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Physics
WAEC / WASSCE 2018
Heat Energy & Temperature
Diagram
Solution
The circuit contains three ammeters A1, A2 and A3 with readings of A2 and A3 shown as indicated in the diagram. Determine the reading of A1.
Attached Figure / Diagram
A
2A
B
3A
C
5A
D
8A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Ammeters are connected in series so,
A3= A2 + A1
A1 = A3 - A1
= 5A - 2A
= 3A
Source: Myschool Past Questions Archive (Record #49857)
Physics
WAEC / WASSCE 2018
Heat Energy & Temperature
Solution
In a series R-L-C circuit, R = 10\(\Omega\), \(X_{c}\)= 4\(\Omega\) and \(X_{L}\) = 9\(\Omega\). The impedance of the circuit is
A
4.1\(\Omega\)
B
5.0\(\Omega\)
C
10.8\(\Omega\)
D
11.2\(\Omega\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The impedance for a RLC circuit is
\(Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}\)
= \(\sqrt{10^{2} + (9 - 4)^{2}}\)
= \(\sqrt{125}\)
= 11.18\(\Omega\) \(\approxeq\) 11.2\(\Omega\)
Source: Myschool Past Questions Archive (Record #49874)
Physics
WAEC / WASSCE 2018
Heat Energy & Temperature
In which of the following fields is radioisotopes not used?
A
Medicine
B
Oil industry
C
Agriculture
D
Weather forecast
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #49894)
Physics
UTME / JAMB 2018
Heat Energy & Temperature
Solution
The critical angle for light traveling from a transparent medium to air s measured as 34º. The refractive index of the medium is
A
0.56
B
1.50
C
1.79
D
2.02
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
N = \(\frac{1}{sin\theta}\)
= \(\frac{1}{sin34}\)
= 1.79
Source: Official Exam / Past Question Archive
Physics
WAEC / WASSCE 2018
Heat Energy & Temperature
Solution
You are provided with an ammeter, a resistor, key, metre bridge, and other necessary apparatus.
i. Connect a circuit as shown in the diagram above.
ii. Close the key and use the jockey to make contact with AB at N such that AN = d = 25cm
iii. Read and record the ammeter reading.
iv. Evaluate 1\(^{-1}\).
v. Repeat the procedures for values of d = 35cmm, 50cm, 65cm and 80cm. In each case, record I and determine 1\(^{-1}\)
vi. Tabulate your results.
vii. Plot a graph with log on the vertical axis and d on the horizontal axis.
viii. Determine the slope, s of the graph.
ix. State two precautions taken to obtain accurate results.
(b)i. Use your graph to determine the value of d = l = 1.5A.
ii. State two factors that affect the resistance of a wire.
A
0.5
B
0.8
C
1.2
D
1.5
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
S/N
d(cm)
I(A)
I\(^{1}\)(A\(^{-1}\))
Log I\(^{-1}\)
1
25
0.65
1.54
0.19
2
35
0.55
1.82
0.26
3
50
0.44
2.50
0.40
4
65
0.30
3.33
0.52
5
80
0.23
4.35
0.64
vii. Scale: 2cm to 10 units on x-axis
2cm to 0.1 unit on y-axis
viii. Slopes(s) = \(\frac{x_{2} - x_{1}}{y_{2} - y_{1}}\)
= \(\frac{80 -25}{0.64 - 0.20}\)
= \(\frac{55}{0.44}\)
= 125
(ix) Precautions
(a) Key opened in between reading or keys opened when readings were not taken
(b) Tight connections ensured
(c) Avoided parallax error when taking reading on ammeter or metre rule
(d) Repeated readings shown
(e) Avoided zero error on ammeter or metre rule
(f) Clean terminals ensured.
(b)i. 1\(^{-1}\) = \(\frac{1}{1.5}\)
= 0.67
Log(1\(^{-1}\)) =-0.174
ii. Factors affecting the resistance of a wire
- Length of wire
- Cross-sectional area/ thickness/ diameter/ radius of wire
- Resistivity or nature of wire
- Temperature.
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
Which is the incorrect formula for a body accelerating uniformly?
