Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 181–195 of 345 verified questions
Sort by:
Mathematics
UTME / JAMB 2002
Statistics and Probability
Solution
Find the mean of the data: 7, -3, 4, -2, 5, -9, 4, 8, -6, 12
A
3
B
4
C
1
D
2
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(Mean: \frac{7 + (-3) + 4 + (-2) + 5 + (-9) + 4 + 8 + (-6) + 12}{10} = \frac{20}{10}\)
= 2
Source: Myschool Past Questions Archive (Record #3384)
Mathematics
UTME / JAMB 2002
Statistics and Probability
Solution
The mean of a set of six numbers is 60. If the mean of the first five is 50, find the sixth number in the set.
A
105
B
100
C
95
D
110
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Let the sum of the first five numbers and the sixth number be x and t respectively.
\(\frac{x + t}{6} = 60 \implies x + t = 360\)
\(\frac{x}{5} = 50 \implies x = 250\)
\(\therefore t = 360 - 250 = 110\)
Source: Myschool Past Questions Archive (Record #3395)
Mathematics
UTME / JAMB 2002
Statistics and Probability
Solution
Calculate the mean deviation of the set of numbers 7, 3, 14, 9, 7, and 8.
A
13/6
B
5/2
C
7/6
D
7/3
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
x
7
3
14
9
7
8
Total
\(x - \bar{x}\)
-1
-5
6
1
-1
0
\(|x - \bar{x}|\)
1
5
6
1
1
0
14
Mean : \(\frac{7 + 3 + 14 + 9 + 7 + 8}{6} = \frac{48}{6} = 8\)
Mean deviation : \(\frac{\sum |x - \bar{x}|}{n} = \frac{14}{6} = \frac{7}{3}\)
Source: Myschool Past Questions Archive (Record #3396)
Mathematics
NECO SSCE 2002
Statistics and Probability
Solution
The mean and the range of the set of numbers: 1.20, 1.00, 0.90, 1.40, 0.80, 0.80, 1.20 and 1.10 are p and q respectively. What is the value of p ÷ q?
A
1.11
B
65
C
1.85
D
2.45
E
3.85
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Mean of 1.20, 1.00, 0.90, 1.40, 0.80, 0.80, 1.20 and 1.10
→ \(\frac{8.4}{8}\) = 1.05 → p
Range = 1.40 - 0.80 = 0.60 → q
p \div q = 1.05 \div 0.60
= 1.75
Source: WAEC / JAMB / NECO Classroom Archive (Record #42203)
Mathematics
WAEC / WASSCE 2002
Statistics and Probability
Diagram
The median of the distribution is
Attached Figure / Diagram
A
25
B
17.5
C
15
D
12.5
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #26546)
Mathematics
WAEC / WASSCE 2002
Statistics and Probability
Solution
The number of goals scored by a school team in 10 netball matches are as follows: 3, 5, 7, 7, 8, 8, 8, 11, 11, 12. Find the probability that in a match, the school team will score at most 8 goals.
A
\(\frac{7}{10}\)
B
\(\frac{2}{5}\)
C
\(\frac{3}{5}\)
D
\(\frac{1}{5}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
Number of at most 8 goals = 7
P(at most 8 goals) = \(\frac{7}{10}\)
Source: Myschool Past Questions Archive (Record #26567)
Mathematics
NECO SSCE 2002
Statistics and Probability
Solution
A petrol attendant recorded the number of vehicles that bought petrol from him for -3 hours and recorded 12 cars and 27 buses. What is the probability that the next vehicle will be a bus?
A
\(\frac{4}{39}\)
B
\(\frac{4}{13}\)
C
\(\frac{5}{13}\)
D
\(\frac{6}{13}\)
E
\(\frac{9}{13}\)
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
Prob = \(\frac{ no of expected outcome}{ no of total outcome}\)
no of cars = 12, no of buses = 27
no of total outcome = 12 + 27 = 39
no of expected outcome = 27
Prob( next vehicle will be bus) = \(\frac{27}{39} = \frac{9}{13}\)
Source: Myschool Past Questions Archive (Record #42062)
Mathematics
NECO SSCE 2002
Statistics and Probability
The probability that a student will pass a mathematics test is ⅗. If 3 students are chosen at random, what is the probability that at least 2 of them will pass the test?
