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Physics
WAEC / WASSCE 2011
Waves and Optics
The main difference between echo and reverberation is that
A
reverberation is reflected sound while echo is refracted sound
B
the time interval between incident sound and reflecte sound is shorter for reverbration
C
the amplitude of an echo is greater
D
reverberation is from acoustic speakers while echo comes from clifts
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35479)
Physics
WAEC / WASSCE 2011
Waves and Optics
For photoelectric emission, the threshold frequency is the
A
maximum frequency of incident radiation that will eject elecrons
B
minimum fraquency of incident radiation required to eject elecrons
C
frequency which results in the emission of the greater number of electrons
D
fraquency whch impacts greatest kinetic energy to emitte electrons
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35497)
Physics
WAEC / WASSCE 2011
Waves and Optics
Solution
State three methods of polarizing an unpolarized light
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
The methods of polarizing an unpolarized light are:
- reflection from plane, smooth surfaces.
- double refraction through crystals.
- selective absorption
- polaroid.
- Scattering by small particles, etc.
Source: Myschool Past Questions Archive (Record #53330)
Physics
WAEC / WASSCE 2011
Waves and Optics
Diagram
Solution
Use the diagram above as a guide to carry out the following experiment.
Trace the outline ABCD of the rectangular glass prism on the drawing paper provided.
Remove the prism. Select a point N on AB such that AN is about one-quarter of AB.
Draw the normal LNM. Also, draw a line RN to make an angle \(\theta\) = 75^\circ with AB at N.
Fix two pins at \(P_1\) and \(P_2\) on line RN. Replace the prism on its outline.
Fix two other pins at \(P_3\) and \(P_4\) such that they appear to be in a straight line with the images of the pins at \(P_1\) and \(P_2\) when viewed through the prism from DC.
(vi) Remove the prism and the pins at \(P_3\) and \(P_4\). Draw a line to join \(P_3\) and \(P_4\)
Produce line \(P_4\) \(P_3\) to meet the line DC at O. Draw a line to join NO.
Measure and record the values of MO and NO.
Evaluate \(\theta\) = \(\frac{MO}{NO}\) and cos \(\theta\).
Repeat the procedure for four other values of \(\theta\) = 65^\circ 55^\circ, 45^\circ, and 35^\circ. In each case, evaluate \(\theta\) and cos \(\theta\).
Tabulate your readings.
Plot a graph with cos \(\theta\) on the vertical axis and \(\theta\) on the horizontal axis.
Determine the slope, s, of the graph.
State two precautions taken to ensure accurate results
(b)i. State Snell's law of refraction.
ii. Calculate the critical angle for the glass prism used in the experiment above if its refractive index is 1.5.
Attached Figure / Diagram
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Observation/table of values
S/N
\(\theta\)(0)
Mo(cm)
No(cm)
\(\theta\)=\(\frac{MO}{NO}\)
Cos \(\theta\)
1
75.0
1.60
6.60
0.100
0.260
2
65.0
3.00
7.00
0.290
0.420
3
55.0
3.10
7.30
0.390
0.570
4
45.0
3.10
7.60
0.480
0.700
5
35.0
4.50
8.00
0.520
0.820
Slope (s) = \(\frac{\bigtriangleup \text {cos} \theta}{\bigtriangleup \theta} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
\(\frac{MO}{NO} = \frac{0.77-0.20}{0.50-0.17}\)
\(\frac{0.57}{0.33}\)
Slope (s) = 1.72
Graph cos \(\theta\) against = \(\phi\) = \(\frac{MO}{NO}\)
see the graph above.
PRECAUTIONS; i
- Ensured pins are vertical/ erect.
- Ensured neat traces/sharp pencil (shown on trace)
- Ensured reasonable spacing of pins (about 4cm apart)
- Avoided parallax error in reading protractor/metre rule.
(b)i. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.
