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Physics
UTME / JAMB 1984
Current Electricity & Electric Circuits
Solution
What is the cost of running five 50W lamps and four 100W lamps for 10 hours if electrical energy costs 2 kobo per kWh?
A
N0.65
B
N0.13
C
N3.90
D
N39.00
E
N234.00
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
PT = (5 x 50) + (100 x 4)
= 650watts
Energy(kWhr) = 650 x 10-3 x 10
= 6.5 kWhr
1kWhr cost 2 kobo ; 6.5 kWhr will cost \(\frac{2 \times 6.5}{1}\)
= 13 kobo
Source: Myschool Past Questions Archive (Record #28739)
Physics
UTME / JAMB 1984
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Which of the following statements is (are) NOT true about the emission of the photoelectrons from metallic surfaces?
i. all metallic surfaces emits the same number of photoelectrons in a given light
ii. most metallic surfaces emit the same number of photoelectrons in visible and infra-red light
iii. a metallic surface emits photoelectrons only if the frequency of the incident light is higher than its own characteristics threshold frequency
A
i only
B
ii only
C
i and ii
D
ii and iii
E
iii only
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
i. All metallic surfaces emit the same number of photoelectrons in a given light, ii. Most metallic surfaces emit the same number of photoelectrons in visible and infrared light
are false
Source: Myschool Past Questions Archive (Record #28740)
Physics
UTME / JAMB 1984
Current Electricity & Electric Circuits
Solution
In the diagram above, X and Y have resistances 6 and 4 ohms respectively, if the power dissipation in X is 10W then power dissipation in Y is
A
2.4W
B
4
C
6.0W
D
6.7W
E
15.0W
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
P = \(\frac{ V^2}{R}\)
\(P_1 R_1 = P_2 R_2\) ( Parallel circuit)
10 x 4 = \(P_2\) x 6
\(P_2\) = \(\frac{40}{6}\) = 6.7W.
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 1984
Circular Motion, Gravitation & Simple Harmonic Motion
A simple pendulum, 0.6m long, has a period of 1.5s. What is the period of a similar pendulum of 0.4m length in the same location?
A
\( 1.5 \frac{ \sqrt{2}}{3} \)s
B
\( 1.5 \frac{ \sqrt{3}}{2} \)s
C
2.25s
D
1.00s
E
2.00s
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #41566)
Physics
UTME / JAMB 1984
Current Electricity & Electric Circuits
Diagram
Solution
What is the resistance of the circuit shown above
Attached Figure / Diagram
A
4Ω
B
11Ω
C
19/5Ω
D
17/4Ω
E
8Ω
medium Difficulty
Verified Correct Answer: Option E
Physical Principles & Numerical Solution
from the diagram, 2ohms and 2ohms are parallel, then total resistance = 1ohms
1ohms, 3ohms and the 4ohms are in series
then total resistance = 1 + 3 + 4 = 8ohms.
Source: Myschool Past Questions Archive (Record #41642)
Physics
UTME / JAMB 1984
Work, Energy, Power & Simple Machines
Diagram
Solution
A force varying linearly with the distance acts on a body as shown above, The work done on the body by the force during the first 10m of motion is
Attached Figure / Diagram
A
100J
B
150J
C
200J
D
300J
E
600J
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The graph shows the force decreasing linearly from 20 N at 0 m to 0 N at 20 m.
For the first 10 m:
- Force at 0 m = 20 N
- Force at 10 m = 10 N (midway)
The area under the graph (work done) is the area of a trapezium:
\(\text{Work} = \frac{1}{2} \times (20 + 10) \times 10 = 15 \times 10 = \mathbf{150\, J}\).
Source: Myschool Past Questions Archive (Record #41643)
Physics
UTME / JAMB 1984
Magnetism, Electromagnetism & AC Circuits
Diagram
Solution
A short bar magnet is placed in earth's magnetic field, as shown above, which of the points II and III are/is possible positions of a neutral point?
Attached Figure / Diagram
A
I only
B
II only
C
III only
D
I and II
E
I,II and III
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
When the magnet is placed with its north pole pointing toward the earth's magnetic north, the two neutral points will occur at III, according to the diagram above.
