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Chemistry
WAEC / WASSCE 2008
Chemical Bonding & Intermolecular Forces
Solution
(a)(1) Define covalent bond.
(ii) Give two properties of covalent compounds
(ii) With the aid of a diagram, show how ammonia molecule is formed
(iv) Illustrate with a diagram the formation of ammonium ion?
(v) What type of bond(s) exist(s) in I. ammonia, H. ammonium ion? (\(_1\)H\(_7\)N)
(b)(i) Write three subatomic particles with their corresponding relative masses. CH\(_2\)OH
(ii) Name the possible states in which water can exist.
(c) (i) State Graham's law of diffusion
(ii) Arrange the following gases, He, CH\(_4\) and N\(_2\) in order of increasing rates of diffusion. Give a reason for the order. [ H = 1, He = 4, C = 12, N = 14 ]
(d) Draw the structures of the following compounds:
(i) 2,3-dimethylbutane;
(ii) 1,4-dibromocyclohexane.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Covalent bond is a bond between two atoms in which each of the atoms contribute to the shared pair of electrons.
(ii) (a) Non-conductors of electricity (b) Insoluble in water/soluble in non-polar solvents. (c) Have low melting or boiling point.
(v) (a) covalent bond (b) covalent bond dative or coordinate covalent bond
(b)
Particles
Relative Masses Proton
Proton
1
Neutron
1
Electron
1
1840
(c)(i) Graham's law of diffusion states that a constant temperature and pressure, the rate of diffusion of a gas is inversely proportional to the square root of its vapour density or molecular mass.
(ii) N\(_2\), CH\(_4\), He : the smaller the molecular mass the faster the rate at which the gas diffuses or the larger the molar mass the slower the rate at which the gas diffuses.
(d)
Source: Myschool Past Questions Archive (Record #52180)
Chemistry
WAEC / WASSCE 2008
Acids, Bases, pH & Salts
Solution
(a)(i) What are acidic oxides?
(ii) Give one example of each of the following oxides: I. acidic oxide; II. basic oxide; III. amphoteric oxide; IV. neutral oxide
(b)(i) Define each of the following terms; I. Heat II. Heat of neutralization
(ii) Weite the above an equation to illustrate each of the terms in (b)(i) above
(ii) Given that the standard heat of combustion of butane (C\(_4\)H\(_{(10)}\) is + 5877 kJmol\(^{-1}\), calculate the heat of 14.5 g butane. [ H = 1, = 12 ]
(c) (i) Name two allotropes of sulphur
(ii) State one difference between the two allotropes.
(d)(i) Give two characteristics of noble eases
(ii) State one use each of I. He; II. Ar.
(e) State what is observed on warming ammonium trioxonitrate (V) with sodium hydroxide.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Oxide of non-metals which dissolve in water to form acidic solution.
(ii) 1. Acidic oxides:- SO\(_2\)/CO\(_2\)/NO\(_2\), etc.
2. Basic oxides:- CaO/Na\(_2\)O/K\(_2\)O, etc.
3. Amphoteric oxides:- Al\(_2\)O\(_3\)/ZnO/PbO, etc.
4. Neutral oxides:- CO/N\(_2\)O, etc.
(b)(i) Heat of combustion is the heat change when one mole of a substance is completely burnt in oxygen or burnt in excess oxygen
(ii) Heat of neutralization is the heat change when one mole of water is produced as a result of a reaction between an acid and alkali in dilLte solution or the heat change when one mole of H+ from an acid reacts with one mole of OH\(^-\) from an alkali to form one mole of H\(_2\)O.
(ii)1. C\(_{(g)}\) + O\(_{2(g)}\) \(\to\) CO\(_{2(g)}\)
2. HaOH\(_{(aq)}\) + HCl\(_{(aq)}\) \(\to\) NaCI + H\(_2\)O\(_{(l)}\) \(\Delta\) Hn\(^o\)
3. Molar mass of C\(_4\)H\(_{10}\) = 12 x 4 + 1 x 10
= 48 + 10 = 58g mol\(^{-1}\) .
