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Physics
WAEC / WASSCE 2011
Electricity and Magnetism
Diagram
Solution
Using the circuit diagram above. Calculate the total charge in the circuit
Attached Figure / Diagram
A
80\(\mu C\)
B
35\(\mu C\)
C
20\(\mu C\)
D
16\(\mu C\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
C - \(C_1 + C_2 = 2 + 6 = \mu F\)
\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)
C = \(\frac{8}{5 \mu F}\)
Q = CV
= \(\frac{8}{5} \times 10 = 16\mu C\)
Source: Myschool Past Questions Archive (Record #35503)
Physics
UTME / JAMB 2011
Electricity and Magnetism
Solution
In Homes, electrical appliances and lamps are connected in parallel because
A
Parallel connections do not heat up the wires
B
independence switches can be used
C
less current will be used
D
less voltage will be used
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
if appliances are connected in series, the effective voltage is the sum of individual voltages which will be high.
Source: Myschool Past Questions Archive (Record #41406)
Physics
UTME / JAMB 2011
Electricity and Magnetism
Solution
In an A.C circuit, the ratio of r.m.s value to peak value of current is
A
2
B
\( \frac{1}{2} \)
C
\( \frac{1}{\sqrt{2}} \)
D
\( \sqrt{2} \)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Irms = \( \frac{I_0}{\sqrt{2}} \)
\( \text{Therefore } \sqrt{2Irms} = I_0 \\
\frac{Irms}{I_0} = \frac{1}{\sqrt{2}} \)
Source: Myschool Past Questions Archive (Record #41407)
Physics
WAEC / WASSCE 2011
Electricity and Magnetism
Solution
You are provided with cells, a potentiometer, an ammeter, a voltmeter, a bulb, a key, a jockey, and other necessary materials.
Measure and record the emf E of the battery.
Set up a circuit as shown in the diagram above.
Close the key K and use the jockey to make a firm contact at J on the potentiometer wire such that PJ = x = 10cm.
Take the record of the voltmeter reading V and the corresponding ammeter reading I.
Evaluate log V and log I.
Repeat the procedure for other values of x =20, 30. 40, 50, and 60cm.
Tabulate your readings.
Plot a graph with the log I on the vertical axis and log V on the horizontal axis.
Determine the slope, s, of the graph.
Determine the intercept, c, on the vertical axis.
State two precautions taken to ensure accurate results.
(b)i. How is the brightness of the bulb affected as x increases? Give a reason for your answer.
ii. List two electrical devices whose actions do not obey ohm's law
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Observation/table of values
S/N
V(volts)
I(Amps)
Log V
Log I
1
0.790
0.030
-0.100
-0.520
2
0.690
0.240
-0.160
-0.620
3
0.600
0.180
-0.220
-0.740
4
0.600
0.120
-0.220
-0.920
5
0.500
0.060
-0.300
-0.220
6
0.300
0.060
-0.520
-0.220
Slope (s) = \(\frac{\bigtriangleup \text{log I}}{\bigtriangleup \text{log V}} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
(s) = \(\frac{-0.4-(-1.4)}{-0.04-(-0.62)} = \frac{-0.4+1.4}{-0.04+0.62}\)
= \(\frac{1}{0.58}\)
s = 1.72
Graph Log I against Log V
PRECAUTIONS; i
- Ensured clean/tight terminals
- Opened key when reading was not taken
- Avoided parallax error in ammeter/ voltmeter.
- Avoided sliding or jockey on the potentiometer wire M Zero error of voltmeter/ammeter were noted.
(b)i. The brightness of the bulb increases. Voltage/current through the bulb increases.
ii. The devices that do not obey ohm's law;
Diode
Transistor
Thyristor
Capacitor
Thermistor
Source: Myschool Past Questions Archive (Record #60015)
Physics
UTME / JAMB 2010
Electricity and Magnetism
Solution
Three 4Ω resistors connected in parallel have a potential difference of 16 V applied across them. What is the total current in the circuit?
A
14 A
B
12 A
C
10 A
D
8 A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
1/R = 1/4 + 1/4 + 1/4 = 3/4
R = 4/3
I = V/R
= 164/3
= 16 x 3_4
= 12 A
Source: Myschool Past Questions Archive (Record #14514)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Solution
Eddy currents can be reduced by
A
using coil of high resistance
B
winding the coil on a soft iron core
C
creating holes in the metal plates
D
using coil of low resistance
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
This method interrupts the flow of eddy currents by increasing the resistance in the path of the currents, thereby reducing their magnitude.
Other Options:
A. Using a high-resistance coil: This does not directly affect eddy currents in conductive materials.
B. Winding the coil on a soft iron core can enhance magnetic effects and may not reduce eddy currents.
D. Using low resistance coil: This would not help reduce eddy currents; it could potentially increase the flow of currents.
