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Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
The main constituent of water-glass is
A
calcium trioxosilicate(IV)
B
calcium trioxosulphate(IV)
C
sodium trioxosulphate(IV)
D
sodium trioxosilicate(IV)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Water glass, also known as sodium silicate or alkali silicate glass, is a glassy solid made up of sodium oxide (Na\(_2\)O) and silica (silicon dioxide, SiO\(_2\)).
Source: Myschool Past Questions Archive (Record #70402)
Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
Which of the following represents an order of increasing reactivity?
A
Au < Cu < Sn < Fe < Ca
B
Ca < Fe < Sn < Cu < Au
C
Au < Cu < Fe < Sn < Ca
D
Ca < Sn < Fe < Cu < Au
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The order of reactivity of metals, from most to least reactive, is:
Potassium: Most reactive and easily forms positive ions
Sodium: Second most reactive
Lithium: Third most reactive
Calcium: Fourth most reactive
Magnesium: Fifth most reactive
Aluminum: Sixth most reactive
Zinc: Seventh most reactive
Iron: Eighth most reactive
Tin: Ninth most reactive
Lead: Tenth most reactive
Hydrogen: Eleventh most reactive
Copper: Twelfth most reactive
Silver: Thirteenth most reactive
Gold: fourteenth most reactive
Platinum: Fifteenth most reactive
Source: Myschool Past Questions Archive (Record #70403)
Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
An oxide of nitrogen that can rekindle a glowing splint is
A
nitrogen(I)oxide
B
nitrogen(II)oxide
C
nitrogen(IV)oxide
D
dinitrogen tetraoxide
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Nitrogen(I)oxide (nitric oxide) rekindles a brightly glowing splint just like oxygen does. This similarity is because both nitric oxide and oxygen support combustion.
Source: Myschool Past Questions Archive (Record #70412)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
In a chemical reaction, surface area of reactants can affect
A
CaCO\(_3\) + 2HCl → CaCl\(_2\) + H\(_2\)O + CO\(_2\)
B
MgCl\(_2\) + H\(_2\)SO\(_4\) → MgSO\(_4\) + 2HCl
C
H\(_2\) + Cl\(_2\) → 2HCl
D
NaOH + HCl → NaCl + H\(_2\)O
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The surface area of reactants affects the rate of a reaction between limestone and hydrochloric acid because it increases the number of collisions between the particles of the reactants. For example, if you have a large marble chip of calcium carbonate and hydrochloric acid, the acid can't reach all the calcium carbonate in the middle of the chip. If you break the marble chip into smaller pieces, you'll have a larger surface area for the acid to react with, and the reaction will happen faster.
Source: Myschool Past Questions Archive (Record #70416)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
C\(_2\)H\(_{4(g)}\) + 3O\(_{2(g)}\) → 2CO\(_{2(g)}\) + 2H\(_2\)O\(_{(g)}\)
The above equation represents the combustion of ethene.If 10cm\(^3\) of ethene is burnt in 50cm\(^3\) of oxygen, what would be the volume of oxygen that would remain at the end of the reaction?
A
20cm\(^3\)
B
40cm\(^3\)
C
60cm\(^3\)
D
50cm\(^3\)
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Gay Lussac’s Law of Combining Volumes states that when gases react, they do so in volumes which bear a simple ratio to one another, and to the volume of the product(s) formed if gaseous, provided the temperature and pressure remain constant.
C\(_2\)H\(_{4(g)}\) + 3O\(_{2(g)}\) → 2CO\(_{2(g)}\) + 2H\(_2\)O\(_{(g)}\)
1 mole : 3 moles
Total volume required: 10 cm\(^3\) 50 cm\(^3\)
Reacted Volume: 10 cm\(^3\) 30 cm\(^3\)
Residual volume: 0 (50 - 30) = 20 cm\(^3\)
Source: Myschool Past Questions Archive (Record #70417)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
The hybridization scheme in ethyne is
A
sp
B
sp\(^3\)
C
sp\(^2\)d
D
sp\(^2\)s
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The hybridization scheme in ethyne is sp. In ethyne, each carbon atom's 2s orbital combines with one of its 2p orbitals to form two sp hybrid orbitals. The frontal lobes of these orbitals face away from each other, resulting in a straight line.
Source: Myschool Past Questions Archive (Record #70418)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
An organic compound with general formula RCOR' is an
A
alkanone
B
alkanal
C
alkanoate
D
alkanoic acid
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
An organic compound with the general formula RCOR' is an alkanone, which is a type of ketone.
Ketones: Have the general formula RCOR' and contain a carbonyl group, which is a carbon atom double-bonded to an oxygen atom.
