Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 2191–2205 of 5315 verified questions
Sort by:
Physics
WAEC / WASSCE 2009
Heat Energy & Temperature
Solution
An inductor of inductance 1.0H is connected in series with a capacitor of capacitance 2.0\(\mu F\) in an a.c. circuit. to resonate
A
112.5Hz
B
225.0Hz
C
323.5Hz
D
707.1Hz
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
fo = \(\frac{1}{2 \pi \sqrt{LC}} = \frac{1}{2 \times 3.14 \sqrt{1 \times 2 \times 10^{-6}}}\)
= 112.5Hz
Source: Myschool Past Questions Archive (Record #35212)
Physics
WAEC / WASSCE 2009
Electricity and Magnetism
Solution
An ammeter connected to an a.c circuit records 5.5. The peak current in the circuit is
A
7.8A
B
7.1A
C
3.8A
D
3.5A
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(I_o = I_{rms} \times \sqrt{2} = 5.5 \times 1.41 = 7.8A\)
Source: Myschool Past Questions Archive (Record #35213)
Physics
WAEC / WASSCE 2009
Modern Physics and Nuclear Physics
Solution
Two isotopes of uranium are designed as \(^{238}U\) and \(^{235}U\). The numbers 238 and 235 represent their
A
atomic numbers
B
nucleon numbers
C
proton numbers
D
neutron numbers
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
neutrons + protons = the nucleus or mass numbers.
U-238 has mass number(proton 92 + neutron 146=238)
U-235 has mass number (proton 92 + neutron 143 =235)
Source: Myschool Past Questions Archive (Record #35218)
Physics
WAEC / WASSCE 2009
Mechanics and Properties of Matter
Solution
The main difference between x-rays and \(\gamma-rays\) lies in their
A
ionizing ability
B
absorption rate
C
mode of production
D
mode of propagation
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
X-rays and γ-rays are both electromagnetic radiations with similar properties (they propagate the same way, have high ionizing ability, and similar absorption behavior).
The "main difference" is how they are produced:
- X-rays → produced by interactions involving electrons outside the nucleus (e.g., in an X-ray tube when fast electrons hit a metal target).
- γ-rays → produced by processes inside the nucleus (e.g., during radioactive decay when an unstable nucleus releases excess energy)
Source: Myschool Past Questions Archive (Record #35219)
Physics
WAEC / WASSCE 2009
Waves and Optics
Solution
An electron of mass 9.1 x 10-31 kg moves with a speed of 107ms-1. Calculate the wavelength of the associates wave[h = 6.6 x 10-34Js]
A
9.0 x 10-24m
B
4.55 x 10-17m
C
7.25 x 10-11m
D
6.20 x 10-8m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\lambda = \frac{hc}{\frac{1}{2}mv^2}\)
= \(\frac{6.6 x 10^{-34} \times 3 \times 10^8}{0.5 \times 9.1 \times 10^{-3} (10^7)^2}\)
= 7.25 x 10-11m
Source: Myschool Past Questions Archive (Record #35221)
Physics
UTME / JAMB 2009
Waves and Optics
Solution
A progressive wave is represented by \( y = 10 \text{Sin} (1000\pi t - \frac{\pi x}{34}) \) . two layers of the wave separated by 153cm have a phase difference of?
A
2700
B
450
C
900
D
1800
E
No Correct Option
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Comparing \( y = 10 \text{Sin} (1000\pi t - \frac{\pi x}{34}) \) with y = A sin (\omegat - ϕ)
where ϕ = \(\frac{2\pi x}{\lambda}\)
comparing: \(\frac{2\pi x}{\lambda}\) = \( \frac{\pi x}{34}\)
\lambda = 34 \(\times\) 2 = 68
: ϕ = \(\frac{2\pi x}{\lambda}\) = \(\frac{2\pi \times 153}{68}\)
ϕ = 4.5\(\pi\) rad = 810^\circ or 90^\circ
since sin 810^\circ or 90^\circ = 1
Source: Myschool Past Questions Archive (Record #41400)
Physics
WAEC / WASSCE 2009
Heat Energy & Temperature
Solution
1. Connect the circuit as shown in the diagram above. PQ is a potentiometer wire 100 cm long and R is a standard resistor of 5\(\Omega\).
2. With the jockey J not making contact with PQ, close the switch. Read and record the ammeter reading I. Open the switch.
3. Use the jockey to make contact with PQ at the 20cm mark such that PJ = I = 20 cm. Close the switch, read and record the value \(I_i\) of the ammeter. Evaluate I\(^{-1}\).
4. Repeat the procedure for other values of I = 35, 50, 65, and 80 cm. In each case, determine the corresponding values of \(I_i\), and I\(^{-1}\). Tabulate your readings.
Plot a graph of I\(^{i}\) on the vertical axis and \(I_i\), on the horizontal axis, starting both axes from the origin (0, 0).
From your graph deduce the value, of \(I_o\) of \(I_i\), when I\(^{-1}\)= 0.
