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Physics
UTME / JAMB 2011
Mechanics and Properties of Matter
Solution
A length of wire has a frequency of 225Hz when stretched by a force of 225N. If the force increased to 324N, what is the new frequency of vibration?
A
270 Hz
B
512 Hz
C
488 Hz
D
356 Hz
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
f1 = 225Hz, T1 = 225N
f2 = ? T2 = 324N
But f ∝ \sqrtT => f = K\sqrtT
=> K = f/\sqrtT
∴ f1/\sqrtT1 = f2/\sqrtT2
225/\sqrt225 = f2/\sqrt324
f2 =
225\sqrt324
\sqrt225
f2 = 270Hz
Source: Myschool Past Questions Archive (Record #14536)
Physics
UTME / JAMB 2011
Electricity and Magnetism
Diagram
Solution
In the circuit above, three resistors, 2\Omega, 4\Omega and 12\Omega are connected in parallel and a 12V battery is connected across the combination. The current flowing through the 12\Omega resistors is
Attached Figure / Diagram
A
14.4 A
B
1.0 A
C
3.2 A
D
9.6 A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
I = \(\frac{V}{R}\) from Ohm's law
I = \(\frac{12}{12}\) = 1A.
Source: Myschool Past Questions Archive (Record #14552)
Physics
WAEC / WASSCE 2011
Heat Energy & Temperature
Which of the following statements is not correct?
A
molecules of ice, water and water vapour have equal intermolecular distances
B
molecules of ice, water and water vapour do not differ in the structure of their molecules
C
molecules of water vapour attract each other with forces far less than the forces of attraction between water molecules
D
water is less compressible than water vapour
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #35373)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
The density P of a spherical ball of diameter d and mass m is given by
A
P = \(\frac{3m}{4 \pi d^3}\)
B
p = 4\(\pi md^3\)
C
p = \(\frac{6m}{\pi d^3}\)
D
p = \(\frac{3m}{2 \pi d^3}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
p = \(\frac{M}{V} = \frac{M}{\frac{4}{3} \pi (\frac{d}{\pi})^3}\)
= \(\frac{6m}{\pi d^3}\)
Source: Myschool Past Questions Archive (Record #35382)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
A metal rod of density 7000 kgm-3 and cross-sectional area of 0.001257m2 has a mass of 1.76kg. Calculate its length.
A
0.20m
B
0.25m
C
0.40m
D
0.50m
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
P = \(\frac{M}{AL}\)
L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m
Source: Myschool Past Questions Archive (Record #35409)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
The pressure in a liquid
A
is the same at all points in the liquid
B
decreases with depth
C
is the same in all directions at a given point
D
is equal to the atmospheric pressure
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35410)
Physics
WAEC / WASSCE 2011
Heat Energy & Temperature
The property of a fluid that is used to determine its suitability as a lubricant is its
A
capillarity
B
viscocity
C
surface tension
D
relative density
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35411)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
The area under a velocity-time graph represents
A
final velocity attained
B
distance covered
C
acceleration
D
workdone
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35412)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
In the absence of gravitational force, the weight of the body is
A
its mass
B
zero
C
its density
D
its volume
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35413)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
Which of the following propeties is not considered in choosing mercury as a thermomemetric liquid?
A
density
B
expansivity
C
conductivity
D
opacity
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Expansion and Contraction: The density of mercury affects how it expands and contracts with temperature changes. A liquid with a consistent and predictable expansion rate is essential for accurate temperature readings.
Calibration: The density of the liquid must be known to calibrate the thermometer accurately. This ensures that the scale on the thermometer corresponds correctly to temperature changes.
Thermal Conductivity: While conductivity can influence how quickly a liquid reaches thermal equilibrium with its surroundings, it is not as critical as density for the overall accuracy of the thermometer.
But in choosing mercury as a thermometric liquid, the density of mercury is not usually considered.
Source: Myschool Past Questions Archive (Record #35414)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
A stone of mass 300g is released from rest from the top of a bulding of height 100m. Determine the kinetic energy gained by the stone when it is a quarter way down from the point of release.[g = 10 ms-2]
A
750.0J
B
225.0J
C
75.0J
D
22.5J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
K.E = P.E = mgh
= 0.3 x 10 x 100 - 0.3 x 10 x 75
= 75J
Source: Myschool Past Questions Archive (Record #35415)
Physics
WAEC / WASSCE 2011
Heat Energy & Temperature
Solution
A body of mass 120g placed at the 10cm mark on a uniform metre rule makes the rule settle horizontally on a fulcrum places at 35cm mark. Calculate the mass of the rule
A
60g
B
80g
C
120g
D
200g
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
m = \(\frac{25 \times 120}{15}\)
= 200g
Source: Myschool Past Questions Archive (Record #35434)
Physics
WAEC / WASSCE 2011
Waves and Optics
Solution
Two simple pendulum A and B of equal lengths and of masses 5g and 20g respectively are located in the same environment. The periods TA and TB of their respective oscillations are related by the equations
A
TA = 4TB
B
TA = \(\frac{1}{4} T_B\)
C
TA = TB
D
TA = 5TB
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The period of a simple pendulum is dependent on the frequency. It is also dependent on the length of the pendulum but not the mass. Since the two pendulums have equal length, then their periods are equal as well.
Source: Myschool Past Questions Archive (Record #35436)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
An object of mass 5.0 kg moves with a velocity of 10ms-1. Calculate its momentum.
A
50.0 kgms-1
B
15.0 kgms-1
C
2.0 kgms-1
D
0.5 kgms-1
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Momentum = MV
= 5 x 10 = 50
Source: Myschool Past Questions Archive (Record #35438)
Physics
WAEC / WASSCE 2011
Mechanics and Properties of Matter
Solution
A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
A
0.75m
B
2.25m
C
8.22m
D
15.00m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S = U\(\sqrt{\frac{2h}{g}}\)
= 15\(\sqrt{\frac{2 \times 1.5}{10}}\)
= 8.22m
Source: Myschool Past Questions Archive (Record #35440)