A
\(\frac{27}{125}\)
B
\(\frac{9}{25}\)
C
\(\frac{72}{125}\)
D
\(\frac{76}{125}\)
E
\(\frac{81}{125}\)
medium Difficulty
Verified Correct Answer: Option E
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #42107)
Mathematics
NECO SSCE 2002
Statistics and Probability
One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one ball is drawn from each bag, what is the probability that both are white?
A
\(\frac{2}{3}\)
B
\(\frac{3}{8}\)
C
\(\frac{7}{24}\)
D
\(\frac{1}{4}\)
E
\(\frac{1}{24}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #42154)
Mathematics
NECO SSCE 2002
Statistics and Probability
The mean heights of 3 groups of students consisting of 20, 16 and 14 students are 1.67m, 1.50m and 1.40m Respectively. What is the mean height of all the students?
A
1.52m
B
1.53m
C
1.54
D
1.55m
E
1.56m
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #42201)
Mathematics
WAEC / WASSCE 2002
Statistics and Probability
Solution
The probabilities that Ade, Kujo and Fati will pass an examination are \(\frac{2}{3}, \frac{5}{8}\) and \(\frac{3}{4}\) respectively. Find the probability that
(a) the three ;
(b) none of them ;
(c) Ade and Kujo only ; will pass the examination.
medium Difficulty
Verified Correct Answer: Option
Step-by-Step Mathematical Solution
(a) \(P(Ade) = \frac{2}{3} ; P(Kujo) = \frac{5}{8} ; P(Fati) = \frac{3}{4}\)
\(P(\text{all three pass the exam}) = \frac{2}{3} \times \frac{5}{8} \times \frac{3}{4}\)
= \(\frac{5}{16}\)
(b) P(Ade fails) = \(1 - \frac{2}{3} = \frac{1}{3}\)
P(Kujo fails) = \(1 - \frac{5}{8} = \frac{3}{8}\)
P(Fati fails) = \(1 - \frac{3}{4} = \frac{1}{4}\)
P(none passes) = \(\frac{1}{3} \times \frac{3}{8} \times \frac{1}{4}\)
= \(\frac{1}{32}\).
(c) P(Ade and Kujo only pass) = \(\frac{2}{3} \times \frac{5}{8} \times \frac{1}{4}\)
= \(\frac{5}{48}\)
Source: Myschool Past Questions Archive (Record #53321)
Mathematics
UTME / JAMB 2001
Statistics and Probability
Solution
Given the scores: 4, 7, 8, 11, 13, 8 with corresponding frequencies: 3, 5, 2, 7, 2, 1 respectively. Find the square of the mode.
A
49
B
121
C
25
D
64
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Mode = score with highest frequency = 11.
Square of 11 = 121
Source: Myschool Past Questions Archive (Record #2810)
Mathematics
UTME / JAMB 2001
Statistics and Probability
Solution
Given the scores: 4, 7, 8, 11, 13, 8 with corresponding frequencies: 3, 5, 2, 7, 2, 1 respectively. The mean score is
A
7.0
B
8.7
C
9.5
D
11.0
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Mean = ∑fx/∑f
Mean = (4x3) + (7x5) + ... + (8x1) all divided by 20
Mean = 174/20 = 8.7
Source: Myschool Past Questions Archive (Record #2867)
Mathematics
UTME / JAMB 2001
Statistics and Probability
Solution
Teams P and Q are involved in a game of football. What is the probability that the game ends in a draw?
A
2/3
B
1/2
C
1/3
D
1/4
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
In a football/soccer game, there are 3 possible outcomes: home win, draw, and away win. So, in this case, Pr(that the game ends in a draw) = \(\frac{1}{3}\)
Source: Myschool Past Questions Archive (Record #2868)
Mathematics
UTME / JAMB 2001
Statistics and Probability
Solution
Find the variance of 2, 6, 8, 6, 2 and 6
A
6
B
5
C
√6
D
√5
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
mean of X = x = (2+6+8+6+2+6)/6 = 30/6 = 5
X → 2,6,8,6,2,6
X - x = -3, 1, 3, 1, 3, 1
(X - x)2 = 9, 1, 9, 1, 9, 1
∑(X-x) = 9+1+9+1+9+1 = 30
Variance = ∑(X-x)2/n = 30/6 = 5
Source: Myschool Past Questions Archive (Record #7713)