily used as a fungicide and algaecide in agriculture, controlling unwanted fungi and algae on crops, as well as in water systems like ponds and aquariums; it can also be used as a pesticide to kill snails and slugs, and in some cases as a soil additive to correct copper deficiencies in the soil.
CuCl\(_2\), also known as Copper(II) chloride, is primarily used as a catalyst in chemical reactions, including applications in the textile industry as a mordant, in the petroleum industry as a deodorizer and purifying agent, as a wood preservative, and in photography as a fixer;
Source: Myschool Past Questions Archive (Record #70452)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
The percentage of hydrogen in the sixth member of the class of the aliphatic alkanes is [H =1, C =12 ]
A
41.34
B
59.54
C
16.28
D
83.72
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The sixth member of the class of the aliphatic alkanes is Hexane with the molecular formular C\(_6\)H\(_{14}\)
Percentage by mass of Hydrogen = \(\frac{mass of Hydrogen in compound}{Total mass of compound}\)\(\times 100\)
Total mass of compound, C\(_6\)H\(_{14}\) = (12 x 6) + (1 x14) = 72 + 14 = 86
Mass of Hydrogen in compound = 14(H) = 14\(\times 1\) = 14
% mass of H = \(\frac{14}{86}\)\(\times 100\)
= 16.28%
Source: Myschool Past Questions Archive (Record #70453)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
The law which states that a pure chemical compound, no matter how it is made, will be made up of the same elements contained in the same proportion by mass is
A
law of conservation of masses
B
law of definite proportion
C
law of multiple proportion
D
law of reciprocal proportion
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The law of definite proportions, also known as the law of constant composition, states that a pure chemical compound will always contain the same elements in the same proportion by mass, regardless of how it is made.
This law is true for any sample of a compound, regardless of its amount or phase (solid, liquid, or gas).
Source: Myschool Past Questions Archive (Record #70454)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
The stability of atomic nucleus is determined by ratio of
A
Neutron/electron
B
Neutron/proton
C
positron/neutron
D
electron/proton
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Stability of an isotope can be determined by calculating the ratio of neutrons to protons present in a nucleus. Elements having atomic number less than 20, mostly have proton and neutron ratio 1:1.
Source: Myschool Past Questions Archive (Record #70455)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
25.0g of potassium chloride were dissolved in 80g of distilled water at 30\(^0\)C. Calculate the solubility of the solute in mol dm\(^3\). [K =39, Cl = 35.5]
A
3.9 moldm\(^3\)
B
4.6 moldm\(^3\)
C
4.0 moldm\(^3\)
D
4.2 moldm\(^3\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Solubilty = \(\frac{number of moles}{Volume of solvent}\)\(\times 1000\)
Number of moles of KCl = \(\frac{mass}{Molar mass}\)
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol, mass = 25.0g
Number of moles of KCl = \(\frac{25}{74.5}\) = 0.336 mole
Solubilty = \(\frac{0.336}{80}\)\(\times 1000\)
= 4.2 moldm\(^3\)
Source: Myschool Past Questions Archive (Record #70456)