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Chemistry
UTME / JAMB 2007
Oxidation, Reduction & Redox Reactions
Solution
The oxidation state of oxygen in tetraoxosulphate (VI) acid is
A
-4
B
-2
C
+4
D
-8
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
H2SO4
(O.N of hydrogen * 2 ) + O.N of sulphur + O.N of oxygen * 4 = 0
∴ 1 * 2 + 6 + 4x = 0
2 + 6 + 4x = 0
8 + 4x = 0
4x 0 - 8 = -8
4x = -8
x = -8/4 = -2
Source: Myschool Past Questions Archive (Record #3831)
Chemistry
UTME / JAMB 2007
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
MnO\(_2\)(s) + xHCl(aq) → MnCl\(_2\)(aq) + yH\(_2\)O(l) + zCl\(_2\)(g)
In the equation above, what are the values of x, y and z respectively
A
2, 1, 2
B
4, 1, 2
C
4, 2, 1
D
1, 2, 1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
MnO\(_2\)(s) + xHCl(aq) → MnCl\(_2\)(aq) + yH\(_2\)O(l) + zCl\(_2\)(g)
First, balance the chemical equation, then equate each of the letters with the coefficients.
On balancing, we have : MnO\(_2\)(s) + 4HCl(aq) → MnCl\(_2\)(aq) + 2H\(_2\)O(l) + Cl\(_2\)(g)
Therefore, x = 4,y = 2 and z = 1
Source: Myschool Past Questions Archive (Record #3834)
Chemistry
UTME / JAMB 2007
Kinetic Theory of Matter & Gas Laws
Solution
Calculate the mass of chlorine gas which occupies a volume of 1.12dm3 at s.t.p
[Cl = 35.5, molar volume of gas at s.t.p = 22.4 dm3
A
15.50 g
B
7.10 g
C
3.55 g
D
1.80 g
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
2 * 35.5g of chlorine has a volume of 22.4 dm3 at s.t.p
∴ xg of chlorine will have a volume of 1.12 dm3
x = (1.12 * 35.5 * 2)/22.4 = 3.55g
Source: Myschool Past Questions Archive (Record #3838)
Chemistry
UTME / JAMB 2007
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Which experiment led to the measurement of the charge on an electron?
A
Mass spectrometric experiment
B
Oil-drop experiment
C
Scattering α - particles
D
Discharge-tube experiment
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In 1909, Robert Millikan and Harvey Fletcher conducted the oil drop experiment to determine the charge of an electron.
Source: Myschool Past Questions Archive (Record #3841)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
What is the volume of oxygen required to burn complete 45 cm\(^3\) of methane at s.t.p?
A
135.0 cm3
B
180.0 cm3
C
45.0 cm3
D
90.0 cm3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
CH\(_4\)(g) + 2O\(_2\)(g) → 2H\(_2\)O(g) + CO\(_2\)(g)
First, ensure the chemical equation is balanced, stoichiometrically.
i.e CH\(_4\) reacts with 2O\(_2\) in ratio 1 : 2
If 1 mole of CH\(_4\) reacts with 2 moles of O\(_2\)
Then 45 cm\(^3\) CH\(_4\) react with X cm\(^3\) O\(_2\)
i.e 1cm\(^3\) = 2cm\(^3\)
45cm\(^3\)= X cm\(^3\)
X = 45 x 2 = 90 cm\(^3\)
Source: Myschool Past Questions Archive (Record #3844)
Chemistry
UTME / JAMB 2007
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
How many electrons are in the L shell of \(^{31}_{15}\)P?
A
5
B
8
C
18
D
2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
N.B :
Atomic number = no. of protons = no. of electrons = 15
Orbital configuration of the neutral atom of the element = 2, 8, 5 which represents the shells starting from the first which is K, L, M respectively. i.e
K = 2, L = 8 , M = 5.
Therefore, the L - shell has 8 electrons.
Source: Myschool Past Questions Archive (Record #3845)
Chemistry
UTME / JAMB 2007
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
If the electron configuration of an element is 1S\(^2\) 2S\(^2\)2P\(^5\), how many unpaired electron are there?
A
2
B
8
C
1
D
4
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
When the electrons are drawn out in the orbitals, following the Hund's rule, the diagram above is what will be obtained.
Source: Myschool Past Questions Archive (Record #3849)
Chemistry
UTME / JAMB 2007
Periodic Table & Periodicity
Solution
Which of the following decrease when a given mass of gas is compressed to half its initial volume?
A
Atomic radius of each
B
Average intermolecular distance
C
Frequency of collisions
D
Number of molecules presents
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
When a gas is compressed to half its volume, the average intermolecular distance decreases because the same number of gas molecules are now confined to a smaller space, forcing them closer together, resulting in a smaller average distance between each molecule.
Conversely, when the volume of a gas is reduced, the frequency of collisions between molecules increases; this is because the molecules have less space to move around, leading to more frequent interactions with each other and the container walls.
