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Physics
UTME / JAMB 2009
Motion Force Circular Motion
Solution
What is the acceleration between two points on a velocity time graph which has coordinates
(10s, 15 ms-1)
and (20 s, 35 ms-1)?
A
1.7 ms-2
B
3.50 ms-2
C
1.00 ms-2
D
2.00 ms-2
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Acceleration = \(\frac{\DeltaV}{\Deltat}\)
= \(\frac{V - U}{t_2 - t_1}\)
= \(\frac{35 - 15}{20 - 10}\)
= \(\frac{20}{10}\)
= 2ms\(^-2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #14139)
Physics
UTME / JAMB 2009
Motion Force Circular Motion
Solution
A car accelerates uniformly from rest at 4 ms\(^{-2}\). How far will it travel in the fifth complete second?
A
100 m
B
50m
C
32 m
D
18 m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
From S = ut + 1/2 at2
S = 1/2 ut2, since U = 0
Let S5 = distance in 5 seconds
= 1/2 x 4 x 52 = 2 x 25 = 50m
S4 = distance covered in 4 seconds
= 1/2 x 4 x 42 = 2 x 16 = 32m
Distance covered in the fifth second
S5 - S4 = 50m - 32m = 18m
Source: WAEC / JAMB / NECO Classroom Archive (Record #14497)
Physics
UTME / JAMB 2009
Work, Energy and Power
Solution
If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 m\s\(^2\)]
A
11.50 kw
B
12.60 kw
C
11.25 kw
D
12.10 kw
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Power = \(\frac{work done}{time taken}\)
where 1 min = 60s
= \(\frac{mgh}{t}\)
= \(\frac{750 \times 10 \times 90}{60}\)
= 11250w or 11.25kw
Source: WAEC / JAMB / NECO Classroom Archive (Record #14142)
Physics
UTME / JAMB 2009
Work, Energy and Power
Solution
An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction.
[g = 10 ms\(^{-2}\)]
A
0.8
B
0.4
C
1.0
D
0.6
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
coefficient of friction
= \(\frac{F}{R}\)
=\(\frac{F}{mg}\)
= \(\frac{500}{80 \times 10}\)
= 0.625
Source: WAEC / JAMB / NECO Classroom Archive (Record #14143)
Physics
UTME / JAMB 2009
Simple Machine
Solution
If a heavy barrel is rolled up a plane inclined at 30° to the horizontal. its velocity ratio will be?
A
3.0
B
3.1
C
3.2
D
2.0
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
V.R = \(\frac{1}{sin\theta}\)
= \(\frac{1}{sin 30^\circ}\)
= \(\frac{1}{0.5}\)
= 2
Source: WAEC / JAMB / NECO Classroom Archive (Record #14146)
Physics
WAEC / WASSCE 2009
Linear Motion & Kinematics
Solution
A moving body accelerates when it?
A
changes its direction at constant speed
B
mauntains a constant linear speed
C
covers equal distances in equal times in a straight line
D
is acted upon by balanced forces
E
none of the above
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
A moving body accelerates when: (i) Change in Speed: If the body increases or decreases its speed, it experiences acceleration, (ii) Change in Direction: Even if the speed remains constant, if the direction of the body changes (such as when turning), it still accelerates. This is because acceleration is defined as any change in velocity, and velocity includes both speed and direction.
Source: WAEC / JAMB / NECO Classroom Archive (Record #35149)
Physics
UTME / JAMB 2009
Equilibrium of Forces
Solution
A plastic sphere floats in water with 50% of its volume submerged. if it floats in glycerine with 40% of its volume submerged,the density of the glycerine is?
A
1400 kgm-3
B
1250 kgm-3
C
500 kgm-3
D
1000 kgm-3
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Weight of glycerine displaced = weight of water dispalced
Mgh glycerine = Mgh water
Pvgh glycerine = Pvgh water
0.4V P glycerine = (0.5v)/v.4v P water = 1.25
(Polycerine)/p water =
But density of substance = relative density x density of water = 1. 25 x 1000kgm3 = 1250kgm-3
Source: WAEC / JAMB / NECO Classroom Archive (Record #14156)
Physics
UTME / JAMB 2009
Equilibrium of Forces
Diagram
Solution
which of the diagrams above shows the position at which a small ball-bearing is in neutral equilibrium?