Source: Myschool Past Questions Archive (Record #35353)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Solution
A galvanometer of internal resistance 50\(\Omega\) and full scale deflection of 20 mA is converted into a voltmeter by connecting a resistor of resistance 1950\(\Omega\) in series to it. Calculate the maximum voltage that can be read by the voltmeter
A
20V
B
30V
C
38V
D
40V
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
V = IR1 + IR2
= 0.02 x 50 + 0.02 x 1950 = 40V
Source: Myschool Past Questions Archive (Record #35341)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Which of the following factors does not affect the electric resistance of wire?
A
length
B
mass
C
temperature
D
cross-sectional area
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35345)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
A positively charged glass rod is placed near the cap of a positively charged electroscope. The divergence of the leaf is observed to
A
decrease
B
increase
C
remain the same
D
increase and collapse immediately
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #35332)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Diagram
Solution
Use the diagram above to calculate the current, I.
Attached Figure / Diagram
A
0.60A
B
0.97A
C
1.03A
D
5.00A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\)
= \(\frac{1}{6} + \frac{1}{4}\)
R = \(\frac{12}{5} = 2.5\Omega\)
R = 2.4 + 10 = 12.4
V = IR
I = \(\frac{v}{R} = \frac{12}{12.4} = 0.97\)
Source: Myschool Past Questions Archive (Record #35337)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Solution
When a lead-acid accumulator is fully charged, evolution of gases occurs at the electrodes. Name these gases and the respective electrodes at which thcy are given off.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Gases are:
(i) Hydrogen at Anode or Lead peroxide.
(ii) Oxygen at cathode or lead plate.
Source: Myschool Past Questions Archive (Record #53437)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Solution
(a) State two factors which affect the mass of elements deposited during electrolysis.
(b) List two non-electrolysis.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
Factors are:
- Current, time and electrochemical equivalent of the element
(b) Non-electrolytes are:
- Petrol, water, ethanol, kerosine, etc.
Source: Myschool Past Questions Archive (Record #53439)
Physics
WAEC / WASSCE 2010
Electricity and Magnetism
Solution
You are provided with a voltmeter V, a chemical cell/ battery E; two standard resistors R, and R a potentiometer a key K a jockey, and other necessary materials.
Set up a circuit as shown in the diagram above.
Close the key K.
Make contact with the potentiometer wire AB using the jockey at a point C such that AC = x = 20cm
Read and record the voltmeter reading
Evaluate x\(^{-1}\) and v\(^{-1}\)
Repeat the procedure for other values of x= 30, 40, 50, 60 and 80cm.
Tabulate your readings.
Plot a graph with V\(^{-1}\) on the vertical axis and x\(^{-1}\) on the horizontal axis, starting both axes from the origin (0, 0).
Determine the:
(a) slope, s, of the graph;
(b) intercept, c, on the vertical axis.
State two precautions taken to ensure accurate results.
(b)i. State the two devices in which ohm's law does not apply.
ii. A current of 1 A is supplied to two resistors of resistance 2\(\Omega\) and 3\(\Omega\) connected in parallel. Calculate the current in each resistor.
medium Difficulty
Verified Correct Answer: Option
Physical Principles & Numerical Solution
x/cm
v/volt
x\(^{1}\)/cm\(^{-1}\)
v\(^{1}\)/volts\(^{-1}\)
20
0.15
0.050
6.667
30
0.20
0.033
5.000
40
0.30
0.025
3.333
50
0.40
0.020
2.500
60
0.50
0.016
2.000
80
0.60
0.013
1.667
Slope = \(\frac{6.667-1.667}{0.050-0.013} = \frac{5}{0.037}\)
= 135.135cm/volt
intercept = 0
Precautions;
- Tight connections /clean terminals was ensured
- Key removed when readings are not being taken.
- Parallex error avoided in reading voltmeter/ rule.
- Zero error noted and corrected for in the voltmeter/rule
- Dragging jockey along the wire avoided
Source: Myschool Past Questions Archive (Record #60018)
Physics
WAEC / WASSCE 2009
Electricity and Magnetism
It takes 4 minutes to boil a quantity of water using an electrical heating coil. How long will it take to boil the same quantity of water using the same coil if the current is doubled? [Neglect any external heat losses]
A
8 minutes
B
4 minutes
C
2 minutes
D
1 minute
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #35182)
Physics
WAEC / WASSCE 2009
Electricity and Magnetism
Which of the following is not a part of the electro-magnetic spectrum?
A
x-rays
B
microwaves
C
infrared radiation
D
alpha rays
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #35198)