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Critical angle is the angle of incidence in the denser medium when the angle of refraction in the less dense medium is 90^\circ. (b) Deviation of a ray in a triangular prism is determined by the factors: - Angle of incidence - Refracting angle of the prism, and - Refractive index of the prism material. (c) A = 2r = 2 x 29 = 58\(^o\) But n = \(\frac{sin \frac{1}{2} (A + Dm)}{sin \frac{1}{2}A} \) sin \(\frac{1}{2}\)(A + Dm) = n sin A \(\frac{1}{2}\)A 58 + Dm = 93.32 - 58 = 35.32\(^o\) (d) Angle P = 45^\circ - 20^\circ = 25^\circ But Angle Q = 180^\circ- 60^\circ = 120^\circ P +Q + R = 180^\circ Hence R = 180 - (P + Q) =180 - (25 + 120) = 35^\circ (ii) n = \(\frac{Sini}{sinP} = \frac{sin45^o}{sin45^o} = 1.673\) (iii) n = \(\frac{sini}{sine} = \frac{sine}{sinR} = \frac{sinee^o}{sin35^o}\) = 1.673 = \(\frac{sine}{sin35^o}\) e = sin\(^{-1}\) (1.673 x sin 35\(^o\)) = 73.7\(^o\) (iv) D = (i + e) - A = (45 + 73.3) - 60\(^o\) = 58.3\(^o\)

Sound is the only mechanical wave among the rest which are electromagnetic waves.

r - rays has the highest frequency followed by X - rays, ultraviolet ray, visible light intra - red and the least is radio weaves

Hot wire ammeter is used because the heat affect of A C is same as that of DC

The colour which an object presents to the eye is the colour of light it reflects. Red rose flower will therefore absorb any other colour and reflect red. Therefore when viewed in blue light, it has no colur to reflect and will therefore appear black. Although mixture of red light and blue light = magenta .

m = v/u = -3 v = -3u f = 15cm 1/v + 1/U = 1/f 1/-3U + 1/u = 1/15 2/3u = 1/15 3U = 15 x 2 U = 30/3 = 10 cm

The period of a simple pendulum is dependent on the frequency. It is also dependent on the length of the pendulum but not the mass. Since the two pendulums have equal length, then their periods are equal as well.

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option D.

n = \(\frac{\sin \frac{1}{2} (dm + A)}{\sin \frac{1}{2} A}\) = \(\frac{\sin \frac{1}{2} (40 + 60)}{\sin \frac{1}{2} \times 60}\) = 1.532

No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option B.

\(\frac{1}{v} = \frac{1}{f} - \frac{1}{U}\) \(\frac{1}{15} - \frac{1}{20} = 60cm\)

No expanded working has been attached for this question yet. The verified answer is Option A.

\(f_1 - f_2 = \frac{1}{T}\) 12 - 10 = \(\frac{1}{2}\) = 0.5