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Physics
UTME / JAMB 1980
Mechanics and Properties of Matter
Solution
The relative densities of zinc, brass, copper, gold and silver are respectively 7.1, 8.5, 8.9, 19.3, 10.5. A metal ornament which weighs 0.425kg and can displace 50 x 10-6m3m of water is made of
A
zinc
B
brass
C
copper
D
gold
E
silver
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
R.D = \(\frac{\text {density of object}}{\text{density of water}}\)
= \(\frac{\frac{0.425}{50 10^-6}{1000}\)
= 8.5
Source: Myschool Past Questions Archive (Record #29109)
Physics
UTME / JAMB 1980
Mechanics and Properties of Matter
Solution
Which of the following statements about sound is NOT true?
A
sound is a longitudinal wave
B
sound can be reflected and refracted like light
C
sound travels through a vacuum
D
sound moves faster in a steel wire than in air
E
sound can ony be produced by vibrating objects
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Sound cannot travel through a vacuum. A vacuum is an area without any air, like space. So sound cannot travel through space because there is no matter for the vibrations to work in.
Source: Myschool Past Questions Archive (Record #29115)
Physics
UTME / JAMB 1980
Mechanics and Properties of Matter
Solution
The activity of a radioactive substance depends on
A
temperature and purity
B
temperature and age
C
purity and age
D
age, purity and temperature
E
none of the above
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Radioactive decay is a nuclear process; therefore, it is not affected by Temperature, Pressure, Chemical state, or purity.
Even if impurities are present, they do not change the decay rate of the radioactive nuclei.
Therefore, Activity depends on the half-life/decay constant and the quantity of radioactive atoms present.
Source: Myschool Past Questions Archive (Record #29133)
Physics
UTME / JAMB 1980
Mechanics and Properties of Matter
Diagram
Solution
What is the acceleration of a particle whose motion is graphically displayed in the diagram above
Attached Figure / Diagram
A
0.67ms-2
B
0.83ms-2
C
0.87ms-2
D
92ms-2
E
2.0ms-2
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Take a straight line(both vertical and horizontal) to touch the straight line.
Acceleration = \(\frac{\text{change in velocity}}{\text{time}}\)
Acceleration = \(\frac{8.7 - 2}{10 - 0}\) = \(\frac{6.7}{10}\) = 0.67m/s\(^2\).
Source: Myschool Past Questions Archive (Record #41611)
Physics
UTME / JAMB 1980
Mechanics and Properties of Matter
Diagram
Solution
In the diagram above, MN is perpendicular to ON and MP. What is the difference between the moment about N of the force of 20 Newtons applied along MP and its moment about O?
Attached Figure / Diagram
A
Zero
B
0.2N.m
C
0.4N.m
D
0.8N.m
E
0.6N.m
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Given: Force \( P = 20 \, \text{N} \), Distance \( MN = 0.4 \, \text{m} \)
Moment About Point N: \(\text{Moment}_N = P \times MN = 20 \, \text{N} \times 0.4 \, \text{m} = 8 \, \text{Nm}\)
Moment About Point O: \(\text{Distance from O} = 0.5 \times \cos(36.87^\circ) \approx 0.4 \, \text{m}\)
\(\text{Moment}_O = P \times \text{Distance from O} = 20 \, \text{N} \times 0.4 \, \text{m} = 8 \, \text{Nm}\)
Difference Between Moments: \(\text{Difference} = \text{Moment}_N - \text{Moment}_O = 8 \, \text{Nm} - 8 \, \text{Nm} = 0 \, \text{Nm}\)
Source: Myschool Past Questions Archive (Record #41613)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
The density 400cm3 of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gm-3 after frying,assuming no loss of oil due to spilling, its new volume was
A
360cm3
B
600cm3
C
240cm3
D
800cm3
E
450cm3
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Since no loss of oil,
Density x volume = constant
D1V1 = D2 x V2
0.9 x 400 = V2
V2 = 600cm3
Source: Myschool Past Questions Archive (Record #29151)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
