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Physics
NECO SSCE 2005
Electricity and Magnetism
The charge of an alpha particle can be neutralized by
A
1 beta particle
B
2 photons of gamma rays
C
2 beta particles
D
4 beta particles
E
4 photons of gamma rays
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43025)
Physics
NECO SSCE 2005
Electricity and Magnetism
An electric motor primary converts
A
electrical energy to chemical energy
B
electrical energy to heat energy
C
electrical energy to mechanical energy
D
mechanical energy to electrical energy
E
mechanical energy to light energy
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43033)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
An a.c circuit of e.m.f 12V has a resistor of resistance 8Ω connected in series to an inductor of inductive reactance 16Ω and a capacitor capacitive reactance 10Ω. The current flow in the circuit is
A
1.4A
B
1.2A
C
12.0A
D
14.0A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Current (I) in the circuit = V/Z
But z =
\sqrt R2 + (XL - XC)2
=
\sqrt 82 + (16 – 10) 2
=
\sqrt 64 + 36
=
\sqrt 100 = 10Ω
∴ Current (I) = V/Z = 12/10 = 1.2 A
Source: Myschool Past Questions Archive (Record #12788)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
A moving coil galvanometer has a full-scale deflection of 3A equivalent to 30o deflection. The sensitivity of the instrument is
A
33.0
B
0.1
C
90.0
D
10.0
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The sensitivity of a measuring instrument is given by deflection per unit current: and given that deflection = 30º; and current (I) = 3A: then the sensitivity of the meter = 30/3 = 10.0
Source: Myschool Past Questions Archive (Record #12791)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
In a reverse biased junction diode, current flows in by
A
positive holes alone
B
majority carriers
C
electron alone
D
minority carriers
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
In a reverse biased junction diode only a very small current flows in, carried by the minority carriers which are the negative charges in the n-semi conductor
Source: Myschool Past Questions Archive (Record #12793)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
If 16mA of current flows through a conductor in one second, the number of electron transported per seconds is
[1 electronic charge = 1.6 x 10-19C]
A
1.00 x 1020
B
2.56 x 10-18
C
2.56 x -17
D
1.00 x 1017
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Current (I) = q/t → q = i x t
= 16 x 10-3 x 1
= 1.6 x 10-2C
But 1.6 x 10-19C = I electronic charge
1 coulomb = 1 / (1.6x10-19)
∴ 1.6 x 10-2 coulombs = 1 / (1.6x10-19) x 1.6x10-2 / 1
= 1.0 x 10-2 x 1019
= 1.0 x 1017
Source: Myschool Past Questions Archive (Record #12802)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
To protect a material from the influnce of an external magnetic field, the materials should be kept
A
square steel ring
B
triangular zinc ring
C
soft iron ring
D
loop of copper wire
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
In order to protect a material from the influence of an external magnetic field, the material is placed in a soft iron ring, usually referred to as magnetic screening.
Source: Myschool Past Questions Archive (Record #12806)
Physics
WAEC / WASSCE 2004
Electricity and Magnetism
Charges on a conductor are
A
evenly distributed over a surface of any shape
B
concentrate on the inner surface of the conductor
C
concentrate at the outer flat surface of the conductor
D
generally concentrated at sharply curved surface
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #34387)
Physics
WAEC / WASSCE 2004
Electricity and Magnetism
Solution
A car fuse marked 3A operates optimally on a 12V battery, calculate the resistance of the fuse
A
36.0\(\Omega\)
B
15.0\(\Omega\)
C
9.0\(\Omega\)
D
4.0\(\Omega\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
R = \(\frac{v}{I} = \frac{12}{3} = 4\Omega\)
Source: Myschool Past Questions Archive (Record #34393)
Physics
WAEC / WASSCE 2004
Electricity and Magnetism
The quantity of electric charge stored in a capacitor is measured in
A
farad
B
ampere
C
coulomb
D
volt
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #34397)
Physics
WAEC / WASSCE 2004
Electricity and Magnetism
An atom is normally electrically neutral because the
A
number of electrons is equal to the number of protons
B
number of electrons is equal to the number of neutrons
C
number of protons is equal to the number of neutrons
D
electrons of the atom are buried deeply in the nucleus
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #34405)
Physics
WAEC / WASSCE 2004
Electricity and Magnetism
In which of the following devices is the principle of photoelectric effect not applicable?
A
close-circuit television camera
B
burglar alarm
C
solar cells
D
periscope
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #34406)
Physics
UTME / JAMB 2004
Electricity and Magnetism
Solution
A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is
A
1.250V
B
2.000V
C
8.000V
D
0.125V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E = V + v
where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.
But from ohm's law V=IR ; v = Iv
\( \implies \) lost voltage = V = Ir
= 4 x 0.5
= 2.0v
Source: Myschool Past Questions Archive (Record #41446)
Physics
NECO SSCE 2004
Electricity and Magnetism
Which of these expresses the relationship between the earth’s magnetic field FE, and the field’ FB due to a magnet at neutral points? FE is
A
equal and opposite to FB
B
equal to and in the same direction with FB
C
greater than and in the same direction with FB
D
greater than and opposite to FB
E
less than and opposite to FB
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #42951)
Physics
NECO SSCE 2004
Electricity and Magnetism
When the same amount of current, I is passed through different wires under the same conditions, the rates of production of heat are
A
directly proportional to I
B
directly proportional to the resistances of the wires
C
directly proportional to the square of the resistances of the wires
D
inversely proportional to I
E
inversely proportional to the resistance of the wires
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #42985)