Evaluate \(I_o\)e
State two precautions taken to ensure accurate results.
(b)) Define the e. m.f. of a battery
ii. A cell X e.m.f. 1.00 V is balanced by a length of 40.0 cm on a potentiometer wire. Another cell Y is balanced by a length of 60.0 cm on the same wire. Calculate the e.m.f. of Y.
A
9.0 x 10-24m
B
4.55 x 10-17m
C
7.25 x 10-11m
D
6.20 x 10-8m
E
none of the above
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S/N
L(cm)
Ii(A)
L\(^{-1}\)(cm\(^{-1}\))
1
20
1.00
0.050
2
35
0.90
0.029
3
50
0.85
0.020
4
65
0.80
0.015
5
80
0.75
0.013
When L\(^{-1}\) = 0, Ii = 0.75A
\(I_o\) = 75A
\(\frac{I_{o}}{I}= \frac{0.75A}{0.20A}\) = 37.5
SEE THE GRAPH ABOVE...
Precautions: i
- ensured there was no error due to parallax when reading my ammeter.
- ensured that I removed the key after each reading.
(b)i. E.m.f is the total work done in pushing one coulomb of electricity round an external resistor and the internal resistor of the source, or the total energy obtained per coulomb from a cell or battery
ii. \(\frac{Ey}{Ex} = \frac{Iy}{Ix}\)
Iy = 60cm
Ex = 1.00v
Ix = 40.cm
Ey = ?
\(\frac{Ey}{1.00}=\frac{60}{40}\)
Ey = \(\frac{60 \times 1.00}{40}\) = 1.50.v
Source: Official Exam / Past Question Archive
Physics
NECO SSCE 2009
Heat Energy & Temperature
The space between the two walls of a vacuum flask is completely evacuated to reduce heat loss by
A
condensation
B
conduction
C
convection
D
evaporation
E
radiation
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43043)
Physics
NECO SSCE 2009
Heat Energy & Temperature
Which of the following substances undergoes sublimation?
A
Ether
B
Ice
C
Iodine
D
Naphthalene
E
Turpentine
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43044)
Physics
NECO SSCE 2009
Mechanics and Properties of Matter
Which of the following statements about the pressure in a liquid is NOT correct? It
A
acts in all direction
B
changes with the material of the container
C
is the same at all points in the same horizontal plane
D
varies with the density of the liquid
E
varies with the depth of the liquid
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #43046)
Physics
NECO SSCE 2009
Heat Energy & Temperature
In which of the following fields is repulsion NOT experienced?
A
Electrical only
B
Gravitational only
C
Magnetic only
D
Magnetic and electrical
E
Magnetic and gravitational
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #43047)
Physics
NECO SSCE 2009
Mechanics and Properties of Matter
Solution
A ball of mass 100g falls from a height of 5m onto a concrete floor and rebounds to a height of 3m. Calculate the energy lost. (g = 10ms-2)
A
2J
B
20J
C
100J
D
1000J
E
2000J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
To calculate the energy lost when a ball falls from a height of \(5 \, \text{m}\) and rebounds to a height of \(3 \, \text{m}\):
Given: Mass of the ball, \( m = 100 \, \text{g} = 0.1 \, \text{kg} \), Initial height, \( h_1 = 5 \, \text{m} \),
Rebound height, \( h_2 = 3 \, \text{m} \), Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
Calculating the potential energy at height \( h_1 \):
\(\text{PE}_1 = mgh_1 = 0.1 \, \text{kg} \cdot 10 \, \text{m/s}^2 \cdot 5 \, \text{m} = 5 \, \text{J}\)
Calculating the potential energy at height \( h_2 \):
\(\text{PE}_2 = mgh_2 = 0.1 \, \text{kg} \cdot 10 \, \text{m/s}^2 \cdot 3 \, \text{m} = 3 \, \text{J}\)
The energy lost is:
\(\text{Energy lost} = \text{PE}_1 - \text{PE}_2 = 5 \, \text{J} - 3 \, \text{J} = 2 \, \text{J}\)
Thus, the energy lost is: \({2 \, \text{J}}\)
Source: Myschool Past Questions Archive (Record #43048)
Physics
NECO SSCE 2009
Mechanics and Properties of Matter
Two forces of magnitude 8N and 4N act at right angle to each other. The angle between the resultant and the 8N force is
A
23.9°
B
26.6°
C
29.5°
D
60.0°
E
63.4°
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #43049)
Physics
NECO SSCE 2009
Waves and Optics
The defect of the eye lens which occurs as a result of weak ciliary muscles is called
A
astigmatism
B
hypermetropia
C
myopia
D
presbyopia
E
spherical aberration
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #43050)
Physics
NECO SSCE 2009
Waves and Optics
Which of the following pairs of phenomena helps in the resolution of the wave-particle paradox of matter?
A
Compton effect and thermionic emission
B
Electron diffraction and refraction
C
emission and absorption of light
D
Interference and polarization
E
Reflection and photoelectric effect
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #43051)