A 500kg car which was initially at rest travelled with an acceleration of 5m sec-2, its kinetic energy after 4 seconds was
A
105J
B
2.5 x 103J
C
2 x 103J
D
5 x 103J
E
5 x 105J`
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J
Source: Myschool Past Questions Archive (Record #29160)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
If the wavelength of a wave travelling with a velocity of 360ms-1 is 60m, the period of the wave is
A
6s
B
3.6s
C
0.17s
D
0.61s
E
3s
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
V = \(\alpha\)F and F = \(\frac{1}{T}\)
v = \(\frac{\pi}{T}\)
T = \(\frac{60}{360}\)
T = 0.17s
Source: Myschool Past Questions Archive (Record #29180)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
If a given mass at constant pressure obeys the relation...volume is proportional to the absolute temperature...the gas is said to obey
A
Hooke's Law
B
Boyle's Law
C
Dalton's Law
D
Charles' Law
E
Newton's Law
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #29188)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
A landlord has eight 40W electric light bulbs, four 60W bulbs and two 100W bulb in his house. If he has all the points on for five hours daily and if N.E.P.A. charges 5k per unit, his bill for 30 days is
A
N5.70
B
N7.23
C
N3.65
D
N8.05
E
N4.50
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Total power = (8 x 40) + (40 x 60) + (2 x 100)
= 760W
Energy(Kwhr) = power x time
= 760 x 10-3 x 150
= 114kwhr.
If, 1kwhr. cost 5k
thus, 114 kwhr. will cost 5 x 114
= N5.70
Source: Myschool Past Questions Archive (Record #29198)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Which of the following statements is correct? The reading of pressure on a mercury barometer is independent of
A
the cross-sectional area of the tube
B
the atmospheric pressure
C
the density of mercury
D
the temperature of mercury
E
the acceleration due to gravity
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #29199)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
An electric cell has an internal resistance of 2 ohms. A current of 0.5A is found to flow when a resistor of 5 ohms resistance is connected across it. What is the electromotive force of the cell?
A
5 volts
B
3.5 volts
C
2.5 volts
D
1 volts
E
10 volts
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
E.m.f. = I(R + r) = 0.5(2+5) = 3.5 volts
Source: Myschool Past Questions Archive (Record #29202)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
The bulb of a motorcycle head-lamp is marked 40W, 6V. The resistance of the filament when it is switched on is
A
\(\frac{6^2}{40^2}\)ohms
B
\(\frac{40}{6^2}\)ohms
C
\(\frac{40}{6}\)ohms
D
6 x 40 ohms
E
\(\frac{6^2}{40}\)ohms
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
Power \(\frac{V^2}{R}\)
40 = \(\frac{6 \times 6}{r}\)
R = \(\frac{36}{40}\)\(\Omega\)
Source: Myschool Past Questions Archive (Record #29205)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
An air bubble rises from the bottom to the top of a water dam which is 40m deep. The volume of the bubble just below the surface is 2.5cm3. Find its volume at the bottom of the dam, if atmospheric pressure is equivalent to 10m water
A
0.0cm3
B
2.0cm3
C
1.6cm3
D
0.625cm3
E
0.5cm3
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
At constant temperature P1V1 = P2V2
P2 = P1 + 40
= 10 + 40 = 50m
10 x 2.5 = 50 x V2
V2 = 0.5cm3
Source: Myschool Past Questions Archive (Record #29218)
Physics
UTME / JAMB 1979
Mechanics and Properties of Matter
Solution
All the heat generated in a 5 ohms resistor by 2A flowing for 30 seconds is used to evaporate 5g of a liquid at its boiling point. Which of the following is the correct value of the specific latent heat of the liquid?
A
120J
B
60Jg-1
C
120Jg-1
D
1500J
E
1500Jg-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Heat energy = Electrical energy
mL = I2RT
5 x L = 2 x 2 x 5 x 30
L = 120Jg-1
Source: Myschool Past Questions Archive (Record #29222)