58g of C\(_4\)H\(_{10}\) = 5877kJ mol\(^{-1}\)
14.5 of C\(_4\)H\(_{10}\) = \(\frac{5877 \times 14}{58}\) kJ mol\(^{-1}\)
= + 1469.25 kJ.
(c)(i) Rhombic
Monoclinic
Rhombic
Monoclinic
Yellow translucent crystal
Transparent amber crystal
Stable at temperature below 96^\circC
Unstable at temperature below 96^\circC
Higher density than monoclinic
Lower density than rhombic
Lower melting point
Higher melting point
Octahedral shaped
Needle shaped.
(d)(i)(a) They are monoatomic gases
(b) They are chemically unreactive
(c) Have low melting/boiling point.
(ii) He — filling balloons. Ar — arc welding.
Source: Myschool Past Questions Archive (Record #52193)
Chemistry
WAEC / WASSCE 2008
Water, Solutions & Solubility
Solution
(a)(i) Define hard water
(ii) Name two substances responsible for hardness in water
(iii) Give two methods for the removal of hardness in water.
(b)(i) What are the raw materials require for the manufacture of tetraoxosulphate (VI) acid by the contact process?
(ii) Write an equation for tr reaction that requires a catalyst in the contact process (iii) State the catalyst used in (b)(ii).
(c)(i) Give two uses of sodium tetraoxosulphate (VI) Consider the reaction represented by the following equation:
Na\(_2\)SO\(_4\).10H\(_2\)O\(_{(s)}\) \(\to\) Na\(_2\)SO\(_4\).H\(_2\)O + 9H\(_2\)O\(_{(g)}\)
(ii) What name is given to this type of reaction?
(iii) Calculate the solubility of Na\(_2\)CO\(_3\) at 25^\circC. if 30.0 cm\(^3\) of its saturated solution at that temperature gave 1.80 g of the anhydrous salt. [C = 12, 0 = 16, Na = 23]
(d)(i) Define the term activated complex
(ii) State one reason why a collision may not produce a chemical reaction
(iii) The formation of water gas is represented by the following equation:
C\(_{(s)}\) + H\(_2\)O\(_{(g)}\) \(\to\) CO\(_{(g)}\) + H\(_{2(0)}\) \(\Delta\)H= + 131 kJmol\(^{-1}\)
Draw an energy profile diagram for the reaction showing the I. activated complex, II. enthalpy of reactants.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Hard water is water which will not readily form lather with soap.
(ii) 1. Calcium tetraoxosulphate (IV) 2. Calcium hydrogen trioxocarbonate (IV) 3. Magnesium tetraoxosulphate (VI) 4. Magnesium hydrogen trioxocarbonate (IV).
(iii)(a) Heating the water to boiling/distillation (b) Addition of calculated amount of calcium hydroxide [Ca(OH)\(_2\)] (c) Addition of washing soda crystals to the water [Na\(_2\)CO\(_3\)] (d) Ion exchange resin/permutit method.
(b)(i) Sulphur air or oxygen
(ii) 2SO\(_{2(g)}\) +O\(_{2(g)}\) \(\rightleftharpoons\) 2SO\(_{3(g)}\)
(iii) V\(_2\)O\(_5\) / Vanadium (V) oxide.
(c)(i) Use of Na\(_2\)SO\(_4\)
(a) Water softener (b) In glass or paper manufacturing (c) As analytical reagent (d) As purgative (e) In the manufacture of detergents .
(ii) Mass of salt per 30 cm\(^3\) of saturated solution = 1.80g.
1000 cm\(^3\) of saturated solution contains = \(\frac{1000 \times 1.80}{30}\)
= 60g.
Molar mass of Na\(_2\)CO\(_3\) = 23 x 2 + 12 x 1 + 16 x 3 = 106g.
Solubility of Na\(_2\)CO\(_3\) = \(\frac{60}{106}\) = 0.566 mole dm\(^3\).
(d)(i) Activated complex is the intermediate (complex) that reactants must attain in order to form a product or it is a temporary species formed by reactant molecules as a result of collision before the products are formed.