Source: Myschool Past Questions Archive (Record #3853)
Chemistry
UTME / JAMB 2007
Metals, Transition Elements & Extraction
Solution
A metal X forms two bromides with the formulae XBr2 and XBr3. What type of bonding exists between X and bromine in the bromide?
A
Ionic bonding
B
Metallic bonding
C
Dative bonding
D
Covalent bonding
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
If the metal X forms two bromides with the formulae XBr\(_2\) and XBr\(_3\), it simply means it has variable oxidation number or states which is one of the characteristics of transition metals. This implies X is a metal. However, whenever a metal combines with a non-metal, there is usually a transfer of electrons from the metals to the non-metals, and the type of bond formed is the ionic or electrovalent bond.
Source: Myschool Past Questions Archive (Record #3859)
Chemistry
UTME / JAMB 2007
Nature of Matter & Separation Techniques
Solution
A mixture of petrol and water can be separated through
A
centrifugation
B
distillation
C
the use of separating funnel
D
the use of filter paper
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Petrol and water are immiscible liquids, so the best method of separation of petrol and water is by a separating funnel.
Source: Myschool Past Questions Archive (Record #3860)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
Which of the following represents an aromatic compound?
A
C6H5OH
B
C6H12
C
C6H9OH
D
C6H8
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Aromatic compounds are chemical compounds that consist of conjugated planar ring systems accompanied by delocalized pi-electron clouds in place of individual alternating double and single bonds. In a simpler term, aromatic compounds are compounds of Benzene and its derivatives.e.g Benzene, Phenol, Toluene, xylene, anthracene, Naphthalene etc all cyclically conjugated.
The compound in option A is called phenol - a benzene ring with an hydroxyl group (OH) attached to C-1.
Source: Myschool Past Questions Archive (Record #3861)
Chemistry
UTME / JAMB 2007
Acids, Bases, pH & Salts
Solution
CH\(_3\)CH\(_2\)Cl + KCN → CH\(_3\)CH\(_2\)CN + KCl
In the reaction above, the cyanide is
A
hydrophobic
B
hydrophilic
C
nucleophilic
D
electrophilic
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
A nucleophile is considered an electron donating species, meaning it readily donates an electron pair to form a bond with another molecule, typically an electrophile, in a chemical reaction; essentially acting as a Lewis base.
CN\(^-\) (cyanide ion) is considered a nucleophile. This is because it has a negative charge and a lone pair of electrons that it can donate to form a bond with a positively charged species, making it an electron-rich species characteristic of nucleophile.
Conversely, an electrophile is a chemical species that forms bonds with nucleophiles by accepting an electron pair. Because electrophiles accept electrons, they are Lewis acids.
Source: Myschool Past Questions Archive (Record #3866)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
Which of the following compounds is the best possible anti-knock agent for petrol?
A
(CH3)2CH - CH(CH3)CH2CH3
B
CH3CH2(CH3)CHCH2CH2CH3
C
CH3CH2(CH3)CHCH2CH2CH3
D
(CH3)3C - CH2CH2CH3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
An "anti-knock agent" for petrol (or gasoline) is a chemical additive that is added to fuel to prevent engine knocking, which is a knocking sound produced by premature ignition in the combustion chamber, and essentially increases the fuel's octane rating by delaying ignition.
Option A - 2,3- dimethylpentane
Option B - 3-methylhexane
Option C - 3-methylhexane
Option D - 2,2-dimethylpentane
Both 2,3-dimethylpentane and 2,2-dimethylpentane are branched-chain structures. However, 2,2-dimethylpentane has a more compact, highly branched structure, which is generally associated with higher octane ratings and better anti-knock properties.
In contrast, 2,3-dimethylpentane has a slightly less branched structure, which may result in slightly lower octane ratings. So, while both compounds are branched, the degree of branching and the resulting octane rating can differ.
Source: Myschool Past Questions Archive (Record #3869)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
The hydrocarbon used in the production of styrene is
A
ethyne
B
propyne
C
ethane
D
ethene
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Styrene is produced from the monomer ethylbenzene through a process called dehydrogenation, where hydrogen is removed from ethylbenzene to create styrene; dehydrogenation of ethylbenzene, a compound obtained by reacting ethylene and benzene. However, ethylene is also known as ethene.
Source: Myschool Past Questions Archive (Record #3870)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
How many structural isomers of chlorobutane are possible?
A
4
B
3
C
2
D
1
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The structural isomers of chlorobutane are: 1-chlorobutane, 2-chlorobutane, 1-chloro-2-methylpropane, and 2-chloro-2-methylpropane; in total, there are four structural isomers of chlorobutane.
Explanation:
1-chlorobutane: Chlorine is attached to the first carbon of a straight carbon chain.
2-chlorobutane: Chlorine is attached to the second carbon of a straight carbon chain.
1-chloro-2-methylpropane: A methyl group is attached to the second carbon of a propane chain, with chlorine on the first carbon.
2-chloro-2-methylpropane: Chlorine is attached to a carbon that is also connected to two methyl groups.
Source: Myschool Past Questions Archive (Record #3980)