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a = \(\frac{v - u}{\Delta t}\) a = \(\frac{20 - 10}{20 - 5}\) a = 0.67ms-1

No expanded working has been attached for this question yet. The verified answer is Option C.

Efficiency = \(\frac{output}{input}\) x 100 40 = \(\frac{20\times10}{input}\) x \(\frac{100}{1}\) input = 500J work against friction = input - output = 500 - 200 = 300J

No expanded working has been attached for this question yet. The verified answer is Option D.

Mw displaced = 40g density = \(\frac{mass}{\text{area x height}}\) I = \(\frac{40}{2\times h}\) h = 20cm

100\(\theta\) .... 875mm 0\(\theta\) ....325mm \(\theta\) .... 190mm \(\frac{0 - \theta}{100 - \theta}\) = \(\frac{325 - 190}{875 - 190}\) \(\theta\) = -25oC = 243k

\(\frac{V_1P_1}{T_1}\) = \(\frac{V_2P_2}{T_2}\) \(\frac{70 \times 1200}{7 \times 273}\) = \(\frac{75 \times V_2}{27 + 273}\) V2 = 1200cm3

Elect. energy = heat energy IVt = mL 20 X 12 t = 1.5 x 336 x 103 t = 2100 sec ; t = 35mins.

\(\lambda\) = 2L 2 x 17 = 34cm F = \(\frac{V}{\lambda}\) = \(\frac{340}{34 \times 10^{-2}}\) = 1000Hz

n = \(\frac{\text{wavelength in space}}{\text{wavelength in glass}}\) 1.5 = \(\frac{5000 \times 10^{-8}}{\lambda g}\) \(\lambda\)g = 3333 x 10-8cm

The maximum kinetic energy of an emitted electrons is independent of the intensity of the incident light but proportional to the frequency ( wavelength) of incident light. increasing the intensity of light only increases the number of photo-electrons

Due to their significantly smaller mass, beta particles have much less inertia and are easily "pushed" by the magnetic force, leading to a much greater deflection (curved path) compared to the heavy, bulky alpha particles.

No expanded working has been attached for this question yet. The verified answer is Option B.

No expanded working has been attached for this question yet. The verified answer is Option D.

No expanded working has been attached for this question yet. The verified answer is Option B.