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Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
The knowledge of surface tension is applied in the following areas except in
A
manufacturing of rain coats
B
production of palm oil
C
floating of a needle on water
D
washing of plates with soapy water
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35743)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
A body is projected vertically upwards with a speed of 10 ms-1 from a point 2m above the ground. Calculate the total time taken for the body to reach the ground. [g = 10ms-2]
A
1.00s
B
2.00s
C
2.18s
D
3.00s
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
T = \(\frac{2u}{g} = \frac{2 \times 10}{10} = 2s\)
Source: Myschool Past Questions Archive (Record #35744)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
The change of state from solid to liquid occurs
A
at constant temperature
B
when temperature is lower than the boiling point
C
when temperature is just near freezing point
D
when temperature is equal to the boiling point
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35754)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Diagram
Solution
The diagram above illustrates a uniform metre rule which is balanced on a pivot by some masses. Calculate the value of M
Attached Figure / Diagram
A
500.0g
B
400.0g
C
44.4g
D
25.0g
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
clockwise moment = Anti-clock wise moment
= M x 40 = 100 x 10
M = \(\frac{1000}{40}\)
= 25g
Source: Myschool Past Questions Archive (Record #35746)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
The period of a simple pendulum X is 5s. What is the period of a simple pendulum Y which makes 50 vibrations in the same time it takes X to make 20 vibrations?
A
12.5s
B
2.5s
C
2.0s
D
1.2s
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
It takes X 5s for 1 complete vibration.
⇒ It takes X (5 x 20)s for 20 vibrations.
= 100s.
It takes Y 100s for 50 vibrations.
⇒ The period of Y = \(\frac{100}{50}\)s
= 2s.
Source: Myschool Past Questions Archive (Record #35747)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
A body of mass M kg rests on a plane inclined at an angle \(\theta\) to the horizontal. The component of the weight of the body parallel to the plane is
A
Mg sin \(\theta\)
B
Mg cos \(\theta\)
C
Mg tan \(\theta\)
D
Mg sec \(\theta\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35756)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
The quality of a note depends on its
A
frequency
B
pitch
C
overtones
D
amplitude
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35760)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
A fish inside a pond appears to be at a depth of 1.5m when viewed vertically from above. The refractive index of the water in the pound is 1.3. Calculate the apparent displacement of the fish
A
2.50m
B
1.95m
C
1.50m
D
0.45m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Real depth = n x apparent depth
= 1.3 x 1.5 = 1.95m
Apparent displacement = 1.95 - 1.5 = 0.45m
Source: Myschool Past Questions Archive (Record #35766)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
An ammeter can be adapted to measure potential difference by using a
A
shunt
B
multiplier
C
rheostat
D
resistance box
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35769)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
A 15 \(\mu F\) capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [\(\pi = 3.142\)]
A
16\(\Omega\)
B
68\(\Omega\)
C
106\(\Omega\)
D
212\(\Omega\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(X_c = \frac{1}{2 \pi fc}\)
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)
Source: Myschool Past Questions Archive (Record #35775)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Which of the following statements is the major advantage of nuclear fusion over nuclear fission?
A
nuclear fusion releases more energy
B
more neutrons are released in fusion than in fission
C
fussion does not release as much dangerous radiation as fission
D
fusion reactions occur more readily than fission
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35782)
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
You are provided with a potentiometer AB, a 102\(\Omega\) standard resistor R, a battery of emf 4.5V, a jockey J, and other necessary materials.
Connect a circuit as shown in the diagram above.
Close key K. Without J making contact with AB, read and record the ammeter reading I. Open the key.
Use the jockey to make contact with AB at the 20cm mark such that AJ = x = 20cm. Close the key, read and record the ammeter reading.
Evaluate x\(^{-1}\).
Repeat the procedure for values of x= 35cm, 45cm, 60cm, and 80cm respectively.
Tabulate your readings.
Plot a graph with x\(^{-1}\) on the vertical axis and \(l_i\) on the horizontal axis, starting both axes from the origin (0, 0).
Determine the slope, s, of the graph.
From your graph, determine the value \(l_o\) of \(I_1\) for which x\(^{-1}\)= 0.
Evaluate \(\frac{I_{o}}{I}\).
State two precautions taken to obtain accurate results.
(b)i. Define the emf of a battery.
ii. A cell X of emf 1.018V is balanced by a length of 50.0cm on a potentiometer wire. Another cell Y is balanced by a length of 75.0cm on the same wire. Calculate the emf of Y.
A
increase sharply
B
decrease slightly
C
remains the same
D
increase gradually
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Electricity
I = 0.36A
\(\frac{x}{cm}\)
\(\frac{I}{A}\)
\(\frac{X^{-1}}{cm^{-1}}\)
20.0
1.14
0.050
35.0
0.90
0.029
45.0
0.84
0.022
60.0
0.78
0.017
80.0
0.66
0.013
Slope (s) = \(\frac{\bigtriangleup {X}^{-1}}{\bigtriangleup {I}}\) = \(\frac{0.08-0.01}{1.68-0.644} = \frac{0.07}{1.036}\)
From the graph,
When X\(^{-1}\) = 0
\(I_0\) of \(I_1\) = 0.448A
x. Evaluate \(\frac{I_{0}}{I}\)
= \(\frac{0.448}{0.36}\) = 1.244
Precaution;
The key was opened when readings were not taken.
I ensured tight connections of the connecting wire
I avoided parallax errors when reading the potentiometer.
(bi) Define emf of a battery: The e.m.f of a cell is the potential difference across its terminals when it is in an open circuit. i.e. not Supplying current to an external circuit.
ii. A cell x emf is 1.018V.
Lengt\(h_1\) on the potentiometer x = 50.0cm
Lengt\(h_2\) on the potentiometer, y,= 75.0cm
A cell Y emf is?
Solution
By formula;
\(\frac{E_{1}}{E_{2}}\) = \(\frac{L_{2}}{L_{1}}\)
\(\frac{1.018}{E_{2}} = \frac{75.0}{50.0}\)
75.\(E_2\) = 1.018 x 50
\(E_2\) = \(\frac{1.018\times 50}{75}\)
\(E_2\) = 0.612V.
see graph above
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2014
Heat Energy & Temperature
Solution
A particle is projected horizontally at 10 ms\(^{-2}\) from the top of a tower 20 M high. Calculate the horizontal distance travelled by the particle when it hits the level ground. [g= 10 ms\(^{-2}\)
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
R = U\(\sqrt{\frac{2H}{g}} = 10\sqrt{\frac{2 \times 20}{10}}\) = 20
Source: Myschool Past Questions Archive (Record #53061)
Physics
UTME / JAMB 2013
Heat Energy & Temperature
When a brick is taken from the earth's surface to the moon, its mass
A
remains constant
B
reduces
C
increases
D
becomes zero
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27107)
Physics
UTME / JAMB 2013
Heat Energy & Temperature
Solution
The pair of physical quantities that are scalar only are ?
A
volume and area
B
moment and momentum
C
length and displacement
D
Impulse and time
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
This is because volume and the area have only magnitude but no direction
Source: Myschool Past Questions Archive (Record #27115)