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No expanded working has been attached for this question yet. The verified answer is Option A.

18\omega ⇔ 100ºC x ⇔ 45ºC 10\omega ⇔ 0ºC \(\frac{ x - 10}{18 - 10} = \frac{ 45 - 0}{ 100 - 0}\) 100x - 1000 = 45 x 8 100x = 360 + 1000 = 1360 x = \(\frac{1360}{100}\) = 13.6.

Table of values XY = 100cm R(\(\Omega\)) 1(amp) V 0 0.15 2.65 1 0.15 2.65 5 0.15 2.65 10 0.10 1.85 20 0.08 1.40 40 0.06 0.90 60 0.04 0.70 Slope = \(\frac{x_{2}-x_{1}}{y_{2}-y_{1}} = \frac{1.75-0.5}{0.10-0.025} = \frac{1.25}{0.075}\) Precautions: I ensured good contact and the correct connection of the circuit. I avoided incorrect positioning of the eye (error due to parallax). Open the key plug when recording the reading taken. (b)i. The experiment is based on Ohm's law. Ohm's law states that the current flowing through a metallic conductor is proportional to the potential difference between its ends provided the temperature and other physical conditions of the conductor remain constant; i.e: \(\frac{V}{|}\) = Constant. ii. Area of cross-section of wire = \(\frac{\pi d^{2}}{4} = \frac{\frac{22}{7} \times (0.2)^{2}}{4}\) \(\frac{3.143 \times 0.04}{4}\) = 0.031mm\(^{2}\) = 3.1m\(^{2}\) Resistivity = \(\frac{RA}{L}\), length (L) = \(\frac{R.A}{resistivity}\) = \(\frac{7 \times 3.1}{8.8 \times 10^{-7}} = \frac{21.7}{8.8 \times 10^{-7}}\) = 2.47 x 10\(^{-7}\)

heat is transferred from the water to the ice/glass through direct contact(conduction) additionally, there is some convective heat transfer within the water as warmer water rises and cooler water sinks.

3919K 3919K. Since neither the mass number (39), nor the atomic number (19) is affected by the emission,the particles emitted can only be gamma ray, which is not a charge particle, but simply a radiation.

85\(\Omega\) ........100oC 52\(\Omega\) ........\(\theta\)oC 20\(\Omega\) ........0oC \(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\) \(\theta = \frac{32 \times 100}{65} = 49.2^oC\)

The amount of heat given out or absorbed when a substance changes its state at a constant temperature is known as latent heat.

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option E.

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option E.

Let the specific heat cap. of the metal = C ∴ Heat lost by the metal = heat gained by the Calorimeter + Water ∴ 0.5 x C x [100 - 25] 80 x [25 - 15] + 420 [25 - 15] 0.5 x C x 75 = 80 x 10 + 420 x 10 37.5C = 800 + 4200 C = 5000/37.5 = 133.3Jkg-1K-1

In a pure (intrinsic) semiconductor, the number of electrons in the conduction band is equal to the number of holes in the valence band. This is because when an electron moves from the valence band to the conduction band, it leaves behind a hole.

The Six's maximum and minimum thermometer uses a liquid-filled bulb connected to a U-shaped tube with a mercury thread. As the liquid expands or contracts, the mercury moves, pushing the steel indexes to indicate the maximum and minimum temperatures, which can be reset using a magnet.

When two bodies are in thermal equilibrium, it means that they have the same temperature. This is because, in thermal equilibrium, there is no net transfer of heat between the bodies, indicating that they have reached the same temperature.