Source: Myschool Past Questions Archive (Record #41644)
Physics
UTME / JAMB 1984
Electrostatics & Capacitors
Diagram
In the circuit Shown above, calculate the effective capacitance between X and Y
Attached Figure / Diagram
A
3/4µF
B
\( 2 \frac{10}{13} µF\)
C
12µF
D
\( 4 \frac{12}{13} µF\)
E
13µF
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #41645)
Physics
UTME / JAMB 1984
Current Electricity & Electric Circuits
Diagram
Solution
In the diagram above, X and Y have resistances 6 and 4 ohms respectively, if the power dissipation in X is 10W then power dissipation in Y is
Attached Figure / Diagram
A
2.4W
B
4
C
6.0W
D
6.7W
E
15.0W
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
P = \(\frac{ V^2}{R}\)
\(P_1 R_1 = P_2 R_2\) ( Parallel circuit)
10 x 4 = \(P_2\) x 6
\(P_2\) = \(\frac{40}{6}\) = 6.7W.
Source: Myschool Past Questions Archive (Record #41646)
Chemistry
UTME / JAMB 1984
Nature of Matter & Separation Techniques
Sodium chloride may be obtained from brine by
A
titration
B
decantation
C
distillation
D
evaporation
E
sublimation
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27607)
Chemistry
UTME / JAMB 1984
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
20 cm\(^3\) of hydrogen gas are sparked with 20cm\(^3\) of oxygen gas in an endimoeter at 373k (100\(^0\)C) and 1 atmosphere. The resulting mixture is cooled to 298 K (25 oC) and passed over calcium chloride. The volume of the residual gas is
A
40 cm 3
B
20 cm 3
C
30 cm 3
D
10cm 3
E
5cm 3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
2H\(_2\) + O\(_2\) → 2H\(_2\)O
From the balanced equation: 2cm\(^3\) : 1cm\(^3\) 2cm\(^3\)
From the question,expected vol. reacted: 20cm\(^3\) 20cm\(^3\)
Actual volume that reacted: 20cm\(^3\) 10cm\(^3\) 20cm\(^3\) → Following the balanced equation i.e ratio 2 : 1 : 2
Volume of H\(_2\) remaining = Expected volume - Actual volume = 20 - 20 = 0cm\(^3\) ⇒ H\(_2\) was used up, hence it's the limiting reactant.
Volume of O\(_2\) remaining = Expected volume - Actual volume = 20 - 10 = 10cm\(^3\) ⇒ O\(_2\) was in excess, thus it was remaining
Residual volume of the O\(_2\) is 10cm\(^3\)
Source: Myschool Past Questions Archive (Record #27609)
Chemistry
UTME / JAMB 1984
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
For the reaction NH4NO2 \(\to\) N2 + 2H2O, calculate the volume of nitrogen that would be produced at S. T. P from 3.2 g of the dioxonitrate(iii)salt. (Relative atomic masses: N = 14, O = 16, H = 1)
A
2.24 dm 3
B
2.24 cm3
C
1. 123
D
1. 12dm 3
E
4. 48 dm 3
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
\(NH_{4}NO_{2}\) \(\to\) \(N_{2}\) + \(2H_{2}O\)
\(64g\) \(\to\) \(22.4dm^{3}\)
\(3.2g\) will give \(\frac{22.4}{64}\) \(\times\) \(\frac{3.2}{64}\)
= \(1.12dm^{3}\)
Source: Myschool Past Questions Archive (Record #27610)
Chemistry
UTME / JAMB 1984
Acids, Bases, pH & Salts
Solution
A molar solution of caustic soda is prepared by dissolving
A
40 g NaOH in 100 g of water
B
40 g NaOH in 1000 g of water
C
20 g NaOH in 500 of solution
D
20 g NaOH in 1000 g of solution
E
2o g NaOH in 80 g of solution
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
A molar solution implies concentration in terms of moles/liter. The respective atomic weights for NaOH are: Na - 23,0 - 16 and H - 1, so the molecular weight, is 23 + 16 + I = 40. Thus 40 grams of NaOH equals one mole of NaOH, and a 1 molar solution of NaOH will contain 40 grams of NaOH chemical in 1000grams of water.
Source: Myschool Past Questions Archive (Record #27611)
Chemistry
UTME / JAMB 1984
Stoichiometry, Mole Concept & Volumetric Analysis
Which among the elements 1. Carbon 2. Oxygen 3. Copper 4. Bromine 5. Zinc, will NOT react with either water or steam?
A
1 and 2
B
2 and 3
C
3 and 4
D
1, 2, and 3
E
2, 3, and 5
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27612)
Chemistry
UTME / JAMB 1984
Stoichiometry, Mole Concept & Volumetric Analysis
Naphthalene when heated melts at 354 K (81 oC). At this temperature the molecules of naphthalene
A
decompose into smaller molecules
B
change their shape
C
are oxidized by atmospheric oxygen
D
contract
E
become mobile as the inter molecular forces are broken
medium Difficulty
Verified Correct Answer: Option E
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option E.
Source: Myschool Past Questions Archive (Record #27613)