A
a = v2 − \(\frac{u^2}{2}\)
B
v2 = u2 + 2as
C
s = ut + \(\frac{1}{2}\) at2
D
v2 − u2= 2as
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Look through the equations of motion
Source: Myschool Past Questions Archive (Record #46372)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
Which of the following statements is NOT correct?
A
Molecules of a liquid are stationary
B
Brownian motion is an evidence of particle nature of matter
C
Matter is made up of molecules
D
The molecules of matter are in constant motion
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Molecules of liquid are not stationary
Brownian motion is an evidence of particle nature of matter
matter is made up of molecules
The molecules of matter are in constant motion
Source: Myschool Past Questions Archive (Record #46386)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
A block and tackle pulley arrangement has 6 pulleys in which an effort of 50N supports a load of 200N, calculate the efficiency of the machine
A
80.0%
B
76.6%
C
66.7%
D
60.7%
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Efficiency = \(\frac{ma}{V.R}\) x \(\frac{100}{1}\)
V.R = number of pulleys = 6
ma = \(\frac{\text{Load}}{\text{Effort}}\) = \(\frac{200}{50}\) = 4
Effiecieny = \(\frac{4}{6}\) × 100 = 66.67%
Source: Myschool Past Questions Archive (Record #46389)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
An element and its isotope only differ in the number of
A
protons
B
electrons
C
ions
D
neutrons
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Isotopy is due to difference in mass number, what causes the difference is the difference in the number of neutrons present
Source: Myschool Past Questions Archive (Record #46392)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
Calculate the height of the image formed by a pinhole camera of length 12cm used to photograph an object 60cm away from the hole and 70cm high
A
10 cm
B
16 cm
C
5 cm
D
14 cm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Magnification = \(\frac{\text{Length of camera}}{\text{distance of object from pin hole}}\)
m = \(\frac{12}{60}\)
= 0.2
Also magnification m = \(\frac{\text{Height of image}}{\text{Height of object}}\)
∴ Height of image = m \times height of object
= 0.2 \times 70
= 14cm
Source: Myschool Past Questions Archive (Record #46396)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Diagram
Solution
The net capacitance in the circuit above is
Attached Figure / Diagram
A
80µF
B
6.0µF
C
4.0µF
D
2.0µF
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
For capacitance i n parallel, 2µF and 2µF are in parallel,
their equivalence is 2µF and 2µF = 4µF
The 4µF generated is now in series with the remaining 4µF.
The net capacitance for series connection is
\(\frac{1}{C}\) = \(\frac{1}{4}\) + \(\frac{1}{4}\) = 1 + \(\frac{1}{4}\) = \(\frac{2}{4}\)
C = \(\frac{4}{2}\)
= 2µF
Source: Myschool Past Questions Archive (Record #46400)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
Which of the following is a scalar quantity?
A
Tension
B
Weight
C
Impulse
D
Mass
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Scalar quantity is a quantity with only magnitude, it has no direction
Tension, weight, impulse are vector quantities because they have direction. Mass is the only scalar quantity there
Source: Myschool Past Questions Archive (Record #46404)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
Which of the following is a semiconductor
A
copper
B
silicon
C
plastic
D
Iron
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Semi-conductor have an elecctric conductivity intermediate in value between that of a pure metal and a good insulator. Silicon is an example
Source: Myschool Past Questions Archive (Record #46433)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
What is the speed of a body vibrating at 50 cyclic per second
A
100 πrads\(_{−1}\)
B
200 πrads\(_{−1}\)
C
50 πrads\(_{−1}\)
D
400 πrads\(_{−1}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
1 cycle = 360^\circ = 2\pi rad
∴ 50 cycle = 2 \pi rad \times 50 = 100 \pirad
∴ = angular speed = 50 cycles per seconds = 100 \pi rads\(_{−1}\)
Source: Myschool Past Questions Archive (Record #46437)
Physics
UTME / JAMB 2017
Heat Energy & Temperature
Solution
The action of blotting paper on ink is due to
A
diffusion
B
osmosis
C
capillarity
D
surface tension
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Capillarity is the tendency of a liquid to rise or fall in a narrow tube and it explains why a blotting paper absorbs ink
Source: Myschool Past Questions Archive (Record #46438)