Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 1636–1650 of 4910 verified questions
Sort by:
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Solution
The sum of the interior angles of regular polygon is 1800o. How many sides has the polygon?
A
16
B
12
C
10
D
8
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Sum = (n - 2)180
1800 = (n - 2)180
divide both sides by 180o
\(\frac{1800}{180}\) = (n - 2)\(\frac{180}{180}\)
10 = n - 2
10 + 2 = n
n = 12
Source: Myschool Past Questions Archive (Record #36794)
Mathematics
WAEC / WASSCE 2012
Number and Numeration
Solution
Find the coefficient of m in the expression of (\(\frac{m}{2} - 1 \frac{1}{2}\)) (m + \(\frac{2}{3}\))
A
-\(\frac{1}{6}\)
B
- \(\frac{1}{2}\)
C
-1
D
-1\(\frac{1}{6}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
(\(\frac{m}{2} - 1\frac{1}{4}\))(m + \(\frac{2}{3}\))
(\(\frac{m}{2} - \frac{3}{2}\))(\(\frac{m}{1} + \frac{2}{3}\))
= \(\frac{m^2}{3} + \frac{3m}{6} - \frac{6}{6}\)
= \(\frac{2m - 9m}{6}\)
= \(\frac{-7m}{6}\)
= 1\(\frac{1}{6}\)
Source: Myschool Past Questions Archive (Record #36796)
Mathematics
WAEC / WASSCE 2012
Number and Numeration
Solution
The volume of a cuboid is 54cm3. If the length, width and height of the cuboid are in the ratio 2:1:1 respectively, find its total surface area
A
108cm2
B
90cm2
C
80cm2
D
72cm2
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
V = L x B x H
V = \(2x \times x \times x = 2x^3\)
= 54cm3
i.e. 2x3 = 54
x3 = \(\frac{54}{2}\) = 27
x = 3\(\sqrt{27}\)
x = 3
L = 2x i.e. 2 x 3 = 6cm
B = x i.e. x = 3cm
H = x i.e. x = 3cm
but A = 2(LB + LH + BH) = 2(6 x 3) + (6 x 3) + (3 x 3) = 2(18 + 18 + 9) = 2(45)
= 90cm2
Source: Myschool Past Questions Archive (Record #36799)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Solution
A side and a diagonal of a rhombus are 10cm and 12cm respectively, Find its area
A
20cm2
B
24cm2
C
48cm2
D
96cm2
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
From the diagram above
B\(^2\) = 10\(^2\) - 6\(^2\) = 64
B = \(\sqrt{64}\) = 8 cm( B represent half the second diagonal not given)
So, the second diagonal not given = 8 + 8 = 16cm.
But, Area of a rhombus = \(\frac{1}{2}\) x both diagonals that is, \(\frac{1}{2}\) x d\(_1\) x d\(_2\)
Area of a rhombus = \(\frac{1}{2}\) x 12 x 16 = 6 x 16 = 96cm\(^2\)
Source: Myschool Past Questions Archive (Record #36800)
Mathematics
WAEC / WASSCE 2012
Number and Numeration
Factorise completely: 32x2y - 48x3y3
A
16x2y(2 - 3xy2)
B
8xy(4x - 6x2y2)
C
8x2y(4 - 6xy2)
D
16xy(2x - 3x2y2)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #36801)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
If x and y are variables and k is a constant, which of the following describes an inverse relationship between x and y?