(ii) A collision may fail to produce a chemical reaction if the energy of the colliding particles is less than activation energy / if the reactant are not properly aligned.
Source: Myschool Past Questions Archive (Record #52202)
Chemistry
NECO SSCE 2008
Reaction Rates & Chemical Equilibrium
Solution
In which of the following equations can Le-chartelier’s principle be applied?
A
H2(g)+S(g) → H2(g)
B
2H2S(g) + O2 (g) → 2H2O(l) + 2SO2(g)
C
N2(g) +3H2(g)
⇌ 2NH3(g)
D
NaOH(aq) +CO2(g) → Na2CO3(aq) + H2O(l)
E
S(s) + 02(g) → SO2(g)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
According to Le Chatelier's Principle, this will be favored if you lower the temperature. The system will respond by moving the position of equilibrium to counteract this - in other words by producing more heat. To get as much ammonia as possible in the equilibrium mixture, you need as low a temperature as possible
Source: Official Exam / Past Question Archive
Chemistry
WAEC / WASSCE 2008
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
(a) In the laboratory preparation of crystals of CuSO\(_4\), a green powder Q was added to dilute H\(_2\)SO\(_4\), and stirred. Effervescence occurred and a gas R was given off which turned lime water milky. Excess Q was removed from the mixture. The solution of Cu\(_2\)SO\(_4\) was concentrated to half its original volume and allowed to stand.
(i) What is substance Q?
(ii) Name gas R
(ii) Why was excess Q used?
(iv) How would you know that the reaction is complete?
(v) What method was used to remove excess Q? (vi) Why was the solution of CusO\(_4\) not heated to dryness?
(b) Name the reagent(s) used for testing each of the following substances in the laboratory: (i) Water; (i) Primary alkanol.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
(a)(i) Q is copper (II) trioxocarbonate (IV)
(ii) R is carbon (IV) oxide
(iii) Excess Q was used to ensure that all the acid reacted
(iv) When there is no more effervescence.
(v) Filtration.
(b)(i) White anhydrous copper (II) teraoxosulphate (VI).
(ii) Alkaline iodine solution, or acidified potassium tetraoxomanganate (VIl).
Source: Myschool Past Questions Archive (Record #60031)
Chemistry
WAEC / WASSCE 2008
Nature of Matter & Separation Techniques
Solution
Credit will be given for strict adherence to the instructions, for observations precisely recorded, and for accurate inferences. All tests, observations, and inferences must be clearly centered in your answer book, at the time they are made.
C is a mixture of two salts. Carry outline following exercises on C. Record your observations and identify any gas(es) evolved. State the conclusion you draw from the result of each test.
(a) Put C into a beaker and add about 10 cm\(^3\) of distilled water, stir the mixture, and filter. Test the filtrate with litmus paper. Keep the residue and the filtrate.
(b)(i) To about 2 cm\(^3\) of the filtrate, add few drops of aqueous HNO\(_3\) followed by AgNO\(_{3(aq)}\)
(ii) Add excess NH\(_3\) solution to the resulting mixture.
(c) To about half of the residue from (a) above, add about 5cm\(^3\) of dilute HNO\(_3\) in drops. Divide the resulting solution into two equal portions.
(d)(i) To the first portion add ammonia solution in drops and then in excess.
(ii) To the second portion add dilute hydrochloric acid.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
Test
Observation
Inference
(a) C + water
Mixture
filtered
Filtrate 1 litmus
Partly dissolves
Colourless filtrate
white residue
No effect on litmus
C contains solution and
insoluble salts
Filtrate is neutral
(b)(i) Filtrate + dil. H\(_2\)SO\(_4\) + AgNO\(_{3(aq)}\)
(ii) Mixture in (b)(i)
+ excess NH\(_3\) soln
No reaction
white ppt
ppt dissolves
Cl\(^-\) present
Cl\(^-\) confirmed
(c) Residue + dil. HNO\(_3\)
Effervescence occurs, gas turns lime water milky
CO\(_2\)
CO\(_3^{2-}\) present
(d)(i) First portion + dil. NH\(_3\) in drops
then in excess
(ii) Second portion + dil. HCl
White ppt
ppt insoluble
White chalky ppt
Pb\(^{2+}\) may be present
Pb\(^{2+}\) present
Pb\(^{2+}\) confirmed
Source: Myschool Past Questions Archive (Record #60032)
Chemistry
WAEC / WASSCE 2008
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Burette readings(initial and final) must be given to two decimal places. Volume of pipette user must also be recorded but on account of experimental procedure is required. All calculations must be done in your answer book. A is O.050 mol dm\(^{-3}\) of acid HX. Bis a solution of NaOH containing 0.025 moles per 250 solutions.