Attached Figure / Diagram
A
A
B
B
C
C
D
D
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Neutral Equilibrium: If the body neither returns to its original position nor increases its displacement further, it will simply adopt its new position.
Examples of neutral equilibrium
Ball moving on the ground.
Motion of sphere.
A roller.
A pencil lying horizontally.
An egg lying horizontally on a flat surface.
Source: WAEC / JAMB / NECO Classroom Archive (Record #41401)
Physics
UTME / JAMB 2009
Projectile Motion
Solution
A bullet fired vertically upward from a gun held 2.0 m above the ground reaches its maximum height in 4.0s. calculate its initial velocity.
[g = 10ms\(^-2\)]
A
10 ms-1
B
8 ms-1
C
40 ms-1
D
20 ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
At maximum height, the final velocity, v = 0
thus from v = u - gt
0 = u - gt
∴ U = at = 10 x 4 = 40 mls
Source: WAEC / JAMB / NECO Classroom Archive (Record #14140)
Physics
NECO SSCE 2009
Projectile Motion
Solution
A projectile attains its maximum height when the angle of projection is?
A
30°
B
45°
C
60°
D
75°
E
90°
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
At an angle of 90^\circ, the projectile is launched straight up, maximizing its height. While other angles can also achieve significant heights, 90^\circ results in the highest possible elevation.
Source: WAEC / JAMB / NECO Classroom Archive (Record #43056)
Physics
UTME / JAMB 2009
Momentum Impulse Newtons Law of Motion
Solution
A body of mass 12kg traveling at 4.2ms-1 collides with a second body of mass 18kg at rest. Calculate their common velocity if the two bodies coalesce after collision?
A
1.5 ms-1
B
1.4 ms-1
C
2.1 ms-1
D
1.7 ms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The sum of momentum before collision
M\(_1\) U\(_1\) + M\(_2\)U\(_2\)
12 x 4.2 + 18 x 0
12 x 4.2
= 50.4
The sum of momentum after collision
(m\(_1\) + m\(_2\))v
= (12 + 18)v
= 30v
V = 50.4/30
= 1.7ms-1
Source: WAEC / JAMB / NECO Classroom Archive (Record #14498)
Physics
UTME / JAMB 2009
Simple Harmonic Motion
Solution
I. The motion of the tyres of a moving car.
II. The motion of a loaded test tube oscillated
vertically.
III. The beating of the heart.
IV. A stone tied to a string and whirled round.
V. The motion of the pistons in a gasoline engine.
Which of the motions above is simple harmonic?
A
III, IV and V only
B
II, III and V only
C
II, III and IV only
D
I,II and III only
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Simple harmonic motion is the motion of a body whose acceleration is directed towards a fixed point and is directly proportional to its displacement from point.
Statements ii, iii and v are clear examples
Source: WAEC / JAMB / NECO Classroom Archive (Record #14141)
Physics
UTME / JAMB 2009
Friction
Solution
The terminal velocity of a ball-bearing falling through a viscous fluid is reached when the?
A
upthrust is equal to the weight of the ball
B
ball accelerate uniformly
C
upthrust is equal to the velocity of the ball
D
velocity is uniform
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
At vt = terminal velocity
= zero acceleration
= uniform velocity
Source: WAEC / JAMB / NECO Classroom Archive (Record #14499)
Physics
UTME / JAMB 2009
Simple Structure of Matter
Solution
It is observed that water will wet a clean glass because the?
A
cohesion of water to glass is stronger than the cohesion of water molecules
B
adhesion of water molecules is weaker than the cohesion of water to glass
C
cohesion of water to glass is weaker than the cohesion of water molecules
D
adhesion of water molecules is stronger than the cohesion of water molecules
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
When the adhesion of liquid molecules to the glass is more than the cohesion of the liquid, the liquid will wet glass.
Source: WAEC / JAMB / NECO Classroom Archive (Record #14194)
Physics
UTME / JAMB 2009
Density and Relative Density
Solution
At 4°c, the volume of a fixed mass of water is?
A
constant
B
minimum
C
maximum
D
zero
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Anomalous expansion of water is at temperature ranges 0^\circc to 4^\circc u. water contract when heated from 0^\circc to 4^\circc. thus the volume of water is least at 4^\circc
Source: WAEC / JAMB / NECO Classroom Archive (Record #14170)