Source: Myschool Past Questions Archive (Record #70419)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
The amount of Faraday required to discharge 4.5 moles of Al\(^{3+}\) is
A
13.5
B
4.5
C
7.5
D
1.5
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Firstly, Al\(^{3+}\) + 3e\(^-\) → Al
1 mole of Al = 1F X 3e\(^-\)
1mole = 3F
4.5moles = X
X = 4.5 X 3 = 13.5 F
Source: Myschool Past Questions Archive (Record #70420)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
The reaction between alkanoic acids and alkanols in the presence of an acid catalyst is known as
A
saponification
B
dehydration
C
esterification
D
hydrolysis
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The reaction between alkanoic acids and alkanols in the presence of an acid catalyst is called esterification:
Esterification is a chemical reaction that combines an alcohol (ROH) and an organic acid (RCOOH) to form an ester (RCOOR) and water. The reaction can be catalyzed by an acid or a base.
Source: Myschool Past Questions Archive (Record #70421)
Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
C\(_x\)H\(_y\)O + 5O\(_2\) → 4CO\(_2\) + 4H\(_2\)O
C\(_x\)H\(_y\)O in the equation is
A
CH\(_2\)O
B
C\(_2\)H\(_6\)O
C
CH\(_4\)O
D
C\(_2\)H\(_4\)O
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
C\(_x\)H\(_y\)O + 5O\(_2\) → 4CO\(_2\) + 4H\(_2\)O
On balancing the equation, we should have
X = 4 , y = 8 and O = 2 ⇒ C\(_4\)H\(_8\)O\(_2\)
Since 2 is a common factor to the three atoms, we can divide through by 2, considering the fact that that formula is not in the option.
We finally have C\(_2\)H\(_4\)O
Source: Myschool Past Questions Archive (Record #70429)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
Alkylation of benzene is catalyzed by
A
palladium
B
nickel
C
sunlight
D
aluminium chloride
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Alkylation is the process of substituting an alkyl group into a benzene ring, replacing a hydrogen on the ring with a group like methyl or ethyl.
Alkylation of benzene can be catalyzed by a number of substances, including:
Aluminum chloride: A common catalyst for the Friedel-Crafts alkylation of benzene. Aluminum chloride acts as a Lewis acid, coordinating with halogens to generate an electrophile.
Fluorinated alumina: Catalyzes the alkylation of benzene with propylene.
Methyl- and ethylsilanes: Catalyze the alkylation of benzene with ethylene and propylene.
Acidic zeolite catalysts: Such as mordenite, which can be used to alkylate benzene with 1-dodecene.
Boron trifluoride: Catalyzes the alkylation of benzene with 2-propanol, forming a carbocation intermediate that attaches to the benzene ring
Source: Myschool Past Questions Archive (Record #70432)
Chemistry
UTME / JAMB 2024
Matter & Separation Techniques
Solution
Benzene formed nitrobenzene at temperature of 60\(^0\)C when it reacts with mixture of concentrated trioxonitrate(V) acid and concentrated
A
phosphoric acid
B
hydrochloric acid
C
tetraoxosulphate(VI) acid
D
hydrogen iodide
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Benzene reacts with a mixture of concentrated nitric acid and concentrated sulphuric acid to form nitrobenzene at a temperature not exceeding 60^\circC. The reaction is known as the nitration of benzene.
Source: Myschool Past Questions Archive (Record #70434)
Chemistry
UTME / JAMB 2024
Stoichiometry & Mole Concept
Solution
The general molecular formula C\(_n\)H\(_{2n-2}\) represents that of an
A
alkyne
B
alkene
C
alkane
D
alkanal
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The general molecular formula C\(_n\)H\(_{2n-2}\) represents that of an alkyne with its first member as ethyne
Source: Myschool Past Questions Archive (Record #70439)
Chemistry
UTME / JAMB 2024
Atomic Structure and Periodic Table
Solution
What accounts for the low melting and boiling points of covalent molecules?
A
They have weak intermolecular forces.
B
They are three-dimensional structures.
C
They have definite shapes.
D
They possess shared electron pairs
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Covalent molecules have low melting and boiling points because of their weak intermolecular forces.The force of attraction between the molecules in a covalent compound is weak, so it takes little energy to break the bonds.
Yes, all covalent compounds have a three-dimensional structure due to the directional nature of covalent bonds, which means the atoms within a molecule are arranged in a specific spatial orientation, giving the molecule a definite shape in three dimensions; this is explained by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
Source: Myschool Past Questions Archive (Record #70440)
Chemistry
UTME / JAMB 2024
Acids, Bases, and Salts
Solution
After breathing in a test tube that contains acidified K\(_2\)Cr\(_2\)O\(_7\), a man noticed the change in the colour of K\(_2\)Cr\(_2\)O\(_7\) from orange to green. This suggests the presence of
A
alkanone
B
alkanal
C
alkanol
D
alkanoic acid
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
When an alcohol is oxidized in a warm solution of potassium dichromate (VI) and dilute sulphuric acid, the solution changes colour from orange to green. This is because the Cr\(_2\)O\(_7\)\(^{2-}\) ions in the solution are reduced to Cr\(^{3+}\) ions. This colour change can be used to identify alcohols. Only alcohols will cause the solution to change colour from orange to green.
Source: Myschool Past Questions Archive (Record #70441)