(a) Put A into the burette and titrate it against 20.00 cm\(^3\) or 25.00 cm\(^3\) portions B using phenolphthalein as indicator. Tabulate your readings and calculate the average volume or A used.
(b) your results and the information provided above, calculate the;
(i) amount of acid in the average
(ii) amount of base in 20.00 cm\(^3\) or 25.00 cm\(^3\);
(iii) mole ratio of acid to base
(c) Write a balanced chemical equation for the reaction between the acid H\(_y\)X and the base NaOH
(d) State the basicity of the acid H\(_y\)X.
medium Difficulty
Verified Correct Answer: Option
Chemical Principles & Mechanism
Table of Result
Indicator used: Phenolphthalein
Volume of pipette = 25 cm\(^3\)
Burette Reading
Rough
1st
2nd
3rd
Final (cm\(^3\))
22.60
22.40
22.30
22.30
Initial (cm\(^3\))
0.00
0.00
0.00
0.00
Volume of acid used (cm\(^3\))
22.00
22.40
22.30
22.30
Average volume of acid used, V\(_A\) = \(\frac{22.40 + 22.30 + 22.30}{3}\)
= \(\frac{67.00}{3}\)
Average titre value = 22.30 cm\(^3\), V\(_A\)
(b)(i) Amount of acid in the average titre, V\(_A\)
1000 cm\(^3\) contains 0.05 moles
V\(_A\) will contain = \(\frac{0.05 \times 22.30}{1000}\)
= 0.0011 moles
(ii) Concentration of NaOH in B
\(\frac{0.025}{0.25}\) = 0.199 mol dm\(^{-3}\)
To calculate the amount of base in 25 cm\(^3\)
\(\frac{25 cm^3}{1000}\) x 0.100 mol dm\(^{-3}\) = 0.0025 moles
(iii) Mole ratio of acid (H\(_y\)X) to base (NaOH)
\(\frac{0.0011}{0.0025}\) = \(\frac{1}{2}\)
(c) Equation for the reaction
2NaOH + H\(_y\)X \(\to\) Na\(_2\)X + H\(_2\)O
(d) Basicity of acid H\(_y\)X = 2, (two)
Source: Myschool Past Questions Archive (Record #60033)
Chemistry
UTME / JAMB 2007
Acids, Bases, pH & Salts
Solution
The salt formed from strong acid and a strong base is?
A
complex
B
neutral
C
basic
D
acidic
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Sodium chloride, which is obtained by neutralization of hydrochloric acid and sodium hydroxide, is a neutral salt.
A neutral salt is formed when a strong acid reacts with a strong base. This is because the strong acid is completely neutralized by the strong base.
When a strong acid and a strong base are combined in the right amounts, the result is a neutral solution with a pH of 7.
The acid and base have neutralized each other, and the acidic and basic properties are no longer present.
The salt formed from a strong acid and a strong base is neutral because the anion and cation are both weak.
They are stable in water and do not react with water to form the original acid or base.
Source: WAEC / JAMB / NECO Classroom Archive (Record #3820)
Chemistry
UTME / JAMB 2007
Periodic Table & Periodicity
Solution
The elements that belong to the third period of the periodic table are?
A
Li, Be, Al and P
B
Na, P, O and Cl
C
B, C, N and O
D
Na, Mg, S and Ar
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Elements in period 3 have 3 shells in their atomic structure.
These include elements from sodium to argon.
