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The correct order is usually splash erosion, followed by sheet erosion, then rill erosion, and finally gully erosion. "Roll" is not a recognized stage in the erosion process, and it seems to be a misunderstanding of the term "rill erosion" which refers to small, parallel channels. Splash erosion: This is the initial stage where raindrops dislodge soil particles. Sheet erosion: Water flows in a thin sheet across the land, removing a uniform layer of soil. Rill erosion: Water concentrates into small, narrow channels, and these channels are called rills. Gully erosion: Rills grow into larger, deeper channels called gullies.

No expanded working has been attached for this question yet. The verified answer is Option C.

No expanded working has been attached for this question yet. The verified answer is Option D.

The yolk (also known as the vitellus) is the nutrient-bearing portion of the egg whose primary function is to supply food for the development of the embryo. Albumen proteins are known to flow into the amniotic cavity, the yolk sac and finally the digestive tract of the embryo and are used as the main source of proteins for tissue synthesis. They are labelled 3 & 4 respectively.

The yolk (also known as the vitellus) is the nutrient-bearing portion of the egg whose primary function is to supply food for the development of the embryo. Albumen proteins are known to flow into the amniotic cavity, the yolk sac and finally the digestive tract of the embryo and are used as the main source of proteins for tissue synthesis. They are labelled 3 & 4 respectively.

81a\(^4\) - 16b\(^4\) = (9a\(^2\))\(^2\) - (4b\(^2\))\(^2\) = (9a\(^2\) + 4b\(^2\))(9a\(^2\) - 4b\(^2\)) N:B 9a\(^2\) - 4b\(^2\) = (3a - 2b)(3a + 2b)

f(x) = Lx3 + 2kx2 + 24 f(-2) = -8L + 8k = -24 4L - 4k = 12 f(1):L + 2k = -24 L - 4k = 3 3k = -27 k = -9 L = -6

O\(\hat{P}\)T = 90º (The radius is perpendicular to the tangent at the point of contact.) Sum of angles in \(\triangle\) PQT = 30 + ( 90 + x ) + (x + 2x) = 180 = 120 + 4x = 180 4x = 180 - 120 = 60º x = \(\frac{60}{4}\) = 15^\circ Therefore, P\(\hat{T}\)O = 2x = 2 x 15 = 30º

Let the bearing of H from P be represented by x^\circ. \(\tan \theta = \frac{30}{60} = 0.5\) \(\theta = \tan^{-1} (0.5) = 26.565^\circ\) \(x = 180^\circ + (90 - 26.565)\) \(x = 180 + 63.435 = 243.435^\circ\) = \(243^\circ 26'\)

Latent heat of Vaporization is much greater than Latent Heat of Fusion for a given substance since vaporization involves more energy to separate molecules as well as to push back on the surrounding atmosphere.

Current = \(\frac{\text{Voltage}}{\text{Resistance}}\) I\(_1 = \frac{10}{2}\) = 5A I\(_2 = \frac{10}{1}\) = 10A I\(_3 = \frac{20}{3}\) = 6.67A I\(_4 = \frac{20}{2}\) = 10A I\(_5 = \frac{20}{1}\) = 20A

First re-arrange the given data in the form 3, 5, 5, 5, 7, 8, 9. 3, 5, 5,|5| 7, 8, 9 median(M) = 5 mode(D) = 5 (M, D) = (5, 5)

Total sharing ratio is 9 X has 4, Y has 4 + 1 If 1 is N5000 Total profit = 5000 x 9 = N45,000

Sum of interior angles of polygon = (2n - 4)rt o = (12 - 4) x 90o = 8 x 90o = 720o each interior angle will have \(\frac{720^o}{6}\) = 120o

\(x \propto y^{3} z^{4}\) \(x = ky^{3} z^{4}\) If y is halved and z is doubled, we have \(x = k (\frac{1}{2} y)^{3} (2z)^{4}\) \(x = k (\frac{y^{3}}{8}) (16z^{4})\)\) \(x = 2k y^{3} z^{4}\) \(\therefore \text{x is increased in the ratio 2 : 1}\)