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The colors of the visible light spectrum with the shortest and longest wavelengths respectively are: Violet and red. Violet light has the shortest wavelength among visible colors, while red light has the longest wavelength. The visible light spectrum, in order of increasing wavelength, goes from violet to blue, green, yellow, orange, and finally red.

The correct statement is: The acceleration of P is equal to that of Q and both are in the same direction. When ball P is released from the roof of the building, it falls freely under the influence of gravity. Similarly, when ball Q is thrown vertically upward, it initially moves upward but is also under the influence of gravity, which acts to slow it down and eventually makes it fall back down. Both balls, P and Q, are subjected to the same acceleration due to gravity (assuming no other forces are acting on them), which is approximately 9.8 m/s² near the surface of the Earth, and this acceleration acts in the downward direction. Therefore, the acceleration of P is equal to the acceleration of Q, and both are in the same direction, which is downward.

\(M_{bullet}\) = 0.05kg, \(V_{bullet}\) = 200m/s, \(M_{block}\) = 0.95kg and \(V_{block}\) = 0 for an inelastic collision \(M_{bullet} \times V_{bullet} + M_{block} \times V_{block} = (M_{bullet} + M_{block})\)v 0.05 x 200 + 0.95 x 0 = ( 0.05 + 0.95)v 10 + 0 = v v = 10m/s K.E of the block = \(\frac{1}{2}mv^2\) K . E = \(\frac{1}{2} \times(0.05 + 0.95) \times10^2\) ( bullet now part of the block) K . E = \(\frac{1}{2} \times1 \times100\) = 50J

The Rutherford scattering experiment showed that the nucleus of an atom: is concentrated in a tiny volume and is positively charged. In the experiment, when alpha particles were fired at a thin gold foil, most of the alpha particles passed straight through, but a few were deflected considerably. This result led Rutherford to conclude that the positive charge of the atom is concentrated in a small, dense nucleus at the center of the atom. The fact that some alpha particles were deflected strongly indicated that there was a positively charged nucleus within the atom. This experiment was crucial in developing our understanding of atomic structure and led to the model of the atom with a central nucleus containing protons and neutrons, surrounded by electrons.

The force of attraction between the nucleons (protons and neutrons) in the nucleus of an atom is called the nuclear force or strong nuclear force. This force is responsible for holding the protons and neutrons together in the nucleus despite the electrostatic repulsion between positively charged protons. It is one of the fundamental forces in nature and plays a crucial role in the stability of atomic nuclei.

When an electron jumps directly from an orbit of n = 4 to n = 2, a photon is emitted. This is a typical scenario in atomic physics where an electron transitions from a higher energy level (orbit) to a lower energy level. During this transition, the electron loses energy, and this energy is emitted in the form of a photon. The energy of the emitted photon corresponds to the energy difference between the two energy levels, as described by the quantization of energy levels in the Bohr model of the atom.

Acceleration of A = a Acceleration of B = 2a (given) then: \( S_A = 0 \times t + \frac{1}{2}at^2 = \frac{1}{2}at^2\) \( S_B = 0 \times t + \frac{1}{2} \times2at^2 = at^2\) \(t^2 = t^2 ⇒ \frac{2S_A}{a} = \frac{S_B}{a}\) ⇒ \(2S_A = S_B\) ( as a cancels out)

The part of the human eye that performs a function similar to the diaphragm in a camera lens is the Iris. Just like the diaphragm in a camera lens controls the amount of light entering the camera, the iris in the eye controls the amount of light that enters the eye by adjusting the size of the pupil. It can contract or expand to regulate the size of the pupil in response to varying light conditions, thus controlling the amount of light that reaches the retina at the back of the eye.

The equation f = \(\frac{1}{D}\) is not a correct mirror formula

The device associated with alternating currents (AC) only from the provided options is the step-up transformer. Step-up transformers are specifically designed to work with alternating currents and are used to increase voltage levels in AC systems.

The conclusive test for magnetism in a steel bar suspended horizontally at its midpoint is when the bar always settles in the magnetic N-S (North-South) direction.

The purpose of commutators in a direct current (DC) motor is to reverse the direction of the current after every half rotation.

F = \(kv^xρ^yA^z\) For the left-hand side: F = mass \times acceleration = \(MLT^{-2}\) For the right-hand side: v = \(LT^{-1}\), ρ = \(ML^{-3}\) and A = \(L^2\) So, \(MLT^{-2} = k(LT^{-1})^x(ML^{-3})^y(L^2)^z\) Since k is dimensionless, \(MLT^{-2} = (LT^{-1})^x(ML^{-3})^y(L^2)^z\) \(MLT^{-2} = L^x \times T^{(-1)x} \times M^y \times L^{(-3)y} \times L^{(2)z}\) \(MLT^{-2} = L^x \times T^{-x} \times M^y \times L^{-3y} \times L^{2z}\) \(MLT^{-2} = L^{(x - 3y + 2z)} \times T^{-x} \times M^y\) \(M^1L^1T^{-2}= L^{(x - 3y + 2z)} \times T^{-x} \times M^{y}\) Comparing the powers: For M, y = 1 For L, x - 3y + 2z = 1 ---- (i) For T, -x = -2 ∴ x = 2 Substitute (2) for x and (1) for y in equation (i) ⇒ 2 - 3(1) + 2z = 1 ⇒ 2 - 3 + 2z = 1 ⇒ -1 + 2z = 1 ⇒ 2z = 1 + 1 ⇒ 2z = 2 ∴ z = 1 Hence, x = 2, y = 1 and z = 1.

a. Strain energy is the potential energy stored within an elastic material as a result of its deformation caused by external forces. b. Energy stored E = \(\frac{1}{2}Fe\) Young Modulus = \(\frac{ Stress}{ Strain}\) = Y Stress = \(\frac{Force}{Area} = \frac{(F)}{(A)}\) Strain = \(\frac{ Extension}{Original Length} = \frac{(e)}{(l)}\) Y = \(\frac{F}{A}\div \frac{e}{l}\) Y = \(\frac{F}{A} \times \frac{l}{e}\) F = \(\frac{YAe}{l}\) Therefore, Energy stored E = \(\frac{1}{2}\frac{YAe}{l}\times e\) E = \(\frac{YAe^2}{2l}\)

i. From v = u + gt: \(u_x\) = ucos\theta, g = 0 (horizontal component is not affected by gravity) \(v_x\) = ucos\theta + (0)t ∴ \(v_x\) = ucos\theta ii. \(v_y = u_y + gt\) ∴ \(v_y = usin\theta + gt\) b. It assumes that the only force acting on the projectile is gravity, and there are no other forces, such as air resistance or drag, affecting its motion.