Source: WAEC / JAMB / NECO Classroom Archive (Record #3856)
Chemistry
WAEC / WASSCE 2007
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
Consider the reaction below: Vegetable oil \(\frac{H2;NI catalyst}{High temperature}\) product. The reaction is applied in the manufacture of?
A
drugs
B
margarine
C
paraffin wax
D
soapy detergents
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
This is called hydrogenation. It includes the manufacture of margarine from animal or vegetable fats and oils.
Ethene reacts with hydrogen in the presence of a finely divided nickel catalyst at a temperature of about 150^\circC. Ethane is produced.
Source: WAEC / JAMB / NECO Classroom Archive (Record #37237)
Chemistry
UTME / JAMB 2007
Oxidation, Reduction & Redox Reactions
Solution
Trioxonitrate (V) acid is not used for preparing hydrogen gas from metals because it
A
is strongly oxidizing
B
is volatile
C
renders the metal passive
D
forms a layer of oxide on the metal
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Nitric acid is not used in the preparation of hydrogen because it is a strong oxidizing agent, meaning it readily oxidizes the hydrogen gas produced during the reaction with a metal, converting it to water and thus preventing the collection of hydrogen gas; instead, acids like dilute hydrochloric acid or sulphuric acid are preferred for hydrogen production as they do not oxidize hydrogen.
Source: Myschool Past Questions Archive (Record #3734)
Chemistry
UTME / JAMB 2007
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
An element used in the production of matches is
A
nitrogen
B
aluminium
C
copper
D
sulphur
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Nitrogen prevents food from degrading by creating an unreactive atmosphere.
Aluminium is used in buildings because it's resistant to corrosion and thermally efficient.
Copper is a versatile metal used in many applications, including electrical wiring, plumbing, construction, and transportation.
Sulphur is commonly used as an ingredient in the head of a match, contributing to its ability to ignite easily when struck against a striking surface; most modern safety matches contain sulfur or charcoal alongside other chemicals like potassium chlorate and antimony sulphide. Sulphur acts as a fuel in the match head, readily combusting when combined with an oxidizer like potassium chlorate.
Source: Myschool Past Questions Archive (Record #3745)
Chemistry
UTME / JAMB 2007
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
When calcium oxide is heated with carbon, the oxide will
A
be converted to carbide
B
be converted to the trioxocarbonate (IV) salt
C
decompose to the metal
D
melt, producing carbon (IV) oxide
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
When calcium oxide (CaO) reacts with carbon (C), it produces calcium carbide (CaC\(_2\))and carbon monoxide (CO). This reaction occurs at very high temperatures, around 700^\circC.
CaO + 3C → CaC\(_2\) + CO
Source: Myschool Past Questions Archive (Record #3748)
Chemistry
UTME / JAMB 2007
Non-Metals & Their Compounds
Solution
A solution which on treatment with hydrochloric acid produces a colourless, odourless gas which turns lime water milky is most likely to be a
A
trioxonitrate (V)
B
chloride
C
trioxocarbonate (IV)
D
hydroxide
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
A solution containing carbonate when treated with hydrochloric acid, produces a colourless, odourless gas (carbon dioxide) that turns lime water milky.
For example, when hydrochloric acid (HCl) reacts with sodium carbonate (Na\(_2\)CO\(_3\)), it releases carbon dioxide (CO\(_2\)) gas, which is colourless and odourless.
Source: Myschool Past Questions Archive (Record #3751)
Chemistry
UTME / JAMB 2007
Metals, Transition Elements & Extraction
Solution
The soft solder used for welding and plumbing is alloy of
A
lead and tin
B
iron and tin
C
lead and zinc
D
iron and zinc
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
An alloy is a mixture of chemical elements of which in most cases at least one is a metallic element, although it is also sometimes used for mixtures of elements;
The soft solder used for welding and plumbing is alloy of Tin and Lead. The mixture of tin and lead creates a eutectic alloy, meaning it has a lower melting point than either metal alone, making it easy to work with and join metal parts together without excessively heating the base material, making it ideal for delicate applications like plumbing joints and electrical connections.
Source: Myschool Past Questions Archive (Record #3752)