Or \(\frac {\text {Sin i}}{\text {Sin r}}\) = a constant for a given pair of media
Where i = angle of incidence;
r = angle of refraction
ii. n = \(\frac{i}{\text{Sin c}}\)
Sin c = \(\frac{1}{1.5}\) = 0.6667
C = sin\(^{-1}\) 0.6667
C = 41.80^\circ
Source: Myschool Past Questions Archive (Record #60007)
Physics
WAEC / WASSCE 2010
Waves and Optics
Solution
A certain wave has a speed of 20ms-1. If the frequency of the wave is 0.25Hz, calculate the distance between successive crests of the wave
A
5.0m
B
40.0m
C
50.0m
D
80.0m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
\(\lambda = \frac{v}{f} = \frac{20}{0.25} = 80\)
Source: Myschool Past Questions Archive (Record #35320)
Physics
WAEC / WASSCE 2010
Waves and Optics
The ability of a wave to spread around corners is called
A
polarisation
B
dispersion
C
diffraction
D
reflection
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35321)
Physics
WAEC / WASSCE 2010
Waves and Optics
The following devices use plane mirrors in their operations, except
A
periscope
B
sextant
C
kaleidoscope
D
binoculars
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #35322)
Physics
WAEC / WASSCE 2010
Waves and Optics
When an object is placed at the principal focus of a concave mirror, the location of the image formed is
A
between principal focus and pole
B
between principal focus and centre of curvature
C
at infinity
D
at centre of curvature
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35323)
Physics
WAEC / WASSCE 2010
Waves and Optics
A ray of light travels from air to water. The refeactive index of water is given by the expression
A
\(\frac{\text{velocity in water}}{\text{velocity in air}}\)
B
\(\frac{\text{sine of angle of refraction}}{\text{sine of angle of incidence}}\)
C
\(\frac{\text{apparent depth}}{\text{real depth }}\)
D
\(\frac{\text{wavelength in air}}{\text{wavelength in water}}\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #35327)
Physics
WAEC / WASSCE 2010
Waves and Optics
A lens that is thinner at the middle and thicher at the edges is
A
diverging
B
converging
C
plano-convex
D
converging meniscus
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35328)
Physics
WAEC / WASSCE 2010
Waves and Optics
Which of the following electromagnetic wave has the longest wavelength?
A
radio-waves
B
gamma rays
C
infrared waves
D
ultraviolet rays
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35329)
Physics
WAEC / WASSCE 2010
Waves and Optics
The resonant frequency of an a.c circuit is 1000 kHz. If each of the capacitance and inductance in the circuit is reduced by 50%, and no other changes are made, the resonant frequency will become
A
250kHz
B
750kHz
C
1000kHz
D
2000kHz
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #35352)
Physics
WAEC / WASSCE 2010
Waves and Optics
Solution
An electron moves with a speed of 2.0 x 10\(^6\)ms\(^{-1}\) in a straight line. Calculate the wavelength of the electron wave. [mass of an electron = 9.1 x 10\(^{-31}\) kg][Planck's constant = 6.6 x 10\(^{-34}\)Js]
A
3.63 x 10-10m
B
6.51 x 10-9m
C
4.24 x 10-8m
D
7.25 x 10-8m
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\lambda = \frac{\text{h}}{\text{mv}}\)
mv = 9.1 \(\times 10^{-31} \times 2.0 \times 10^6 = 1.82 \times 10^{-24} \, \text{kg m/s}\)
\(\lambda = \frac{6.6 \times 10^{-34}}{1.82 \times 10^{-24}} = 3.63 \times 10^{-10} \, \text{m}\)
3.63 \times 10\(^{-10}\)
Source: Myschool Past Questions Archive (Record #35355)
Physics
WAEC / WASSCE 2010
Waves and Optics
The amplitude of a sound wave determines its
A
frequency
B
quality
C
loudness
D
pitch
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35330)
Physics
WAEC / WASSCE 2010
Waves and Optics
As the air column of length L in an air pipe decreases, the frequency of the sationary wave emitted
A
decreases
B
increases
C
varies as L2
D
varies as \(\sqrt{L}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35331)