A
y = kx
B
y = \(\frac{k}{x}\)
C
y = k\(\sqrt{x}\)
D
y = x + k
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #36803)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Diagram
Solution
In the diagram, |QR| = 10m, |SR| = 8m
o, o and |PS| = x, Find x
Attached Figure / Diagram
A
1.32m
B
6.32m
C
9.32m
D
17.32
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
In right angled \(\bigtriangleup\)QPR
tan 30o = \(\frac{10}{x + 8}\)
(x + 8) tan 30 = 10
x + 8 = \(\frac{10}{0.5773}\)
x +8 = 17.3
x = 17.3 - 8
x = 9.32
Source: Myschool Past Questions Archive (Record #36805)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Diagram
Solution
In the diagram, O is a circle centre of the circle PQRS and o. If o, find x
Attached Figure / Diagram
A
108o
B
172o
C
130o
D
50o
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
xo = 86 x 2(angle at centre = 2 x angle at circumference)
= 172o
Source: Myschool Past Questions Archive (Record #36806)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Diagram
Solution
The diagram is a circle centre O. If < SPR = 2m and < SQR = n, express m in terms of n
Attached Figure / Diagram
A
m = \(\frac{n}{2}\)
B
m = 2n
C
m = n - 2
D
m = n + 2
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
If < SPR = 2m then < SQR = 2m but < AQR was n
n = 2m
m = \(\frac{n}{2}\)
Source: Myschool Past Questions Archive (Record #36807)
Mathematics
WAEC / WASSCE 2012
Number and Numeration
Diagram
Solution
In the diagram, MQ//RS, o and o. Find the value of x
Attached Figure / Diagram
A
150o
B
110o
C
100o
D
95o
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
L + 30o - 180o(Sum of o - 30o = 150o
L = q = 150o(opposite o(alt. o(sum of o + c 180
c = 180 - 30
c = 150o
b = a = 30o (opp o (opp o = 180o (sum of o + k + 70o = 180
k + 100o = 180
k = 180 - 100
k = 80o
x + 80o = 180(sum of o - 80o
x = 100o
Source: Myschool Past Questions Archive (Record #36809)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Diagram
Solution
Is the diagram, MN, PQ and RS are three intersecting straight lines. Which of the following statements is/are true? i. t = y ii. x + y + z + m = 180o iii. x + m + n = 180o iv. x + n = m + z
Attached Figure / Diagram
A
i and iv
B
ii
C
iii
D
iv
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
m + y + x = 180o(sum of < s on straight line)
y = n(vertically opp. angle)
m + n + x = 180o
Source: Myschool Past Questions Archive (Record #36810)
Mathematics
WAEC / WASSCE 2012
Geometry and Trigonometry
Diagram
Solution
The position of three ships P,Q and R at sea are illustrated in the diagram. The arrows indicated the North direction. The bearing of Q from P is 050o and < PQR = 72o. Calculate the bearing of R and Q
Attached Figure / Diagram
A
155o
B
80o
C
158o
D
91o
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
< NPQ = < PQB = 50º(alt. < s)
< PQB = 50º
< PQR = < PQR < PQB + < QBR = 72º
< QBR = < PQR - < PQB = 72º - 50º
= 22º
< NQR = 180 - < QBR = 180º - 22 = 158º, the bearing of R from Q = 158º
Source: Myschool Past Questions Archive (Record #36811)
Mathematics
WAEC / WASSCE 2012
Statistics and Probability
Diagram
Solution
The bar chart shows the frequency distribution of marks scored by students in a class test. How many students are in the class?
Attached Figure / Diagram
A
10
B
24
C
25
D
30
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
6 + 8 + 6 + 5 = 25
Source: Myschool Past Questions Archive (Record #36813)
Mathematics
WAEC / WASSCE 2012
Statistics and Probability
Diagram
Solution
The bar chart shows the frequency distribution of marks scored by students in a class test. Calculate the mean of the distribution.
Attached Figure / Diagram
A
6.0
B
3.0
C
2.4
D
1.8
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\begin{array}{c|c} x & f & fx\\ \hline 1 & 6 & 6 \\
2 & 8 & 16\\ 3 & 8 & 18\\ 4 & 5 & 20\end{array}\)
mean x = \(\frac{\sum fx}{\sum f}\)
= \(\frac{60}{25}\)
x = 2.4
Source: Myschool Past Questions Archive (Record #36814)
Mathematics
WAEC / WASSCE 2012
Statistics and Probability
Diagram
Solution
The bar chart shows the frequency distribution of marks scored by students in a class test. What is the median of the distribution?
Attached Figure / Diagram
A
2
B
4
C
6
D
8
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
median = (\(\frac{N + 1}{2}\))th = (\(\frac{25 + 1}{2}\))th
= \(\frac{26th}{2}\)
= 13th
the 13th is 2
Source: Myschool Past Questions Archive (Record #36815)